search for: ron_michael70

I have two variables (x,y) : x : it takes all integer values from 0 to y and, y : takes all values from 0, 10 I am looking for some R code to find all possible pairs of (x,y). Can anyone please help me? New Email addresses available on Yahoo! Get the Email name you've always wanted on the new @ymail and @rocketmail. Hurry before someone else does! [[alternative HTML version

...solve the determinant of "p1" for the values of "z" (I am working with some multivariate time series modelling). When I use det() function, it am getting error that, that function is not for objects with class polynomial. Any idea please? Thanks, --- On Wed, 13/10/10, Ron_M <ron_michael70@yahoo.com> wrote: From: Ron_M <ron_michael70@yahoo.com> Subject: [R] Problem to create a matrix polynomial To: r-help@r-project.org Date: Wednesday, 13 October, 2010, 4:31 PM Dear all R users, I was trying to create a polymonial using the polynom() of "PolynomF" package. My pr...

Dear all R gurus, I have following syntax: y = c(1:10) chippy <- function(x) { y[5] = x sin(cos(t(y)%*%y)*exp(-t(y)%*%y/2)) } curve(chippy, 1, 20, n=200) But I am getting error while executing : Error in xy.coords(x, y, xlabel, ylabel, log) : 'x' and 'y' lengths differ In addition: Warning message: number of items to

Hi, Let say I have a date variable: > ?asd <- as.Date("2012-01-03") > asd [1] "2012-01-03" Now, I want to express this date like 3/1/2012. can somebody help me how to achieve that? Thanks,

Hi all, can anyone please tell me what is the key-word to clear the screen? I am aware of the "cont+L", however I need some R-syntax, that can be typed into the console to clear the screen.   Thanks [[alternative HTML version deleted]]

I need to solve a equation like this : a = b/(1+x) + c/(1+x)^2 + d/(1+x)^3 where a,b,c,d are known constant. Is there any R-way to do that? Thanks in advance -- View this message in context: http://www.nabble.com/How-to-solve-following-equation--tp20785063p20785063.html Sent from the R help mailing list archive at Nabble.com.

Hi, suppose I have following codes : library(zoo); library(ggplot2) dat <- matrix(rnorm(500*2), 500); dat <- zooreg(dat, start = as.Date("01/01/01", "%m/%d/%y"), frequency=1); plot(dat) head(dat); month.no <- format(index(dat), "%m"); dat1 <- cbind(coredata(dat), as.numeric(month.no)) x <- dat1[,1]; y <- dat1[,2]; z <- dat1[,3] Now I draw a

Hi, I want find all roots for the following polynomial : a <- c(-0.07, 0.17); b <- c(1, -4); cc <- matrix(c(0.24, 0.00, -0.08, -0.31), 2); d <- matrix(c(0, 0, -0.13, -0.37), 2); e <- matrix(c(0.2, 0, -0.06, -0.34), 2) A1 <- diag(2) + a %*% t(b) + cc; A2 <- -cc + d; A3 <- -d + e; A4 <- -e fn <- function(z) { y <- diag(2) - A1*z - A2*z^2 - A3*z^3 - A4*z^4

I was trying to dw data from Economagic [http://www.economagic.com/em-cgi/data.exe/libor/day-ussnon], using following code : library(fimport) dat2 = economagicSeries("libor/day-ussnon", frequency = "daily") Here I see that data is not complete, downloaded data starts from "2007-12-31 ", whereas actual data is available from 2001. secondly, how I convert that data

Hi all, Is there any process to conduct a search for a particular digit or letter in a ch. string? For example I want to make a search where 1st numeric figure appears in the string "asd123". Here the answer should be "4" Thanks, -- View this message in context: http://www.nabble.com/Searching-1st-number-within-a-ch.-string-tp25400580p25400580.html Sent from the R help

