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2006 Jun 05
1
Survey - twophase
...above table) Ergo, the y.ratio estimator = r*x.bar(phase1) = 1.5*0.08 = 0.12 with variance = (n1-n2)/n1 * s_regression^2/n2 + s_y^2/n1 = 900/1000 * 0.0765/100 + 0.129/1000 = .00081 SE .02846 with s_regression^2 = yk=c(rep(0,85), rep(1,15)); xk=c(rep(0,90), rep(1,10)) 1/98*sum((yk-1.5*xk)^2) and s_yk^2 = 1/99 * sum( (yk-.15)^2)=0.1287879 I am sorry to bother you with my false calculations, but I just don't know how to receive the correct results. Please help. My example is taken from Kauermann/ Kuechenhoff 2006, p. 111f. thank you so much yours always mark