search for: riskset

...nter-matching. For example, the following code produces a parameter estimate of -1.59 where I expect 0.63: d2 = structure(list(x = c(1, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 0, 0, 1, 0, 1, 0, 1, 0, 1), wt = c(5, 42, 40, 4, 43, 4, 42, 4, 44, 5, 38, 4, 39, 4, 4, 37, 40, 4, 44, 5, 45, 5, 44, 5), riskset = c(1L, 1L, 4L, 4L, 6L, 6L, 12L, 12L, 13L, 13L, 19L, 19L, 23L, 23L, 31L, 31L, 42L, 42L, 45L, 45L, 70L, 70L, 93L, 93L), cc = c(1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0 ), pseudotime = rep(1,24)), .Names = c("x", "wt", "riskset", "cc&qu...

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Dear useRs, I was asked to produce a survival curve like this: http://www.palug.net/Members/jabba/immaginetta.png/view with the cardinality of the riskset at the bottom. I do not like doing it, because it doesn't add any valuable information and because it doesn't discriminate between died and censored. Nevertheless, is there someone able to tell me how to do it? Currently the only way I know to it is using the text() function, but this wo...

I'm trying to learn how to use namespaces, so I have created a small package with two functions. My NAMESPACE file is importFrom(survival, Surv) export(mlreg.fit, risksets) because 'mlreg.fit' uses 'Surv' from 'survival'. However I get * checking package dependencies ... WARNING Namespace dependencies not required: survival Why? (If I remove 'importFrom' I get the expected Error message.) G?ran -- G?ran Brostr?m...

Now I try to add some C and Fortan code to my package, so the NAMESPACE file is useDynLib(eha) importFrom(survival, Surv) export(mlreg.fit, risksets) but I get ..... * checking R files for library.dynam ... OK * checking S3 generic/method consistency ... WARNING Error in .try_quietly({ : Error in library(package, lib.loc = lib.loc, character.only = TRUE, verbose = FALSE) : package/namespace load failed for 'eha' Execution ha...

Dear all, How can I analyze a life table (e.g. for a cohort of insects) in R? I have 20 insects in 200 cages with two different treatments, whose survival is followed over time, such that, e.g., in one treatment, the number of animals surviving is c(20,18,16,12,10,8,4,0), while in the other treatment the survival is c(20,20,18,18,16,15,15,14) at 8 subsequent time intervals. I would very

Hello. I apologize in advance for the VERY lengthy e-mail. I endeavor to include enough detail. I have a question about survival curves I have been battling off and on for a few months. No one local seems to be able to help, so I turn here. The issue seems to either be how R calculates Kaplan-Meier Plots, or something with the underlying statistic itself that I am misunderstanding. Basically,

...As long as the check doesn't get smarter...). This is the relevant part of my Fortran code: ----------------------------------------------------------- subroutine gmlfun(what, & totevent, totrs, ns, & antrs, antevents, size, & totsize, eventset, riskset, & nn, antcov, covar, offset, & beta, gamma, & loglik, h1, h2, h11, h21, h22, & score) ...... call gmlfun1(what, & totevent, totrs, ns, & antrs, antevents, size, & totsize, eventset, riskset,...

Sorry for cross-posting, but I realized my question might be more appropriate for r-devel... Thank you, Giovanni ________________________________________ From: R-help <r-help-bounces at r-project.org> on behalf of Giovanni Petris <gpetris at uark.edu> Sent: Tuesday, September 10, 2019 16:44 To: r-help at r-project.org Subject: [R] Calling a LAPACK subroutine from R Hello R-helpers!

Hello R users I have a question with Kaplan-Meier Curve with respect to my research. We have done a retrospective study on fillings in the tooth and their survival in relation to the many influencing factors. We had a long follow-up time (upto 8yrs for some variables). However, we decided to stop the analysis at the 6year follow up time, so that we can have uniform follow-up time for all the