Displaying 8 results from an estimated 8 matches for "section4".
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2006 Aug 29
0
how to contrast with factorial experiment
Hello, R experts,
If I understand Ted's anwser correctly, then I can not contrast the
mean yields between sections 1-8 and 9-11 under "Trt" but I can
contrast mean yields for sections 1-3 and 6-11 because there exists
significant interaction between two factors (Trt:section4,
Trt:section5). Could I use the commands below to test
the difference between sections 1-3 and 6-11 ?
> contrasts(section)<-c(-2,-2,-2,0,0,1,1,1,1,1,1)
> newobj<-lm(log2(yield)~treat*section)
How can I infer that there is significant difference between sections
1-3 and sections 6-11 f...
2012 Jun 25
2
Fractional Factorial - Wrong values using lm-function
...ing the use of aov and
lm-functions. I'm doing a fractional factorial experiment at our production
site, and I need to familiarize myself with the analysis before I conduct
the experiment. I've been working my way through the examples provided at
http://www.itl.nist.gov/div898/handbook/pri/section4/pri472.htm
http://www.itl.nist.gov/div898/handbook/pri/section4/pri472.htm , but I
can't get the results provided in the trial model calculations. Why is this.
Here is how I have tried to do it:
> data.catapult=read.table("Fractional.txt",header=T) #Read the data in the
> table...
2006 Aug 24
1
how to constrast with factorial experiment
...t) 6.288403 0.050034 125.682 < 2e-16 ***
treatTrt 1.221219 0.070759 17.259 < 2e-16 ***
section1 -0.008502 0.010213 -0.832 0.409675
section2 -0.491175 0.165945 -2.960 0.004942 **
section3 2.569427 0.165945 15.484 < 2e-16 ***
section4 3.556067 0.165945 21.429 < 2e-16 ***
section5 -1.157069 0.165945 -6.973 1.25e-08 ***
section6 -0.003562 0.165945 -0.021 0.982971
section7 -0.487770 0.165945 -2.939 0.005223 **
section8 0.106181 0.165945 0.640 0.525585
section9...
2010 Oct 14
7
undefined method?
I''m trying to learn rails as I go along, and having a bit of trouble.
There is an undefined method cropping that I don''t know why rails
thinks should be there.
Firstly, I''m using rails 3, ruby 1.9.2
I have a controller with an index action This part works fine, but i
am trying to add a comment form to the page that is rendered by that
index action.
Supposing my
2012 Feb 02
9
Modelo senoidal de datos temporales de radiación y prueba de Thom
...verificar su homogeneidad [0].
De momento me encuentro con los siguientes problemas:
1- ¿Existe la prueba de Thom en R? ¿O debo crearme mi propia función?
2- Para la realización del modelo senoidal estoy siguiendo los pasos que
marcan en este texto:
http://www.itl.nist.gov/div898/handbook/eda/section4/eda4253.htm
pero me encuentro con los siguientes problemas:
1a - La serie que estoy utilizando tiene valores perdidos (ND) y hay
varias funciones, como spectrum o lag.plot, que no se pueden utilizar.
Yo los he reconvertido a 0, lo que no se si sera la correcto o me puede
desvirtuar el modelo....
2009 Nov 07
0
Scheffé's method?
Evidently my RSeek capabilities have once again failed me...By any chance is Scheffe's method (http://www.itl.nist.gov/div898/handbook/prc/section4/prc472.htm) implemented independently in any R base packages? If not, is it implemented independently in any of the add-on packages?
Thanks again for any insights.
2003 Nov 15
0
FW: computing a p-value ...
...proceed.
cheers,
Rolf Turner
rolf@math.unb.ca
-----Original Message-----
From: Jason Turner [mailto:jasont@indigoindustrial.co.nz]
This should get you started. These methods can be found in most
introductory statistics textbooks.
http://www.itl.nist.gov/div898/handbook/prc/section4/prc47.htm
Cheers
Jason
--
Indigo Industrial Controls Ltd.
http://www.indigoindustrial.co.nz
64-21-343-545
jasont@indigoindustrial.co.nz
This e-mail message (and any attachments) may contain confidential and/or
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review or dis...
2009 May 20
1
stationarity tests
How can I make sure the residual signal, after subtracting the trend extracted through some technique, is actually trend-free ?
I would greatly appreciate any suggestion about some Stationarity tests.
I'd like to make sure I have got the difference between ACF and PACF right.
In the following I am citing some definitions. I would appreciate your thoughts.
ACF(k) estimates the correlation