search for: sjkiss

...r[[11]][,1]),] test<-cbind(economy, economy_2) plot(as.numeric(test), type='l') #here's another attempt I'm trying.... economy<-data.frame for (i in 15:19) { economy[i,] <-r[[i]][grep('Economy', r[[i]][,1]), ] } Begin forwarded message: > From: Simon Kiss <sjkiss at gmail.com> > Date: October 7, 2010 4:59:46 PM EDT > To: Simon Kiss <simonjkiss at yahoo.ca> > Subject: Fwd: [R] Converting scraped data > > > > Begin forwarded message: > >> From: Ethan Brown <ethancbrown at gmail.com> >> Date: October 6, 20...

Hello: Forgive me, this is surely a simple question but I can't figure it out, having consulted the help archives and "Data Manipulation With R" (Spector). I have a list of 11 data frames with one common variable in each (prov). I'd like to use lapply to go through and recode one particular level of that common variable. I can get the recode to work, but it only returns the

Hi: I'm sure this is a very easy problem. I've consulted Data Manipulation With R and the R Book and can't find an answer. Sample list of data frames looks as follows: .xx<-list(df<-data.frame(Var1=rep('Alabama', 400), Var2=rep(c(2004, 2005, 2006, 2007), 400)), df2<-data.frame(Var1=rep('Tennessee', 400), Var2=rep(c(2004,2005,2006,2007), 400)),

Dear colleagues, this seems like an easy problem, and I found some suggestions which I've incorporated in the help list, but I can't quite get it right. I want to add a series of years to a second x-axis category label. I generate them with test and test_2 below, format them with some spacing (which is the suggestion I took from the R-list) and concatenate them and then write them with

Dear Colleagues, I have recently installed R Commander on my Mac OS 10.6.8. I'd like to use it for an undergraduate class this year. Everything appears to be working fine, except for one thing. I cannot use Command-tab to cycle from the X11 window in which RCommander is running to any other window open in my workspace. This is particularly important because I cannot cycle to the graphics

Hi there I'm trying to fit a logistic regression model to data that looks very similar to the data in the sample below. I don't understand why I'm getting this error; none of the data are proportional and the weights are numeric values. Should I be concerned about the warning about non-integer successes in my binomial glm? If I should be, how do I go about addressing it? I'm

Hi all: I struggle a lot scraping web data. I still haven't got a handle on the XML package. I'd like to get particular exchange rates from this table: https://raw.github.com/currencybot/open-exchange-rates/master/latest.json This is the code that I'm working with: library(RCurl) library(XML)

Hello: I s there a way to use xtable with objects from the psych package, particularly principal()? Is there a difference between princomp and principal? xtable seems to play better with princomp. Thank you. Yours, Simon Kiss ********************************* Simon J. Kiss, PhD Assistant Professor, Wilfrid Laurier University 73 George Street Brantford, Ontario, Canada N3T 2C9

Dear colleagues, I have a series of newspaper articles in a text file, downloaded from a text file. They look as follows: Document 1 of 100 \n \n \n Newspaper Name \n \n Day Date I have a series of grep scripts that can extract the date and convert it to a date object, but I can't figure out how to grep the newspaper name. There is no field ID attached to those lines. The best I can come

Dear colleagues, working with the data frame below, trying to reverse two variables I the error message below. i searched through the help list but could not find any postings which could help me solve the situation. I tried attaching and detaching the data frame to no avail. Yours, Simon Kiss *DATA FRAME 'data.frame': 1569 obs. of 9 variables: $ equal : num 3 4 3 2 3 4 2 3 2 2 ...

Dear colleagues, Is there a way to order list items by date? I have a series of surveys in a list where the name of each list item is the date the survey was taken but the list items are out of order. Each data frame has a variable in it with the survey date as well, if that helps. Yours, Simon Kiss #Sample Data mylist<-list('1991-01-01'=data.frame(a=rep(5,5),

Dear colleagues, I have a data set that looks roughly like this; mydat<-data.frame(state=c(rep("Alabama", 5), rep("Delaware", 5), rep("California", 5)), news=runif(15, min=0, max=8), cum.news=rep(0, 15)) For each state, I'd like to cumulatively sum the value of "news" and make that put that value in cum.news. I'm trying as follows but I get

Hello all: I'm trying to use the following code to get commands, comments and results to a .txt file. It only appears to capture comments. When I comment those out with #, it creates a NULL file. Someone seemed to have a similar problem with a mac GUI (https://stat.ethz.ch/pipermail/r-help/2010-September/253177.html) but the result seemed to be ambiguous. Is there a work-around?

Dear colleagues, I'm working with the 2008 Canada Election Studies (http://www.queensu.ca/cora/_files/_CES/CES2008.sav.zip), trying to construct a weighted national sample using the survey package. Three weights are included in the national survey (a household weight, a provincial weight and a national weight which is a product of the first two). In the following code I removed variables with

Dear colleagues, particularly academic ones, So I'm creating a Microsoft Word template for myself so that every time I teach a new course, I don't have to enter in the dates manually for each class session. I'd like to use an R script that can generate an irregular series of dates starting from one date (semester begin) to another (semester end) using an irregular interval in

Dear list colleagues, I'm trying to come up with a test question for undergraduates to illustrate comparison of means from a complex survey design. The data for the example looks roughly like this: mytest<-data.frame(harper=rnorm(500, mean=60, sd=1), party=sample(c("BQ", "NDP", "Conservative", "Liberal", "None", NA), size=500,

Dear colleagues, I want to calculate the value of x2 based on the value of x1. x1 is a factor with three separate levels. I want to make sure that missing values remain as NA in X2, but non-missing values take on a value of either 0 or 1 dependending on the value in x1. This is the code I'm working with...Can any one help? I've seen some other requests on a topic like this, but not

Hi there: I'm preparing a report in RStudio 0.96.330 on a Mac OS. I'm running R 2.15.0 I understand from Ross Ihaka's document (http://www.stat.auckland.ac.nz/~stat782/downloads/Sweave-customisation.pdf) that you can modify the line length of Sweave output by a call to options(wdith=x). This works great for me for numeric output, but not for character vectors that I have to print.

. HI there, I'd like to show demonstrate how the chi-squared distribution works, so I've come up with a sample data frame of two categorical variables y<-data.frame(gender=sample(c('Male', 'Female'), size=100000, replace=TRUE, c(0.5, 0.5)), tea=sample(c('Yes', 'No'), size=100000, replace=TRUE, c(0.5, 0.5))) And I'd like to create a list of 100

Hi: How do I select different variables from a list of data frames. I have a list of 13 that looks like below. Each data frame has more variables than I need. How do I go through the list and select the variables that I need. In the example below, I need to get the variables "a", and "q10" and "q14" to be returned to two separate data frames. Thank you. Yours, Simon