Displaying 12 results from an estimated 12 matches for "snunes".
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nunes
2007 Feb 23
2
Google Custom Search Engine for R
Hi,
Since "R" is a (very) generic name, I've been having some trouble
searching the web for this topic. Due to this, I've just created a
Google Custom Search Engine that includes several of the most relevant
sites that have information on R.
See it in action at:
http://google.com/coop/cse?cx=018133866098353049407%3Aozv9awtetwy
This is really a preliminary test. Feel free to
2008 Jun 17
2
Measuring dispersion
Hi,
I'm looking for a function to measure the dispersion of a set of
values ranging from 0 to 1.
This function should be 0 if all the values are evenly spaced within
the interval and it should be > 0 if values are clustered.
The more clustered the values are, the higher should the function be.
An example:
[0; 0.2; 0.4; 0.6; 0.8; 1] - function should be ~ 0
[0; 0.1; 0.1; 0.15; 1] -
2007 Mar 02
2
Error in length of vector ?
Hi,
I'm having a weird result with the length() function:
>a
[... omited ...]
[9994] NA "2003-12-03 16:37:00" "2002-06-26 18:43:00"
[9997] "2005-07-04 04:00:00" "2007-02-16 22:09:00" "2007-02-24 15:49:00"
[10000] NA
> length(LastModified)
[1] 9
> length(c(LastModified))
[1] 9
I was expecting to get
2007 Feb 15
3
Working with temporal data
Hi,
I have several files with data in this format:
20070102
20070102
20070106
20070201
...
The data is sorted and each line represents a date (YYYYMMDD). I would
like to analyze this data using R. For instance, I would like to have
a histogram by year, month or day.
I've already made a simple Perl script that aggregates this data but I
believe that R can be much more powerful and easy on
2005 Dec 13
1
Manipulating matrices
Hi,
I'm pretty new to R and I've been having some problems filtering data
in matrices.
I have the following initial dataset:
|| year | name | varA ||
I have multiple values for "varA" for the same "year" and the same "name".
Having this as the input I would like to obtain the following:
|| year | name | {varA mean} ||
Where I only have one line for each
2007 Feb 16
1
Working with temporal data [Solved]
..."days", "weeks", "months", "secs",
"mins", "hours".
One final question, how could I easily filter my dataset if, for
instance, I only wanted to see results from 2006 ?
Thanks to all who helped,
S?rgio Nunes
On 2/15/07, S?rgio Nunes <snunes at gmail.com> wrote:
> Hi,
>
> I have several files with data in this format:
>
> 20070102
> 20070102
> 20070106
> 20070201
> ...
>
> The data is sorted and each line represents a date (YYYYMMDD). I would
> like to analyze this data using R. For instance, I wo...
2007 Jun 20
2
Averaging dates?
Hi,
What's the best way to average dates?
I though mean.POISXct would work fine but...
> a
[1] "2007-04-02 19:22:00 WEST"
> b
[1] "2007-03-17 16:23:00 WET"
> class(a)
[1] "POSIXt" "POSIXct"
> class(b)
[1] "POSIXt" "POSIXct"
> mean(a,b)
[1] "2007-04-02 19:22:00 WEST"
> mean(b,a)
[1] "2007-03-17
2007 Mar 07
2
No years() function?
Hi,
I'm trying to aggregate date values using the aggregate function. For example:
aggregate(data,by=list(weekdays(LM),months(LM)),FUN=length)
I would also like to aggregate by year but there seems to be no
years() function.
Should there be one? Is there any alternative choice?
Also, a hours() function would be great. Any tip on this?
Thanks in advance!
S?rgio Nunes
2009 Jun 01
1
Bug in hist() when working with Dates ?
Hi,
It seems that hist() has a buggy behavior when breaking over "days".
The bug can be reproduced in a few steps:
> d=data.frame(date=c("2009-01-01", "2009-01-02", "2009-01-02"))
> d$date=as.Date(d$date)
> d$date
[1] "2009-01-01" "2009-01-02" "2009-01-02"
> h=hist(d$date, "days")
> h$count
[1] 3
2005 Dec 13
4
Ploting graphics using X tints from a color
Hi,
I'm trying to draw a 2D plot using multiple tints of red. The
(simplified) setup is the following: || year | x | y ||
My idea is that each year is plotted with a different tint of red.
Older year (lightest) -> Later year (darkest). I've managed to plot
this with different scales of grays simply by doing:
palette(gray(length(years):0/length(years)))
before the plot and for each
2005 Sep 28
1
Change console language ?
Hi,
I'm pretty new to R, I've just installed version 2.1.1 on Windows.
I have a simple (it seems) doubt - how do I change the Console default
Language ?
It's set to Portuguese but I would like to view it in English.
Thanks in advance,
S??rgio Nunes
2009 Nov 04
0
Correlation of ranks of labels?
Hi,
I have two ranks of labels (strings) representing user preferences of colors.
For instance, here is a simple example with 4 preferences for each user:
> rank1
[1] "red" "blue" "green" "black"
> rank2
[1] "white" "gray" "black" "blue"
How can I compute Kendall's Tau for this scenario?
Thanks in