search for: sally

...;Bonham Upper", "Bonham Upper", "Bonham Upper", "D13", "D13", "D13", "D13", "D13", "D13", "D13", "D13", "D13", "D13", "D13", "D13", "D13", "Sally Lower", "Sally Lower", "Sally Lower", "Sally Lower", "Sally Lower", "Sally Lower", "Sally Lower", "Sally Lower", "Sally Lower", "Sally Lower", "Sally Lower", "Sally Lower", "Sally...

Dear Help, Suppose I have a character vector. x <- c("Bob", "loves", "Sally") I want to combine it into a single string: "Bob loves Sally" . paste(x) yields: paste(x) [1] "Bob" "loves" "Sally" The following function combines the character vector into a string in the way that I want, but it seems somewhat inelegant. paste.v...

If I have a dataframe which is organized like this: name color likes? 1 sally red 0 2 sally blue 1 3 sally green 1 4 jake red 0 5 jake blue 1 6 jake green 1 7 tom red 1 8 tom blue 0 9 tom green 0 And I want to create a matrix in the form: red blue green sally 0 1 1 jake 0 1 1 tom 1 0 0 Are...

Hi all, I have downloaded the latest version of wine in order to run iTunes but when I tried to execute the program here is what I get : cd /home/sally/Documents $ wine iTunes64Setup.exe Trying to load PE image for unsupported architecture (AMD-64) err:process:create_process starting 64-bit process L"Z:\\home\\sally\\Documents\\iTunes64Setup.exe" not supported on this platform wine: Mauvais format EXE pour Z:\home\sally\Documents\iTunes6...

Hi sri, As your problem involves a few logical steps, I found it easier to approach it in a stepwise way. Perhaps there are more elegant ways to accomplish this. svdat<-read.table(text="Count id name type 117 335 sally A 19 335 sally A 167 335 sally B 18 340 susan A 56 340 susan A 22 340 susan B 53 340 susan B 135 351 lee A 114 351 lee A 84 351 lee A 80 351 lee A 19 351 lee A 8 351 lee A 21 351 lee A 88 351 lee B 111 351 lee B 46 351 lee B 108 351 lee B",header=TRUE) # you can also do this with other reshape...

Dear All, I am trying to reshape the data with some conditions. A small part of the data looks like below. Like this there will be more data with repeating ID. Count id name type 117 335 sally A 19 335 sally A 167 335 sally B 18 340 susan A 56 340 susan A 22 340 susan B 53 340 susan B 135 351 lee A 114 351 lee A 84 351 lee A 80 351 lee A 19 351 lee A 8 351 lee A 21 351 lee A 88 351 lee B 111 351 lee B 46 351 lee B 108 351 lee B >From the above data I am expecting an output like below...

...mon <drjimlemon at gmail.com> wrote: > Hi sri, > As your problem involves a few logical steps, I found it easier to > approach it in a stepwise way. Perhaps there are more elegant ways to > accomplish this. > > svdat<-read.table(text="Count id name type > 117 335 sally A > 19 335 sally A > 167 335 sally B > 18 340 susan A > 56 340 susan A > 22 340 susan B > 53 340 susan B > 135 351 lee A > 114 351 lee A > 84 351 lee A > 80 351 lee A > 19 351 lee A > 8 351 lee A > 21 351 lee A > 88 351 lee B > 111 351 lee B > 46 351...

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...wanted a logical value for x and y. Looking more closely at your initial message, I see that you wanted _all_ values of A with respect to maxB in x and y. The error with maximum values was due to a typo. Perhaps this will do what you want: svdat<-read.table(text="Count id name type 117 335 sally A 19 335 sally A 167 335 sally B 18 340 susan A 56 340 susan A 22 340 susan B 53 340 susan B 135 351 lee A 114 351 lee A 84 351 lee A 80 351 lee A 19 351 lee A 8 351 lee A 21 351 lee A 88 351 lee B 111 351 lee B 46 351 lee B 108 351 lee B",header=TRUE) # you can also do this with other reshape...

A ridiculous number of answers to a fairly trivial query on R-news lately - 13 messages on the archive so far telling how to do paste(c("Bob","loves","Sally"),collapse=" "). I think a lot of this is due to the increased latency because of network and mailer problems that Martin mentioned earlier, but there's an inherent latency in mailing lists that means any trivial query is in danger of being swamped by a dozen identical resp...

