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Hello How can I select several not continuous rows ? If I wanted to select rows 1 to 7 I'll write mydata[,1:7] But what if I need to select rows 1 to 5 and 10 to 15? -- View this message in context: http://r.789695.n4.nabble.com/How-to-select-not-continous-rows-tp3003840p3003840.html Sent from the R help mailing list archive at Nabble.com.

I seem to have a (recent) problem with mongrel on NetBSD. I''m running a development release of NetBSD (called NetBSD-current 4.99.34). When I start mongrel, it listens on the IPv6 wildcard address, but not on the IPv4 wildcard: => Booting Mongrel (use ''script/server webrick'' to force WEBrick) => Rails application starting on http://0.0.0.0:3000 => Call with

Hello What's the differente betwen using "plot" and using "print" in order to plot a graph? For example in order to plot the result of a histogram. cheers -- View this message in context: http://r.789695.n4.nabble.com/plot-vs-print-tp3045256p3045256.html Sent from the R help mailing list archive at Nabble.com.

Hello Where could I find examples on how to work with the time index in a timeseries or zoo series? Let say I've got this series DATA 1990-01-01 10:00:00 0.900 1990-01-01 10:01:00 0.910 1990-01-01 10:03:00 0.905 1990-01-01 10:04:00 0.905 1990-01-01 10:05:00 0.890 ....................... 2000-12-31 20:00:00 0.992 How do I make simple calculations such as ... ? Calculate the

Hello Imagine I have a vector with ones and zeroes I write it compactly: 1111111100001111111111110000000001111111111100101 I need to get a new vector replacing the "N" ones following the zeroes to new zeroes. For example for N = 3 1111111100001111111111110000000001111111111100101 becomes 1111111100000001111111110000000000001111111100000 I can do it with a for loop but I've read

Hi Usually "aggregate" is used to calculate things such as the sum of all data on the first day, the sum next day, and so on. But how can I calculate the mean of the first hour of all days, the mean of the second hour of all days, and so on. ??? That's Most examples: today at 1am + today at 2am + today at 3am +.... -> sum today tomorrow at 1am + tomorrow at

Hello How do you compare R to SAS in terms of speed and management of large datasets? What about Revolution R? I've seen on their site, they claim that Revolution R is much faster than R and it's multithread... Can you really notice the difference?. What dissadvantage does it have? I think it's based on R 2.10. but R already issued the version 2.12 Regards What alternative

Hello. I don't uderstant when to use textConnection and when not. Some examples do it, some not. I've even seen something like con <- textConnection(rev(rev(ReadLines('data.txt'))[-(1:2])) data <- read.table(con) close(con) -- View this message in context: http://r.789695.n4.nabble.com/when-to-use-textConnection-tp2327132p2327132.html Sent from the R help mailing list

Hello I've used read.table to read a file that contains numbers such as 0.00001 when I write them back with write.table those numbers appear as 1e-5 How can I keep the old format? thanks -- View this message in context: http://r.789695.n4.nabble.com/number-format-writing-1e-5-instead-of-0-00001-tp3003831p3003831.html Sent from the R help mailing list archive at Nabble.com.

Hello Could anyone explain me the difference between strftime vs strptime, please ? I've read the help but it's a little bit cionfusing for me. cheers -- View this message in context: http://r.789695.n4.nabble.com/strftime-vs-strptime-tp3018865p3018865.html Sent from the R help mailing list archive at Nabble.com.

down vote favorite Hello I have a zoo series. It lasts 10 years and its frequency is 15min. I'd like to get a new zoo series (or vector) with the same number of elements, whith each element equal to the first element of the day. That's, The first element everyday is repeated throughout the wole day. This is not same as aggregate(originalseries,as.Date,head,1) because this gives a

Hello Why this works: ncota <- 1 nslope <- 29 resul <- matrix(rep(0,ncota*nslope*4),ncota*nslope,4) But this doesn't? ncota <- 1 sini <- 0.1; sfin <- 1.5; spaso <- 0.05; nslope <- 1+((sfin-sini)/spaso) resul <- matrix(rep(0,ncota*nslope*4),ncota*nslope,4) I guess the problem is that the division gives a noninteger number. How can I get the second one work? I

hello I think I've found a bug I don't know if it's a chron bug or a R one. (05/12/05 23:00:00) +1/24 gives (05/12/05 24:00:00) instead of (05/13/05 00:00:00) it looks like the same but it's not because when you get the date of this datetime it says day 12 instead of 13. Please, forward it to the place where this bugs are supposed to be posted. cheers -- View this message

Howdy. I have these models: User, field "mundane_name" user has_one :instructor_profile (may or may not exist) instructor_profile, field "sca_name" belongs_to :user I would like to craft a search on these fields, which is effectively this, but in one go: matching_users = User.where("mundane_name ILIKE ?", "%#{target}%") matching_profiles =

When I create a new app with the rails command, it creates a log directory. You must chmod that to 666 according to the error message I get whenever anything (like script/generate) tries to log a message. Fine ... ... But, what the hell is this about??? $ ls -la log/ ls: cannot access log/.: Permission denied ls: cannot access log/..: Permission denied ls: cannot access log/development.log:

Attempting remote update of mongrel Select which gem to install for your platform (i386-mswin32) 1. mongrel 1.1 (java) 2. mongrel 1.1 (mswin32) 3. mongrel 1.1 (ruby) 4. mongrel 1.0.4 (ruby) 5. mongrel 1.0.4 (mswin32) 6. Skip this gem 7. Cancel installation 2 > ERROR: While executing gem ... (OpenURI::HTTPError) 404 Not Found This is using the NetBean IDE''s ''ruby

Hello How can I substitute all NA values by zero in a R zoo series? I've been reading about na.locf and na.omit but I think none of them do what I need. thanks. -- View this message in context: http://r.789695.n4.nabble.com/Substitute-NAs-by-zero-tp2546715p2546715.html Sent from the R help mailing list archive at Nabble.com.

Hello I have two series (that can have with different frequencies or with missing values). I merge them and use na.locf, getting a zoo objet with a common index and two core columns. How can I add this columns getting a new zoo series? Any other way of adding two asynchronou series? regards -- View this message in context:

Hello I have a file with this format 2005-01-03 09:05 0.00 2005-01-03 09:10 0.01 2005-01-03 09:15 0.02 2005-01-03 09:20 0.03 2005-01-03 09:25 0.04 2005-01-03 09:30 0.05 2005-01-03 09:35 0.06 2005-01-03 09:40 0.07 2005-01-03 09:45 0.08 2005-01-03 09:50 0.09 2005-01-03 09:55 0.10 2005-01-03 10:00 0.00 2005-01-03 10:05 0.00 .... some

Hi, when I do cap deploy:cold I get this error: rake aborted! undefined local variable or method `acts_as_commentable'' for #<Class: 0x7fa1c34a2f10> /usr/local/lib/ruby/gems/1.8/gems/activerecord-2.2.2/lib/active_record/ base.rb:1833:in `method_missing_without_paginate'' /usr/local/lib/ruby/gems/1.8/gems/mislav-will_paginate-2.3.8/lib/ will_paginate/finder.rb:170:in