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> On 16 Jun 2017, at 15:59 , Robert McGehee <rmcgehee at walleyetrading.net> wrote: > > For instance, what would you expect to get from unlist() if each element of the list had different levels, or were both ordered, but in a different way, or if some elements of the list were factors and others were ordered factors? >> unlist(list(ord...

...ractice. Has r-devel really lost the momentum for continuous improvement, to converge R to an optimum? I struggle to recognize the project I loved in 2000. ? Gesendet:?Freitag, 16. Juni 2017 um 18:31 Uhr Von:?"peter dalgaard" <pdalgd at gmail.com> An:?"Robert McGehee" <rmcgehee at walleyetrading.net> Cc:?"Jens Oehlschl?gel" <jens.oehlschlaegel at truecluster.com>, "r-devel at r-project.org" <r-devel at r-project.org> Betreff:?Re: [Rd] 'ordered' destroyed to 'factor' > On 16 Jun 2017, at 15:59 , Robert McGehee <rmcge...

On Wed, Apr 5, 2017 at 2:24 PM, Robert McGehee <rmcgehee at walleyetrading.net> wrote: > Winston, > I had a similar experience to you tracking down an insanely difficult bug > in my R code that "disappeared" whenever slight changes were made to the > script (e.g. like adding cat() statements). In my case, it coincided with >...

...element is not a scalar there is an error. as.character() does not seem to make a distinction between the all-scalar and not-all-scalar cases but does various things with NA's of various types. Bill Dunlap TIBCO Software wdunlap tibco.com On Mon, Jan 22, 2018 at 11:14 AM, Robert McGehee < rmcgehee at walleyetrading.net> wrote: > Also perhaps a surprise that the behavior depends on the mode of the NA. > > > is.na(as.character(list(NA_real_))) > [1] FALSE > > is.na(as.character(list(NA_character_))) > [1] TRUE > > Does this mean deparse() preserves NA-ness for...

...implying a bug where none exists, or that there was something wrong with Matrix or S4. Thanks again, Robert -----Original Message----- From: Georgi Boshnakov [mailto:georgi.boshnakov at manchester.ac.uk] Sent: Sunday, January 29, 2017 1:40 PM To: r-devel at r-project.org Cc: Robert McGehee <rmcgehee at walleyetrading.net> Subject: RE: R-devel Digest, Vol 167, Issue 25 Hi, Short answer: import 'as.matrix' and export your method(s) for it. From WRE: "All S4 classes to be used outside the package need to be listed in an exportClasses directive. Alternatively, they can be speci...

...bably use the PCRE regex library anyway. However, as this is basically what you did, I'm not sure why you're not happy with your existing approach. -----Original Message----- From: Paul Miller [mailto:pjmiller_57 at yahoo.com] Sent: Thursday, July 13, 2017 3:01 PM To: Robert McGehee <rmcgehee at walleyetrading.net> Cc: r-help at r-project.org Subject: Re: [R] Extracting sentences with combinations of target words/terms from cancer patient text medical records Hi Robert, Thank you for your reply. An attempt to solve this via a regular expression query is particularly helpful. Unfort...

...d the word breast. " [4] "1: This sentence contains the words breast and the term metastatic. 2: This sentence contains the word breast and the term stage IV." ________________________________ From: Robert McGehee <rmcgehee at walleyetrading.net> Cc: "r-help at r-project.org" <r-help at r-project.org> Sent: Wednesday, July 12, 2017 12:47 PM Subject: RE: [R] Extracting sentences with combinations of target words/terms from cancer patient text medical records Hi Paul, Sounds like you have your ans...

On 5 April 2017 at 15:46, Winston Chang wrote: | On Wed, Apr 5, 2017 at 2:24 PM, Robert McGehee <rmcgehee at walleyetrading.net> | wrote: | | > Winston, | > I had a similar experience to you tracking down an insanely difficult bug | > in my R code that "disappeared" whenever slight changes were made to the | > script (e.g. like adding cat() statements). In my case, it coincide...

