Displaying 20 results from an estimated 24 matches for "serum".
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serup
2011 Jan 26
2
2 functions with same name - what to do to get the one I want
...ciated.
Tried to instal Hmisc but got this message, so I assume I have it
> utils:::menuInstallPkgs()
Warning: package 'Hmisc' is in use and will not be installed
ran the demo from Hmisc with no luck...
> set.seed(1)
> ch <- rnorm(1000, 200, 40)
> ecdf(ch, xlab="Serum Cholesterol")
Error in ecdf(ch, xlab = "Serum Cholesterol") :
unused argument(s) (xlab = "Serum Cholesterol")
ran the sample code from stats and it worked...
> x <- rnorm(12)
> Fn <- ecdf(x)
> Fn # a *function*
Empirical CDF
Call: ecdf(x)
x[1:12...
2002 Dec 06
2
Mutiple page trellis plots with relation = "free" or "sliced"
Hello,
Has anyone out there encountered a problem like this:
xyplot(Plasma ~ Serum | Analyte,
data = sp.df,
aspect = 1,
layout = c(1, 1, 200),
scales = list(relation = "free")
)
Gives the error:
Error in pretty(x[is.finite(x)], ...) : x must be numeric
On the other hand, this works (but I don't want the default of having
everyt...
2006 Dec 03
4
prop.trend.test issue
...have the clinical study data.
Year 0 Year 3
Retinol (nmol/L) N Mean +-sd Mean +-sd
Vitamin A group 73 1.89+-0.36 2.06+-0.53
Trace group 57 1.83+-0.31 1.78+-0.30
where N is the number of male for the clinical study.
I want to test if the mean serum retinol has increased over 3 years
among subjects in the vitamin A group.
> 1.89+0.36
[1] 2.25
> 1.89-0.36
[1] 1.53
> 2.06+0.53
[1] 2.59
> 2.06-0.53
[1] 1.53
> prop.trend.test(c(2.25, 1.53),c( 2.59, 1.53))
Chi-squared Test for Trend in Proportions
data: c(2.25, 1.53) o...
2007 Feb 01
3
Lining up x-y datasets based on values of x
Hi,
I was wondering if there is a direct approach for lining up 2-column
matrices according to the values of the first column. An example and a
brute-force approach is given below:
x <- cbind(1:10, runif(10))
y <- cbind(5:14, runif(10))
z <- cbind((-4):5, runif(10))
xx <- seq( min(c(x[,1],y[,1],z[,1])), max(c(x[,1],y[,1],z[,1])), 1)
w <- cbind(xx, matrix(rep(0, 3*length(xx)),
2023 Nov 03
1
I need to create new variables based on two numeric variables and one dichotomize conditional category variables.
Hello Everyone,
I have three variables: Waist circumference (WC), serum triglyceride (TG)
level and gender. Waist circumference and serum triglyceride is numeric and
gender (male and female) is categorical. From these three variables, I want
to calculate the "Lipid Accumulation Product (LAP) Index". The equation to
calculate LAP is different for male and fema...
2023 Nov 03
1
I need to create new variables based on two numeric variables and one dichotomize conditional category variables.
...hether your variables are in a data frame or
list or whatever, which you failed to specify. If so, ?with may be useful.
Cheers,
Bert
On Fri, Nov 3, 2023 at 3:43?AM Md. Kamruzzaman <mkzaman.m at gmail.com> wrote:
> Hello Everyone,
> I have three variables: Waist circumference (WC), serum triglyceride (TG)
> level and gender. Waist circumference and serum triglyceride is numeric and
> gender (male and female) is categorical. From these three variables, I want
> to calculate the "Lipid Accumulation Product (LAP) Index". The equation to
> calculate LAP is differe...
2023 Nov 03
1
I need to create new variables based on two numeric variables and one dichotomize conditional category variables.
...two numeric
variables and one dichotomize conditional category variables.
Message-ID:
<CAGbxoeGjsxZKQ6qijEMq-X-5doqnQQS1jjPDDrGT6hH5xWqOKQ at mail.gmail.com>
Content-Type: text/plain; charset="utf-8"
Hello Everyone,
I have three variables: Waist circumference (WC), serum triglyceride (TG)
level and gender. Waist circumference and serum triglyceride is numeric and
gender (male and female) is categorical. From these three variables, I want
to calculate the "Lipid Accumulation Product (LAP) Index". The equation to
calculate LAP is different for male and fema...
2007 Dec 13
2
Function for AUC?
Hello
Is there an easy way, i.e. a function in a package, to calculate the
area under the curve (AUC) for drug serum levels?
Thanks for any advice
--
Armin Goralczyk, M.D.
--
Universit?tsmedizin G?ttingen
Abteilung Allgemein- und Viszeralchirurgie
Rudolf-Koch-Str. 40
39099 G?ttingen
--
Dept. of General Surgery
University of G?ttingen
G?ttingen, Germany
--
http://www.chirurgie-goettingen.de
2023 Nov 03
2
I need to create new variables based on two numeric variables and one dichotomize conditional category variables.
...two numeric
variables and one dichotomize conditional category variables.
Message-ID:
<CAGbxoeGjsxZKQ6qijEMq-X-5doqnQQS1jjPDDrGT6hH5xWqOKQ at mail.gmail.com>
Content-Type: text/plain; charset="utf-8"
Hello Everyone,
I have three variables: Waist circumference (WC), serum triglyceride (TG)
level and gender. Waist circumference and serum triglyceride is numeric and
gender (male and female) is categorical. From these three variables, I want
to calculate the "Lipid Accumulation Product (LAP) Index". The equation to
calculate LAP is different for male and fema...
