search for: salaris

Hi, Is there an easy way of querying an active record for a maximum column value? I need to do queries like: SELECT MAX(salary) FROM employees TIA, Jeroen

Hello all. I have the following: plot(salaries$yearID, salaries$salary, type='n', xaxt='n', xlab='', yaxt='n', ylab='') axis(1, at=unique(salaries$yearID), labels=unique(salaries$yearID), lwd=.25, tck=-0.05) axis(2, axTicks(2), format(axTicks(2), scientific = F)) Which nicely creates the Y axis with the raw numbers, which are in the range of .5 - 7

I have the data similar to the following in a data frame: LastName Department Salary 1 Johnson IT 56000 2 James HR 54223 3 Howe Finance 80000 4 Jones Finance 82000 5 Norwood IT 67000 6 Benson Sales 76000 7 Smith Sales 65778 8 Baker HR 56778 9 Dempsey HR 78999 10 Nolan

Easy one: Let''s say I have a table called ''employees'' with a column called salaries, how can I add Employee.salaries_total to the model? Thanks! -- Posted via http://www.ruby-forum.com/.

Hopefully this is an easy problem... I'm trying to add a partitioned rank column to a data frame where the rank is calculated separately across a partition by categories, the way you could easily do in SQL. I found this solution in the archives that looked like it might work: http://tolstoy.newcastle.edu.au/R/e11/help/10/09/8675.html The example has a data frame with several car companies,

Hi, is there an R function like sql's TOP key word? I have a dataframe that has 3 columns: company, person, salary How do I get top 5 highest paid person for each company, and if I have fewer than 5 people for a company, just return all of them? Thanks, Richard [[alternative HTML version deleted]]

Hi, netters, First of all, thanks a lot for all the prompt replies to my earlier question about "merging" data frames in R. Actually that's an equivalence to the "join" clause in mysql. Now I have another question. Suppose I have a data frame X with lots of columns/variables: Name, Age,Group, Type, Salary. I wanna do a subtotal of salaries: aggregate(X$Salary,

Hi, What do you think is a reasonable salary for a ROR programmer in Manchester, UK? If you''re working with ROR and in the UK i''d be interested in knowing your salary :-) Your opinions would be very valuable to me JD -- Posted via http://www.ruby-forum.com/.

Hello I have Vacancy model and vacancy_spec test with validates_numericality_of :salary, greater_than: 1 in the model and validate_numericality_of(:salary).is_greater_than(2) in the _spec. When i run rspec spec command tests pass (in some cases and in other they don''t) Why? vacancy.rb ------------------------ class Vacancy < ActiveRecord::Base validates_presence_of :name,

Dear "R Gurus", I am having two dummy csv data sets A and B containing 19 and 15 cases/observations respectively. From the two data set 13 cases are intersection. From one of the two (any) data set, How do I then retrieve the unmerged data ? let's take A for example, six cases must appear in our results. See the R codes below. Please assist. Looking forward to hearing

Plotting with 2 x axis? One axis inside another, for example salary within state, 1-50 | 50 ? 100 | 100+ | 1- 50 | 50 -100 | 100+ | ? repeated bins for salary AL ! AR ?? more states The values are all stored with a single data frame. I have tried different things with the axis function and done many

I'm sorry for the way OT post, but here goes. I'm an informatics specialist, and R user. My wife is a secondary school maths teacher. My wife recently tried to explain to her class the link between education and potential salary, and I would love to be able to show this graphically, however, I cannot find any freely available data for this. Does anyone know of a suitable dataset,

The dataframe is id salary 100 500 101 600 102 700 103 800 how can i generate a subsets if salary>600? -- View this message in context: http://r.789695.n4.nabble.com/Filtering-in-R-tp2299603p2299603.html Sent from the R help mailing list archive at Nabble.com.

Hi everyone, I''m new to Rails and Ruby, and have been working my way through the Pickaxe and Agile Rails books for the last week or so. With a background in payroll apps I found that the default ActiveRecord mapping of decimal columns to float variables really bothered me! Financial calcs need high levels of accuracy and floats just don''t give you that. I know there are a bunch

How do you label Xtick and Ytick marks with Currency symbols: $2000 instead of 2000? I would like to add dollar symbols to tickmarks on boxplots, histograms and back-to-back histograms. My Examples (requiring the lattice and Hmisc packages): data(case0102, package="Sleuth2") str(case0102) boxplot(Salary~Sex, case0102) histogram(~ Salary | Sex, data=case0102) require(Hmisc) #

I am facing a problem with a function in survey package. The function svyvar gives the estimated population variance from a given sampling scheme. I am working with a data having more than four continuous variables. In order to have have population total for all those cont. variables I have written in the following format svyvar(~var1+var2+var3+var4+var5+var6,data) ; var1,var2,...,var6 are 6

I have a string like this st <- "SELECT COUNT(empid), COUNT(mgrid), COUNT(empname), COUNT(salary), FROM Employees" How can I remove the last comma before the FROM statement? -J

I have a query which returns a data set like so: > salaries yearID POS pct 1 2009 RF 203 2 2009 DH 200 3 2009 1B 198 4 2009 3B 180 5 2009 LF 169 6 2009 SS 156 7 2009 CF 148 8 2009 2B 97 9 2009 C 86 10 2008 DH 234 11 2008 1B 199 12 2008 RF 197 13 2008 3B 191 14 2008 SS 180 15 2008 CF 164 16 2008 LF 156 17 2008 2B 104 18 2008

Hello I am a Ruby newbie, thus a rather simple question. My list view shows table records and enables user to click a button in order to change value of one attribute in given record. I use this code to invoke a method from controller: <%= button_to "Change", { :action => "edit", :id => prog.id_prog } %> My method looks like this (just a simple one - to set the

Mydata is as under. dat=" salary ex + 1 1856 1799 + 2 1856 1800 + 3 1858 1800 + 4 1858 1801 + 5 1862 1803 + 6 1862 1805 + 7 1862 1810 + 8 1865 1805 + 9 1865 1808 + 10 1865 1815 + 11 1865 1820 + 12 1870 1810 + 13 1870 1830 + 14 1880 1840 + 15 1880 1845 + 16 1880 1851 + 17 1880 1853 + 18 1880 1855 + 19 1885 1850 + 20 1885 1852 + 21 1885 1857 + 22 1885 1860 + 23