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Dear R users, I want a help to write an algorithm for swapping rows and columns in a matrix thanks in advance [[alternative HTML version deleted]]

Dear R users, I have this program aa<-array(rep(0,27),dim=c(3,3,3)) a<-matrix(rep(1,9),ncol=3) n<-0 for (i in 1:3) {            a[i,]<-a[i,]*(-1)       n<-n+1       aa[,,n]<-a[i,] } but i real want to multiply each row  with -1 according to for loop and after that to put it in the array.  I will give an example for what excaclty want -1 -1 -1  1  1  1  1  1  1 -1 -1 -1 -1

Dear R users, I have an array that has matrices that i want BB[16,5,2:27] i want to put each of the 26 matrices into a List  thanks in advance [[alternative HTML version deleted]]

Dear R users, I have this problem with memory i guess  AA<-array(rep(0,96096000),dim=c(16,5,3003,400)) Error: cannot allocate vector of size 733.2 Mb can anyone help me,  Thanks in advance... [[alternative HTML version deleted]]

Dear R users, i have this problem with matrices i want to check between two matrices if they are isomorphic i will give an example for what excactly i want   1 -1  1                                 -1  1   1 -1   1  -1                                1  -1  -1   1  1   -1                                1   1  -1 this two matrices are isomorphic beacause if i change the first 2 columns the matrices

Dear R users, I have a Hadamard matrix 16x15 and i want to put 16x5 submatrices in an array put i have an error. > A1<-matrix(c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0, + 1,0,1,0,1,0,1,0,1,0,1,0,1,0,1, + 0,1,1,0,0,1,1,0,0,1,1,0,0,1,1, + 1,1,0,0,1,1,0,0,1,1,0,0,1,1,0, + 0,0,0,1,1,1,1,0,0,0,0,1,1,1,1, + 1,0,1,1,0,1,0,0,1,0,1,1,0,1,0, + 0,1,1,1,1,0,0,0,0,1,1,1,1,0,0, + 1,1,0,1,0,0,1,0,1,1,0,1,0,0,1, +

Dear R users, I have the "any" function of R  any(ind.c, ind.r, ind.sgn) all are logical factors  it works fine when any of three is true but when they are combined it doesnt work. i tried this any(ind.c, ind.r, ind.sgn,((ind.c==TRUE) & (ind.r==TRUE)), ((ind.c==TRUE) & (ind.sgn==TRUE)),((ind.r==TRUE) & (ind.sgn==TRUE)),  ((ind.c==TRUE) & (ind.r==TRUE) &

Dear R users, I want to check matrices when i change the order of the rows or/and the order of the columns or/and the combination of them i will give an example what i want  1  -1  1  1      1  1   1  1 -1  -1 -1 -1    -1 -1  -1  -1   1  1    1  1     1 -1    1   1 these 2 matrices are identical because i change the first row and make it third   1  -1  1  1      -1  1   1  1 -1  -1 -1

Dear R users, i want to put the results of a list to a for loop. i will give an example m1<-matrix(rep(1,15),ncol=5)   ind.sgn <- lapply(1:ncol(m1), combn, x = ncol(m1))  ind.sgn [[1]]      [,1] [,2] [,3] [,4] [,5] [1,]    1    2    3    4    5 [[2]]      [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [1,]    1    1    1    1    2    2    2    3    3     4 [2,]    2    3    4    5   

I have 3003 16x5 submatrices from a hadamard matrice of 16x15. I want to write an algorithm that check all of these 3003 matrices if they are isomorphic and i want to find and keep the non-isomorphic ones. Any help will be welcome.  [[alternative HTML version deleted]]

Dear R users,  I have 2 matrices dim(16x5) below and i want to write an algorithm that check the 2 matrices if they are isomorphic ones (Isomorphic matrices: if I change the rows or/and columns or/and zeros into 1 and 1 into zeros in a row(s) or column(s) are the 2 matrices identical). 0    0    0    0    0  1    0    1    0    1  0    1    1    0    0  1    1    0    0    1  0    0    0    1    1

i have this problem with matrices i want to check between two matrices if they are isomorphic i will give an example for what excactly i want   1 -1  1                                 -1  1   1 -1   1  -1                                1  -1  -1   1  1   -1                                1   1  -1 this two matrices are isomorphic beacause if i change the first 2 columns the matrices are identical