search for: rueda

Dear Oscar,   Thanks for your help.It's so nice of you to explain this package to me.   Best Regards,   James LAN 发件人： Oscar Rueda [via R] <ml-node+s789695n4431468h14@n4.nabble.com> 收件人： monkeylan <lanjinchi@yahoo.com.cn> 发送日期： 2012年2月29日, 星期三, 下午 9:21 主题: Re: Bayesian Hidden Markov Models Dear James, The distances are normalized between zero and 1, so in your case all of them will be zero. You can check that...

Hi, We are analizing the relationship between the abundance of groupers in line transects and some variables. We are using the quasipoisson distribution. Do we need to include the length of the transects as an offset if they all have the same length?? Also, can we include in the gam models variables that are measured at different spatial scales? We have done an analysis to see what variables

...ry share for domain controller [netlogon] path = /usr/local/samba/lib/netlogon read only = yes write list = ntadmin ; share for storing user profiles [profiles] path = /export/smb/ntprofile read only = no create mask = 0600 directory mask = 0700 -- | Ariel Molina Rueda | | ariel@ml.com.mx | www.artesann.com ___________________

...14.4794 2.4754 4 10.2167 2.2024 5 8.462 1.8876 6 7.1204 1.8919 7 6.7124 1.8915 8 6.5114 1.9193 9 6.3748 1.864 Error: subscript out of bounds Would someone in the list help me with these errors? Cheers, Oscar Oscar M. Rueda, PhD. Postdoctoral Research Fellow, Caldas Lab, Breast Cancer Functional Genomics. University of Cambridge. Cancer Research UK Cambridge Institute. Li Ka Shing Centre, Robinson Way. Cambridge CB2 0RE England Please note that my email address will be changing to: Oscar.Rueda at cruk.cam.ac.uk

Hi, I am comparing the observed and fitted values of my GAM model, which includes the explanatory variables: longitude, depth, ssh, year and month. When I compare observed and fitted values for longitude, depth and ssh it works. But when I try to do it for month and year (which are as factors in the GAM model) it doesn't work. My observed and fitted values are exactly the same.. How is that

..., "cansado") # 0 Necesito así, as.dist(miresultado)... A B C D ... A 0 B 0.2 0 C 0.1 0 0 D 0.9 0.89 0 ... No sé si le puedo explicar a la función dist() o a alguna amiga suya que method = "ALINE" quiere decir que use la función `aline()`. O si tengo que intentar reinventar la rueda, pero con alineR::aline(x). También capaz que pueda evitar que aparezcan los NA sin mellar el trabajo. Gracias por la pacencia. -- Juan Abasolo Hizkuntzaren eta Literaturaren Didaktika Saila Bilboko Hezkuntza Fakultatea Euskal Herriko Unibertsitatea UPV/EHU Sarriena auzoa z/g 48940 Leioa Bizk...

Hello everyone, I have a data set like this: > head( fish_transect) ID_TRANSECT ID_PROJECT DE_ZONE DE_LOCALITY DE_SECTOR MES 1 42 MB Tarragona Creixell Control I 9 2 42 MB Tarragona Creixell Control I 9 3 42 MB Tarragona Creixell Control I 9 4 42 MB Tarragona Creixell Control I 9 5 42

...después en otras librerías. Aunque con tu respuesta soy capaz de crear una función que permite la generación de la estructura que te he indicado de un paso de modo totalmente automatizado, ¿Existe alguna función que haga la conversión directamente? (Simplemente es para que no re-invente yo mismo la rueda) Mi intención es usar después ggmap con ggplot2 Un saludo y gracias en todo caso, con tu indicación ya te digo, dar solución a mi objetivo de crear algo que directamente me lea los ficheros de modo como yo quiero en un solo paso y todo dentro de R (como debe ser) > From: oscar.perpinan en upm.es...

