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Hi, I have a long matrix of the following form which I would like to subset according to the third column: [x y z]: a1 c1 1 a1 c1 2 a2 c1 1 a1 c2 1 a1 c2 2 . . . The first two columns a characters ai and cj. I would like to keep all the rows where there are two entries for z, 1 and 2. That is, I want: a1 c1 1 a1 c1 2 a1 c2 1 a1 c2 2 . . . I try to use something like

Hi, I ran a program that was exhausting the (unix) server's available memory. I got a bus error and then chose to save and quit workspace (option 4). That may not have been a smart idea - when I try to use R now, I get the error message: Error in load(name, envir = .GlobalEnv) : ReadItem: unknown type 0, perhaps written by later version of R Fatal error: unable to restore saved data in

Hi all, I am trying to create a unique identifier for each row, combining numbers from three columns. Do you know if there is a general formula to do this (or some manual where I can read about this)? I figure I can use the numeric entries of the columns as "coordinates" and multiply them with different coefficients (different magnitudes) to get the unique ID - but it would be nice to

Hi, I am trying to estimate a VECM without constant using the following code: data(finland) sjf <- finland sjf.reg<-ca.jo(sjf, type = c("eigen"), ecdet = c("none"), K = 2,spec=c("transitory"), season = NULL, dumvar = NULL) cajools(sjf.reg) While the cointegration test does not use a constant, it is used in the cajools which I do not want. I am sure I am

Hi, I am trying to replicate blocks of a matrix (defined by factors) into another matrix, but an unequal, consecutive number of times for each factor. I need to find an elegant and fast way to do this, so loops will not work. An example of what I am trying to do is the following: # the data - first column entries are both data and the two factors x<-matrix(c(1,2,3,4),2,2) > x [,1]