search for: sieira

...n(retval) } listPOSIXct <- function(x) { ? retval = list() ? for (i in 1:length(x)) retval[[i]] = x[i] ? return(retval) } Is there a better way to do this (other than using *apply instead of for above) that better leverages vectorization? Am I missing something here? Thanks! --? Alexandre Sieira CISA, CISSP, ISO 27001 Lead Auditor "The truth is rarely pure and never simple." Oscar Wilde, The Importance of Being Earnest, 1895, Act I

...class(range[i])) [1] "Date" [1] "Date" > > for (i in seq(from=d1, to=d2, by="day")) print(class(i)) [1] "numeric" [1] "numeric" This is output from R version 2.15.2 (2012-10-26) on Mac OS X 10.8.2. Is this expected behavior? -- Alexandre Sieira CISA, CISSP, ISO 27001 Lead Auditor "The truth is rarely pure and never simple." Oscar Wilde, The Importance of Being Earnest, 1895, Act I Sent with Sparrow (http://www.sparrowmailapp.com/?sig)

This thread seems to be very old, most of the bat files should be runnable using Code: wine cmd < path/to/your/file.bat .