Displaying 11 results from an estimated 11 matches for "rxy".
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2009 May 11
0
Partial correlation function required
...ot;There should be given data\n")
}
data <- data.frame(x,y,z)
if(na.rm == T){
data = na.omit(data)
}
- Ignored:
# recursive formula
if(dim(z)[2] == 1){
tdata <- na.omit(data.frame(data[,1],data[,2]))
rxy <- cor(tdata[,1],tdata[,2],m=method)
tdata <- na.omit(data.frame(data[,1],data[,-c(1,2)]))
rxz <- cor(tdata[,1],tdata[,2],m=method)
tdata <- na.omit(data.frame(data[,2],data[,-c(1,2)]))
ryz <- cor(tdata[,1],tdata[,2],m=met...
2009 Jul 13
0
testing equality of two dependent correlations + normality issue
...(hopefully simple?) stats question. I would
like to test equality of two correlation coefficients in a setting with
three variables X,Y,Z, i.e. equality of r(X,Y) and r(Z,Y). I have found a
formula to transform the "2 dependent correlations difference" to
t-distribution with N-3 df:
t = (rxy - rzy)* SQRT[{(n - 3)(1 + rxz)}/ {2(1 - rxy^2 - rxz^2 - rzy^2 +
2rxy*rxz*rzy)}]
(Blalock, H., 1972. Social Statistics. NY: McGraw-Hill. Page 406-7). Am
actually not sure whether this is exact or approximate (even given normality
assumption, the Fisher's Z-transform which this is - I assume - ba...
2013 Aug 27
1
[PATCH] drivers/char: pl011: Enable receive timeout interrupt
The commit 874f76a "PL011: fix reverse logic for interrupt mask register"
introduced regression on the Versatile Express. The board didn''t receive
correctly input.
The timeout interrupt may be asserted when the FIFO is not empty, and no futher
data is received over a 32-bit period.
Signed-off-by: Julien Grall <julien.grall@linaro.org>
---
xen/drivers/char/pl011.c | 2
2001 Feb 16
1
Sub_scribe and a question
...rix (loops)_______ (sec): ", =
timing, "\n"))
remove("b", "j", "k")
flush.console()
# (5)
cumulate <- 0; p <- 0; vt <- 0; vr <- 0; vrt <- 0; rvt <- 0; RV <- 0; j =
<- 0; k <- 0;
x2 <- 0; R <- 0; Rxx <- 0; Ryy <- 0; Rxy <- 0; Ryx <- 0; Rvmax <- 0
# Calculate the trace of a matrix (sum of its diagonal elements)
Trace <- function(y) {sum(c(y)[1 + 0:(min(dim(y)) - 1) * (dim(y)[1] + =
1)], na.rm=3DFALSE)}
for (i in 1:runs) {
x <- abs(rnorm(22*22)); dim(x) <- c(22, 22)
timing <- system.time({...
2006 Aug 21
1
Retrieving p-values and z values from lmer output
I can't find a way to retrieve z values and p-values from the output
from lmer in the lme4 package. How is this done?
Rick B.
2013 Oct 09
4
[LLVMdev] Subregister liveness tracking
On Oct 8, 2013, at 2:06 PM, Akira Hatanaka <ahatanak at gmail.com> wrote:
> What I didn't mention in r192119 is that mthi/lo clobbers the other sub-register only if the contents of hi and lo are produced by mult or other arithmetic instructions (div, madd, etc.) It doesn't have this side-effect if it is produced by another mthi/lo. So I don't think making mthi/lo clobber the
2006 Jul 04
1
lmer print outs without T
Hi,
I have been having a tedious issue with lmer models with lots of
factors and lots of levels. In order to get the basic information at
the beginning of the print out I also have to generate these enormous
tables as well. Is there a method command to leave off all of the
effects and correlations? Or, do I have to go to string commands?
2006 Jul 15
3
names() function and lmer()
Hello All,
I would like to retrieve some of the results from the lmer(...)
function in library lme4. If I run a model, say
fm.1 <- lmer(y ~ 1 + (1 | x), data = dog)
and try names(fm.1), I get NULL. Is there anyway to retrieve the information?
Thanks
2013 Oct 18
0
pamer.fnc y la nueva versión de R
Gracias a todos por las recomendaciones. Ya me he puesto en contacto con el
autor y le explicado donde esta el error. Es tan fácil como que han
cambiado la estructura de los objetos tipos lmer desde la versión 2.15.3
con lo que su paquete dejo de funcionar. Por suerte la nueva estructura
conserva por lo menos la parte necesaria para hacer sus funciones. Se
localizar el fallo y como arreglarlo, lo
2013 Oct 18
2
pamer.fnc y la nueva versión de R
Javier,
Creo que aquí aplica la ley de Linus que dice: "Dado un número
suficientemente elevado de ojos, todos los errores se convierten en
obvios". La persona que revisa y encuentra un error no necesariamente
tiene que ser la misma que la que lo escribe. Una motivación muy importante
al compartir un código es la de recibir los beneficios del control de
calidad por parte de tus pares.
2013 Dec 02
1
pamer.fnc y la nueva versión de R
Hace unos meses os escribir para comunicaros que había un fallo en esta
función. Como os prometí os comento la respuesta por si alguno está
interesado en utilizar el paquete LMERconvenientsfucntions
Dear Javier,
The package has been updated and should work for you fine now. Note that
function mcp.fnc does not return the fourth plot (dffits) anymore. We still
have to figure out a way to compute