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shortanswer
2010 Sep 04
4
Please explain "do.call" in this context, or critique to "stack this list faster"
...1)*nr) + 1):(j*nr), ] <- mylist[[j]]
## I searched a long time for an answer that looked better.
## This website is helpful:
## http://stackoverflow.com/questions/tagged/r
## I started to type in the question and 3 plausible answers
## popped up before I could finish.
## The terse answer is:
shortAnswer <- do.call("rbind",mylist)
## That's the right answer, see:
shortAnswer == dataComplete
## But I don't understand why it works.
## More importantly, I don't know if it is fastest, or best.
## It is certainly less error prone than "dataComplete"
## First, mak...