Hi all, Can anyone tell me why I am getting different results in calculating SD of 2 numbers ? > (1.25-0.95)/2 [1] 0.15 > sd(c(1.25, 0.95)) [1] 0.2121320 # why it is different from 0.15? Regards, Send instant messages to your online friends http://uk.messenger.yahoo.com [[alternative HTML version deleted]]

Hello, I am into some calculation on a list object, therefore requesting the peers if there is any short cut way to so the same calculation. Let say I have following list object: > List <- vector('list', length = 3) > set.seed(1) > List[[1]] <- rnorm(5) > List[[2]] <- rnorm(2) > List[[3]] <- rnorm(7) > List [[1]] [1] -0.6264538 0.1836433 -0.8356286

Hi, I have 2 questions on list object:   1. Suppose I have a matrix like: dat <- matrix(1:9,3)   Now I want to replicate this entire matrix 3 times and put entire result in a list object. Means, if "res" is the resulting list then I should have:   res[[1]]=dat, res[[2]]=dat, res[[3]]=dat   How can I do that in the easilest manner?   2. Suppose I have 2 list objects: list1 <- list2

Hi everyone, I have this kind of raw dataset : - <Temp diffgr:id="Temp14" msdata:rowOrder="13"> <Date>2005-01-17T00:00:00+05:30</Date> <SecurityID>10149</SecurityID> <PriceClose>1288.40002</PriceClose> </Temp> - <Temp diffgr:id="Temp15" msdata:rowOrder="14">

...otically it should collapse to "truth" i.e. for large sample size, variance of MLE should be zero. However asymptotic normality says, MLE have some distribution and hence variance.   Can anyone please clarify me? Your help will be highly appreciated. --- On Wed, 8/10/08, Ron Michael <ron_michael70@yahoo.com> wrote: From: Ron Michael <ron_michael70@yahoo.com> Subject: [R] MLE To: r-help@stat.math.ethz.ch Date: Wednesday, 8 October, 2008, 6:05 PM May I ask one statistics related question please? I have one query on MLE itself. It's property says that, for large sample size it is...

Hi all, I am wondering is there any way to check whether some Directory exists or not, given the parent path of that directory? After searching for a while I found that there is a function dir.create() to create some directory. However I need to know whether such directory already exists or not, otherwise I will create that.   Thanks, [[alternative HTML version deleted]]

Let say, I have a matrix with 8 rows and 6 columns:  >  df1  <- matrix(NA, 8, 4)  > df1       [,1] [,2] [,3] [,4]  [1,]   NA   NA   NA   NA  [2,]   NA   NA   NA   NA  [3,]   NA   NA   NA   NA  [4,]   NA   NA   NA   NA  [5,]   NA   NA   NA   NA  [6,]   NA   NA   NA   NA  [7,]   NA   NA   NA   NA  [8,]   NA   NA   NA   NA  Now I want to get **all possible** ways to fetch 6 cells at a

Hello everyone,   I have a matrix like :   mat <- matrix(rnorm(12*3), 3)   Now I want to break that matrix in 4 parts each of them are matrix of (3x3) and put those 4 matrices in a "list" object of length 4   Can anyone please tell me how to do that? Get your new Email address! Grab the Email name you&#39;ve always wanted before someone else does! [[alternative HTML

Hi, is there any direct R function to write an diagonal matrix in an opposite way? for example I want to get like:   > diag(rnorm(5))[,5:1]            [,1]       [,2]       [,3]      [,4]       [,5] [1,]  0.0000000  0.0000000  0.0000000  0.000000 -0.1504687 [2,]  0.0000000  0.0000000  0.0000000 -2.139669  0.0000000 [3,]  0.0000000  0.0000000 -0.2102133  0.000000  0.0000000 [4,]  0.0000000

I want to draw following plot, given here http://www.2shared.com/file/4327128/830b82c4/pic.html for the following data : dat <- cbind(rnorm(100), sample(c(1:4), 1000, T)) colnames(dat) <- c("data","level") Here x-axis should be on "data" and y-axis is for "level" and z-axis should be to display the frequency of "data" for a particular