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...q= 202.41 on 1 degrees of freedom, p= 0 n= 5496 I am not quite sure how to use the output. I see that it gives the Scale parameter. How do I find the Shape paramater as a function of the covariate? Thank you, Steven --------------------------------------- ------------------------- Steven Shechter PhD Candidate in Industrial Engineering University of Pittsburgh www.pitt.edu/~sms13

Hi, If I set df=2 in my smooth.spline function, is that equivalent to running a linear regression through my data? It appears that df=# of data points gives the interpolating spline and that df = 2 gives the linear regression, but I just want to confirm this. Thank you, Steven