Displaying 5 results from an estimated 5 matches for "roots2".
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roots
2011 Jun 09
1
Trying to make code more efficient
I have a repetative task in R and i'm trying to find a more efficient way to
perform
the following task.
lst <- list(roots = c("car insurance", "auto insurance"),
roots2 = c("insurance"), prefix = c("cheap", "budget"),
prefix2 = c("low cost"), suffix = c("quote", "quotes"),
suffix2 = c("rate", "rates"), suffix3 = c("comparison"),
state =...
2011 Jun 09
1
Error: missing values where TRUE/FALSE needed
I'm writing a function and keep getting the following error message.
myfunc <- function(lst) {
lst <- list(roots = c("car insurance", "auto insurance"),
roots2 = c("insurance"), prefix = c("cheap", "budget"),
prefix2 = c("low cost"), suffix = c("quote", "quotes"),
suffix2 = c("rate", "rates"), suffix3 = c("comparison"))
myone <- function(x, y) {
nu <- do.call(p...
2011 Jun 09
2
Problem with a if statement inside a function
...nn Arbor, MI", "South Bend, IN",
"Daytona Beach, FL", "Peoria, IL", "Atlantic City, NJ", "Antioch,
CA", "Thousand Oaks, CA")
lst <- list(roots = c("car insurance", "auto insurance"),
roots2 = c("insurance"), prefix = c("cheap", "budget"),
prefix2 = c("low cost"), suffix = c("quote", "quotes"),
suffix2 = c("rate", "rates"), suffix3 = c("comparison"),
state =...
2011 Jun 06
1
Merge two columns of a data frame
I have the following data:
prefix <- c("cheap", "budget")
roots <- c("car insurance", "auto insurance")
suffix <- c("quote", "quotes")
prefix2 <- c("cheap", "budget")
roots2 <- c("car insurance", "auto insurance")
roots3 <- c("car insurance", "auto insurance")
suffix3 <- c("quote", "quotes")
df1 <- expand.grid(prefix, roots, suffix)
df2 <- expand.grid(prefix2, roots2)
df3 <- expand.grid(roo...
2011 Jun 09
1
Using a function inside a function
I'm trying to run a function inside a function but get an error message.
lst <- list(roots = c("car insurance", "auto insurance"),
roots2 = c("insurance"), prefix = c("cheap", "budget"),
prefix2 = c("low cost"), suffix = c("quote", "quotes"),
suffix2 = c("rate", "rates"), suffix3 = c("comparison"))
myfunc <- function(lst) {
myone <-...