search for: skotara

Displaying 4 results from an estimated 4 matches for "skotara".

2009 Jan 12
2
assign a list using expression?
Dear R-users, I would like to assign elements to a list in the following manner: mylist <- list(a = a, b = b, c = c) To do this I tried myexpr <- expression(a = a, b = b, c = c) mylist <- list( eval(myexpr) ) It ends up by overwriting a when b is assigned and b when c is assigned. Additionally the element of the list does not have a name. Could you tell me why this is the case? Thank
2009 May 22
1
anova leads to an error
Dear R-list, the following code had been running well over the last months: exam <- matrix(rnorm(100,0,1), 10, 10) gg <- factor(c(rep("A", 5), rep("B", 5))) mlmfit <- lm(exam ~ 1); mlmfitG <- lm(exam ~ gg) result <- anova(mlmfitG, mlmfit, X=~0, M=~1) Until, all of a sudden the following error occured: Fehler in
2008 Dec 04
1
How to get Greenhouse-Geisser epsilons from anova?
Dear all, I apologize for my basic question. I try to calculate an anova for repeated measurements with 3 factors (A,B,C) having 2, 2, and 7 levels. or with an additional fourth between subjects factor D. Everything works fine using aov(val ~ A*B*C + Error(subject/ (A*B*C) ) ) or aov(val ~ (D*A*B*C) + Error(subject/(A*B*C)) + D ) val, A, B, C, D and subject are columns in a data.frame. How
2009 Jan 23
1
Anova and unbalanced designs
Dear R-list! My question is related to an Anova including within and between subject factors and unequal group sizes. Here is a minimal example of what I did: library(car) within1 <- c(1,2,3,4,5,6,4,5,3,2); within2 <- c(3,4,3,4,3,4,3,4,5,4) values <- data.frame(w1 = within1, w2 = within2) values <- as.matrix(values) between <- factor(c(rep(1,4), rep(2,6))) betweenanova <-