Hi Paul, Sounds like you have your answer, but for fun I thought I'd try solving your problem using only a regular expression query and base R. I believe this works: > txt <- "Patient had stage IV breast cancer. Nothing matches this sentence. Metastatic and breast match this sentence. French bike champion takes stage IV victory in Tour de France." > pattern <-

On 01/20/2018 08:24 AM, William Dunlap via R-devel wrote: > I believe that for a list as.character() applies deparse() to each element > of the list. deparse() does not preserve NA-ness, as it is intended to > make text that the parser can read. > >> str(as.character(list(Na=NA, LglVec=c(TRUE,NA), > Function=function(x){x+1}))) > chr [1:3] "NA" "c(TRUE,

...ife easier during initial development, import the whole 'Matrix' and when things work think about cleaning up and importing only stuff that you need. Best regards, Georgi Boshnakov ------------------------------ Message: 15 Date: Fri, 27 Jan 2017 22:41:10 +0000 From: Robert McGehee <rmcgehee at walleyetrading.net> To: "r-devel at r-project.org" <r-devel at r-project.org> Subject: [Rd] Matrix package breaks as.matrix method Message-ID: <30D28A63376088428E8318DD67FD407F705B2E at ny-mailstore1.walleyetrading.net> Content-Type: text/plain; charset="us-ascii...

Dear all, ? I don't know if you consider this a bug or feature, but it breaks reasonable code: 'unlist' and 'sapply' convert 'ordered' to 'factor' even if all levels are equal. Here is a simple example: o <- ordered(letters) o[[1]] lapply(o, min)[[1]]??????????# ordered factor unlist(lapply(o, min))[[1]]? # no longer ordered sapply(o, min)[[1]]??????????# no

) On Wed, Apr 5, 2017 at 2:59 AM, Martin Maechler <maechler at stat.math.ethz.ch> wrote: > > >>>>> Winston Chang <winstonchang1 at gmail.com> > >>>>> on Tue, 4 Apr 2017 15:29:40 -0500 writes: > > > I've done some more investigation into the problem, and it is very > > difficult to pin down. What it looks like is

R developers, Seems I get a bad result ("%#4.0-1e" in particular) when trying to use prettyNum digits=0 with scientific notation. I tried on both my Linux box and on an online R evaluator and saw the same problem, so it's not limited to my box at least. I see the problem in both R 3.5.3 and R 3.3.2. options(scipen=-100) prettyNum(1, digits=0) [1] "%#4.0-1e" prettyNum(2,

Hi Bert, Thanks for your reply. It appears that I didn't replace the variable name "sampletxt" with the argument "x" in my function. I've corrected that and now my code seems to be working fine. Paul ________________________________ From: Bert Gunter <bgunter.4567 at gmail.com> Cc: R-help <r-help at r-project.org> Sent: Tuesday, July 11, 2017 2:00 PM

Hi, The Matrix package and the as.matrix method do not seem to be compatible inside of a package. Here's an example. I've created a simple package "mat" that defines an eponymous class and as.matrix method on that class. All is well, unless that package has the Matrix package in its Depends or Imports (and imports, e.g. the "Diagonal" function). Then my as.matrix

Feature request: I want to use update.formula to subtract an intercept (or other) term from a formula with a dot on the RHS. However, as this causes an error, I propose a patch below. Thus, I want: > update.formula(y ~ ., ~ . -1) [1] y ~ . - 1 Instead I get this error: Error in terms.formula(tmp, simplify = TRUE) : '.' in formula and no 'data' argument While the error

Also perhaps a surprise that the behavior depends on the mode of the NA. > is.na(as.character(list(NA_real_))) [1] FALSE > is.na(as.character(list(NA_character_))) [1] TRUE Does this mean deparse() preserves NA-ness for NA_character_ but not NA_real_? -----Original Message----- From: R-devel [mailto:r-devel-bounces at r-project.org] On Behalf Of Herv? Pag?s Sent: Monday, January 22,

Hello, I have a vector of values with significant autocorrelation, and I want to calculate an unbiased standard deviation that adjusts for the autocorrelation. The formula linked below purports to provide what I want: https://en.wikipedia.org/wiki/Unbiased_estimation_of_standard_deviation#Effect_of_autocorrelation_.28serial_correlation.29 However, rather than just implementing this equation in

Hi, It's been my experience that when you combine or aggregate vectors of factors using a function, you should be prepared for surprises, as it's not obvious what the "right" way to combine factors is (ordered or not), especially if two vectors of factors have different levels or (if ordered) are ordered in a different way. For instance, what would you expect to get from