Hello, My name is Felipe I succesfuly installed Shorewall 4.4.20.3 in Ubuntu 10.04, This installation is for controlling the access into the local Network, My question is if it is possible to make a conecction WAN to LAN using Terminal Name?? i have been searching in goolge but i didnt find an answer!!!! For example we have IP Public into shorewall with 2 interfaces, and in the LAN we have 3

...gt; > B 0.2 0 > > C 0.1 0 0 > > D 0.9 0.89 0 > > ... > > > > No sé si le puedo explicar a la función dist() o a alguna amiga suya que > > method = "ALINE" quiere decir que use la función `aline()`. O si tengo > que > > intentar reinventar la rueda, pero con alineR::aline(x). > > > > También capaz que pueda evitar que aparezcan los NA sin mellar el > trabajo. > > > > Gracias por la pacencia. > > > > -- > Marcelino de la Cruz Rot > Depto. de Biología y Geología > Física y Química Inorgánica >...

...después en otras librerías. Aunque con tu respuesta soy capaz de crear una función que permite la generación de la estructura que te he indicado de un paso de modo totalmente automatizado, ¿Existe alguna función que haga la conversión directamente? (Simplemente es para que no re-invente yo mismo la rueda) Mi intención es usar después ggmap con ggplot2 Un saludo y gracias en todo caso, con tu indicación ya te digo, dar solución a mi objetivo de crear algo que directamente me lea los ficheros de modo como yo quiero en un solo paso y todo dentro de R (como debe ser) > From: oscar.perpinan en upm....

Hi all: I already made a dendrogram, I want to change the labels; In my data set there is one column with text that I want to set as the labels, any one can tellme how can I do it? Thanks, Ana Marcela [[alternative HTML version deleted]]

Hi If I have a <- Inf + 1i then Re(a) is Inf, and Im(a) is 1, as expected. But if b <- 1 + Inf * 1i, then Im(b) = Inf , as expected, but Re(b) = NaN, which I didn't expect. Why this asymmetry? How to define an object with Re(b)=1, Im(b)=Inf? -- Robin Hankin Uncertainty Analyst Southampton Oceanography Centre European Way, Southampton SO14 3ZH, UK tel 023-8059-7743

Dear R users, I´m studying about Bayesian Statistics. In this context, please, anyone have some basic script of RJMCMC (Reversible Jump Markov chain Monte Carlo) in R or WinBUGS? My aim is to learn how to implement this methodology. Thanks a lot. Marcus Vinicius [[alternative HTML version deleted]]

Hi, I am using this loop par(mfrow=c(3,3)) annos<-c(2001:2007,2009) for (i in annos) { t<-subset(masia,YEAR==i) t$FAMILIA<-drop.levels(t$FAMILIA) pie(table(t$FAMILIA),main=i) } To make piecharts of species composition among years (my data frame is called "masia"). So I get 1 piechart of the families that we have found in our survey each year. We don't have always

I just can't get kphone to register with asterisk, i can make calls to the demos and even get into the mailbox but kphone cannot register. Here's my story. Can you help me?? Please I have installed asterisk on debian using apt-get install asterisk. I have configured an extension in extensions.conf as follows exten => 8003,1,Dial(Sip/8003,${RINGTIME},rt) exten =>

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Hola buenos días: Hace algún tiempo mandé una duda que sobre fichero tipo shapefile que publica el Instituto Geográfico Nacional de España y que detallo en el word Duda_sobre_shp. El tema es que al final no obtuve respuesta (es cierto que lo mandé en Agosto y en esa fechas entiendo que sea normal, por tanto por recomendación de un conocido vuelvo de nuevo a remitir la cuestión) Como no podía

I have two pairs of related vectors x1,y1 and x2,y2 I wish to do a test for differences in means of x1 and y1, ditto x2 and y2. I am getting odd results. I am not sure I am using 'pt' properly... I have not included the raw vectors as they are long. I am interested if I am using R properly... > c(length(x1), length(y1), length(x2), length(y2)) [1] 3436 1619 2677 2378 First

r-help: I have an R package suggestion. After spending several hours the other day installing about a dozen packages, I had an idea. In xemacs, there is a "sumo" package which allows me to install a large bundle of xemacs packages at one time (about a 120 modes including ESS). I think R should have a similar bundle. It would be so much easier than hunting/downloading/installing.