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..., that leaves 1,460 bytes for payload. 7,000 / 1,460 = 4.8 packest/sec. 4.8 pkts/sec * 40 bytes of header = 192 bytes/sec. 7,192 bytes / sec = 57,536 bits /sec. All-in-all, the IP overhead accounts for an additional 3% with a 56kbps stream. Take the overhead and multiply it by the number of simultanenous clients. In my experience, though the actual data rate is higher. I haven't done any further testing in awhile and I assume that the theoretical maximum of stuff put in each packet isn't the full 1460 bytes. -I

Hi all, my question: how is the exact formula to calculate bandwidth needed to upstream at given bitrate to a certain number of simultaneous listeners ? is it simply BANDWIDTH (bps) = BITRATE (bps) X LISTENERS ? tnx in advance, carlo. -------------- next part -------------- An HTML attachment was scrubbed... URL: