Displaying 1 result from an estimated 1 matches for "seq_date".
Did you mean:
seq_data
2017 Oct 18
0
A wrapper of seq.Date() encounters an issue
Hello,
I?ve tried to have a wrapper function of seq.Date(), saying seq_date(). The
seq_date() function takes exactly the same arguments and the defaults as
seq.Date(). The seq_date() is expected to return the same results as
seq.Date(), but it triggers an error in seq.Date(). The little reproducible
example shows below:
seq_date <- function(from, to, by, length.out = N...