Hi, I would like to generate a facebook call on behalf of a user to create a request to another user to install the app. Is there a way to do this without being in a fb_request_form? the use case is: Fred is creating a task, he assign it to a friend Sally , if Sally has already installed & setup my app, no problem, if she hasnt, I want to send an add request from Fred along with details of the task. I have a create task form with tons of stuff in it including a friend selector, so I have the friends id. thanks Joel

Hello! I am still a beginner. Can you tell me how to delete a row (from a matrix or data.frame) if the row name starts with U? See example below: U179971039 0.058663 0.087575 empty1 -0.1296 -0.09105 empty2 0.136259 0.398073 empty3 0.446041 -0.33997 Sally [[alternative HTML version deleted]]

...t)) summary(QM_1) The call in version 2 has changed: Call: glm(formula = HB_NHB ~ elev + costdis1, family = binomial(link = logit), data = glm_2) But I’m getting the exact same results as I did in the model where costdis1 is squared. Any ideas what I might do to correct this? Thank you. Sally [[alternative HTML version deleted]]

...R is just reading the one cell as my data. How can I get R to read the all the data rows and columns? Is there a way to clear the one-cell selection status? Or perhaps there is another issue that needs addressing. I would like to get this data table configured into R as a dataframe. Thank you, Sally [[alternative HTML version deleted]]

Dear R helpers, I need to estimate a probit model with box constraints placed on several of the model parameters. I have the following two questions: 1) How are the standard errors calclulated in glm (family=binomial(link="probit")? I ran a typical probit model using the glm probit link and the nlminb function with my own coding of the loglikehood, separately. As nlminb does not

...iables are continuous so I'm getting error messages in R. cod.fall.full.gam.model<-gam(Kept.CPUE~s(HOUR)+s(LAT_dec)+s(LONG_dec)+s(meantemp_C)+s(meandepth_fa)+s(change_depth)+s(seds), data=cod.fall.version2,family=poisson) In dpois(y, mu, log = TRUE) ... : non-integer x = 5.325517 Thanks Sally -- View this message in context: http://www.nabble.com/GAM-and-Poisson-distribution-tp20508604p20508604.html Sent from the R help mailing list archive at Nabble.com.

I've read the Wiki on using asterisk's built-in transfer options (#8 and #6). They work fine but how does one cancle an attended transfer? Example: I have person on phone, I hit #6 to being att-transfer. I enter Sally's extension. I let it ring for a few seconds. Sally never picks up but her voicemail does. How do I hangup her voicemail and resume the previous call? The example on the wiki assumes the transferee picks up the phone. :/ -Matthew -- ----------------------------------------------------------...

...rently have Polycom 501 phones. We have Asterisk with Realtime/MySQL running for our SIP/Voicemail/Extensions. When one phone dials another, the receiving end does in fact see the callers ID. But... our old phone system set the caller id on the senders phone to show who they called. Example... If Sally calls Jim, then Sally's phone should just say "1001", it should say "Jim <1001>". Any know if this is possible. Our old PBX did this, and the bosses were curious if this is possible. Thanks, Rob

Thanks to those who had suggestions on my last post, but none of those seems to have worked. I have narrowed down the problem a bit though, seems users can't write to a share that is not their primary group. For example: Bob's primary group is Bob and secondary group is Sally. Bob can write to the Bob group share but not the Sally group share. Anymore thoughts/suggestions. Thanks again in advance. Ben Following is the original message: Am having trouble getting samba to work properly it seems. Setup went smooth, the processes are running. Can log in with smbclie...

...icients(fred) beta1.hat <- coefficients(fred)[2] beta2.hat <- coefficients(fred)[3] n <- length(V1) nboot <- 1000 beta1.star <- double(nboot) beta2.star <- double(nboot) for (i in 1:nboot) { k <- sample(1:n, replace = TRUE) x.star <- V1[k] y.star <- V2[k] sally <- ltsreg(y.star ~ x.star + I(x.star^2)) curve(predict(sally, data.frame(x.star = x)), add = TRUE, col = 2) beta1.star[i] <- coefficients(sally)[2] beta2.star[i] <- coefficients(sally)[3] } points(V1, V2, pch = 16) curve(predict(fred, data.frame(V1 = x)), add = TRUE,...