search for: snune

Displaying 12 results from an estimated 12 matches for "snune".

Did you mean: sune
2007 Feb 23
2
Google Custom Search Engine for R
Hi, Since "R" is a (very) generic name, I've been having some trouble searching the web for this topic. Due to this, I've just created a Google Custom Search Engine that includes several of the most relevant sites that have information on R. See it in action at: http://google.com/coop/cse?cx=018133866098353049407%3Aozv9awtetwy This is really a preliminary test. Feel free to
2008 Jun 17
2
Measuring dispersion
Hi, I'm looking for a function to measure the dispersion of a set of values ranging from 0 to 1. This function should be 0 if all the values are evenly spaced within the interval and it should be > 0 if values are clustered. The more clustered the values are, the higher should the function be. An example: [0; 0.2; 0.4; 0.6; 0.8; 1] - function should be ~ 0 [0; 0.1; 0.1; 0.15; 1] -
2007 Mar 02
2
Error in length of vector ?
Hi, I'm having a weird result with the length() function: >a [... omited ...] [9994] NA "2003-12-03 16:37:00" "2002-06-26 18:43:00" [9997] "2005-07-04 04:00:00" "2007-02-16 22:09:00" "2007-02-24 15:49:00" [10000] NA > length(LastModified) [1] 9 > length(c(LastModified)) [1] 9 I was expecting to get
2007 Feb 15
3
Working with temporal data
Hi, I have several files with data in this format: 20070102 20070102 20070106 20070201 ... The data is sorted and each line represents a date (YYYYMMDD). I would like to analyze this data using R. For instance, I would like to have a histogram by year, month or day. I've already made a simple Perl script that aggregates this data but I believe that R can be much more powerful and easy on
2005 Dec 13
1
Manipulating matrices
Hi, I'm pretty new to R and I've been having some problems filtering data in matrices. I have the following initial dataset: || year | name | varA || I have multiple values for "varA" for the same "year" and the same "name". Having this as the input I would like to obtain the following: || year | name | {varA mean} || Where I only have one line for each
2007 Feb 16
1
Working with temporal data [Solved]
..."days", "weeks", "months", "secs", "mins", "hours". One final question, how could I easily filter my dataset if, for instance, I only wanted to see results from 2006 ? Thanks to all who helped, S?rgio Nunes On 2/15/07, S?rgio Nunes <snunes at gmail.com> wrote: > Hi, > > I have several files with data in this format: > > 20070102 > 20070102 > 20070106 > 20070201 > ... > > The data is sorted and each line represents a date (YYYYMMDD). I would > like to analyze this data using R. For instance, I w...
2007 Jun 20
2
Averaging dates?
Hi, What's the best way to average dates? I though mean.POISXct would work fine but... > a [1] "2007-04-02 19:22:00 WEST" > b [1] "2007-03-17 16:23:00 WET" > class(a) [1] "POSIXt" "POSIXct" > class(b) [1] "POSIXt" "POSIXct" > mean(a,b) [1] "2007-04-02 19:22:00 WEST" > mean(b,a) [1] "2007-03-17
2007 Mar 07
2
No years() function?
Hi, I'm trying to aggregate date values using the aggregate function. For example: aggregate(data,by=list(weekdays(LM),months(LM)),FUN=length) I would also like to aggregate by year but there seems to be no years() function. Should there be one? Is there any alternative choice? Also, a hours() function would be great. Any tip on this? Thanks in advance! S?rgio Nunes
2009 Jun 01
1
Bug in hist() when working with Dates ?
Hi, It seems that hist() has a buggy behavior when breaking over "days". The bug can be reproduced in a few steps: > d=data.frame(date=c("2009-01-01", "2009-01-02", "2009-01-02")) > d$date=as.Date(d$date) > d$date [1] "2009-01-01" "2009-01-02" "2009-01-02" > h=hist(d$date, "days") > h$count [1] 3
2005 Dec 13
4
Ploting graphics using X tints from a color
Hi, I'm trying to draw a 2D plot using multiple tints of red. The (simplified) setup is the following: || year | x | y || My idea is that each year is plotted with a different tint of red. Older year (lightest) -> Later year (darkest). I've managed to plot this with different scales of grays simply by doing: palette(gray(length(years):0/length(years))) before the plot and for each
2005 Sep 28
1
Change console language ?
Hi, I'm pretty new to R, I've just installed version 2.1.1 on Windows. I have a simple (it seems) doubt - how do I change the Console default Language ? It's set to Portuguese but I would like to view it in English. Thanks in advance, S??rgio Nunes
2009 Nov 04
0
Correlation of ranks of labels?
Hi, I have two ranks of labels (strings) representing user preferences of colors. For instance, here is a simple example with 4 preferences for each user: > rank1 [1] "red" "blue" "green" "black" > rank2 [1] "white" "gray" "black" "blue" How can I compute Kendall's Tau for this scenario? Thanks in