2018 May 22
2
Nelson-Aalen Estimator in R: Error Message
Dear all,
Currently, I am doing a research project about serum sodium levels and falling. I am doing my analysis in R. I am performing the multiple imputation right now. I want to perform a survival analysis later, but therefore I need to specify the Nelson-Aalen estimator. My dataset is called DF1, the event indicator is Falls and the time variable is Time. T...
2023 Nov 03
1
[EXTERNAL] RE: I need to create new variables based on two numeric variables and one dichotomize conditional category variables.
...two numeric
variables and one dichotomize conditional category variables.
Message-ID:
<CAGbxoeGjsxZKQ6qijEMq-X-5doqnQQS1jjPDDrGT6hH5xWqOKQ at mail.gmail.com>
Content-Type: text/plain; charset="utf-8"
Hello Everyone,
I have three variables: Waist circumference (WC), serum triglyceride (TG)
level and gender. Waist circumference and serum triglyceride is numeric and
gender (male and female) is categorical. From these three variables, I want
to calculate the "Lipid Accumulation Product (LAP) Index". The equation to
calculate LAP is different for male and fema...
2004 Aug 05
1
ANOVA with repeated measurements (Dan Rajdl)
Dear R-users,
I have some human serum lipid concentrations (cholesterol, apoB ...),
each lipid was measured (in the same person) for 6 times in different
time points (start, 3 months, 6 months, 12 months, 18 months, 24
months). There were 2 groups of participants: one with a nutritional
intervention and the other without it. I would li...
2005 Feb 16
0
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Facial pores will appear finer and smoother. Your complexion will look cleare with
visible improvements in skin texture.
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C. Acne Clarifying Serum
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D. Super Actives Whitening Tonic...
2006 Apr 10
2
TukeyHSDs function (pgirmess package)
...e data set below can be used.
>numbers<-c(845,829,682, 689,581,495)
Is there something wrong with this function? Or is there a better way
to extract significant comparisons
from a tukey test?
Cheers,
Rune
-------------------------------------------
Rune Vejen Petersen, M.Sc.Eng.
Statens Serum Institute
Dept. of Infectious Disease Immunology
Artillerivej 5, 81/344
DK-2300 Copenhagen
[[alternative HTML version deleted]]
2005 Oct 16
1
measurement error model - "simple" linear regression
...found the thread on this subject this summer but
wonder whether it has been taken any further. I have an important
medical problem where X is computed from a three independent and
complicated measurements (exchangeable sodium and potassium and total
body water - i.e. X = (Nae+Ke)/TBW ) and Y is serum sodium
concentration (all data in Edelman, JCI 1958). I have the individual
data in the paper (but have not yet had time to enter it) and Edelman
et al in fact reported measurement errors for most individual items.
Edelman and coworkers made a linear regression of Y on X and now I
would like t...
2008 Dec 09
1
creating standard curves for ELISA analysis
...ulate the
concentrations of unknown, but it is too tedious and manual especially when
I have 100's of files to process. I would appreciate some help in creating
a R script to do this with minimal manual input. s A1-G1 and A2-G2 are
standards serially diluted H1 and H2 are Blanks. A3 to H12 are serum
samples. I am pasting the structure of my data below:
A1 14821
B1 11577
C1 5781
D1 2580
E1 902
F1 264
G1 98
H1 4
A2 14569.5
B2 11060
C2 5612
D2 2535
E2 872
F2 285
G2 85
H2 3
A3 1016
B3 2951.5
C3 547
D3 1145
E3 4393
F3 4694
G3 1126
H3 1278
A4 974.5
B4 3112.5
C4 696.5
D4...
2018 May 22
0
Nelson-Aalen Estimator in R: Error Message
...nd see what the value of variables was at the point of the error. This could give you a clue about what is going on.
-pd
> On 22 May 2018, at 15:29 , A.C. van der Burgh <a.c.vanderburgh at erasmusmc.nl> wrote:
>
> Dear all,
>
> Currently, I am doing a research project about serum sodium levels and falling. I am doing my analysis in R. I am performing the multiple imputation right now. I want to perform a survival analysis later, but therefore I need to specify the Nelson-Aalen estimator. My dataset is called DF1, the event indicator is Falls and the time variable is Time. T...
2009 Mar 07
2
ttest in R
Dear list,
i am a biologist who needs to do some ttest between disease and non disease,
sex, genotype and the serum levels of proteins on a large number of
individuals. i have been using excel for a long time but it is very tedious
and time consuming. i am posting the data below and ask your help in
generating a code to get this analysis done in R. thanks
gender disease genotype data
M N CC 3.206447188
F N CC 8...
2006 May 09
2
post hoc comparison in repeated measure
Hi, I have a simple dataset with repeated measures.
one factor is treatment with 3 levels (treatment1,
treatment2 and control), the other factor is time (15
time points). Each treatment group has 10 subjects
with each followed up at each time points, the
response variable is numeric, serum protein amount. So
the between subject factor is treatment, and the
within subject factor is time. I ran a 2-way ANOVA
with repeated measures considering time as the within
subject factor:
aov(response~treat*time+Error(subject/time),dat)
The results told me that the treatment is marginally
signifi...
2010 Sep 09
5
Calculating with tolerances (error propagation)
Hello Bernardo,
---------
If I understood your problem this script solve your problem:
q<-0.15 + c(-.1,0,.1)
h<-10 + c(-.1,0,.1)
5*q*h
[1] 2.475 7.500 12.625
---------
OK, this solves the simple example.
But what if the example is not that simple. E.g.
P = 5 * q/h
Here, to get the maximum tolerances for P, we need to divide the maximum
value for q by the minimum value for h, and