search for: rfm

I would like to compute the MC test (rfm.test) available in the package MarkedPointProcess (for the data BITOEK for example) in order to test the dependence between the marks and their locations. Why the syntax of rfm.test is false here? I have the message : ****************************** ML WARNING! Forbidden values! -- if there are to...

Six Fried Rice Contact: Geoff Coffey Phone: 602-384-1804 Email: geoff-5v4lRIDW0s4umAx9uhQu3g@public.gmane.org Ruby On Rails, Today''s Hottest Web Framework, Now Supports FileMaker Server Six Fried Rice, a FileMaker Pro Services Provider, Releases Rfm, a Free Open Source FileMaker API for Ruby and Ruby on Rails. The buzz about Ruby on Rails can be heard all over the web. This world class development platform makes web developers more productive when building powerful web sites with up-to-the minute data. But before today, it was unwieldy to in...

I'm trying to perform a RFM analysis on attached dataset, i'm able to get the results using the auto_rfm function but i want to define my own breaks for RFM, when i tried to define my own breaks i got the identical result i.e 111 for every ID. please help me with this with working R script. Thanks hemantsain.com

hello, I'm confused what you guys are talking about. i just want to set ideal threshold values for my RFM scores which can be done using Quantiles but i don't want to use quantiles because my data is not normally distributed so it will lead to wrong ranges of breaks. to fix this problem I'm looking for an approach which can define the ideal range to breaks to categorize RFM scores into 3 segmen...

Hi Hemant, Let's take it one step at a time. Save this code as "qdrfm.R" in your R working directory: It includes the comments I added last time and fixes a bug in the recency scoring. qdrfm<-function(x,rbreaks=3,fbreaks=3,mbreaks=3, date.format="%Y-%m-%d",weights=c(1,1,1),finish=NA) { # if no finish date is specified, use current date if(is.na...

Dear wise ones, I have a problem assigning different colors to bars in a barplot. The data I'm using is the following dataframe (truncated) : > L0 r n p t [...] 18 19 1 1 RFM 19 20 1 1 RFM 20 21 2 1 RFM 21 23 6 1 RIH 22 24 2 1 ROC 23 25 1 1 ROC 24 26 1 1 ROC 25 27 2 1 ROC 26 28 2 1 RFT 27 29 1 1 RFT 28 30 2 1 RFT 29 31 1 1 ROH [...] My barplot should display ascending bars according to L0$n. Their width depends on L0$p, which can be greater than...

...>> >> From: Hemant Sain [mailto:hemantsain55 at gmail.com] >> Sent: Friday, October 13, 2017 8:51 AM >> To: PIKAL Petr <petr.pikal at precheza.cz> >> Cc: r-help mailing list <r-help at r-project.org> >> Subject: Re: [R] How to define proper breaks in RFM analysis >> >> Hey, >> i want to define 3 ideal breaks (bin) for each variable one of those variables is attached in the previous email, >> i don't want to consider quartile method because quartile is not working ideally for that data set because data distribution is non...

Hi Guys, We''ve been using RFM to sync to a FMP server. As we were deploying the app to the production server, we encountered a small problem in this part of the code: In enviroment.rb: SERVER_CONFIG = { :host => "my.ip.number", :account_name => "user", :password => "pass" } DATAB...

...> Cheers > Petr > > From: Hemant Sain [mailto:hemantsain55 at gmail.com] > Sent: Friday, October 13, 2017 8:51 AM > To: PIKAL Petr <petr.pikal at precheza.cz> > Cc: r-help mailing list <r-help at r-project.org> > Subject: Re: [R] How to define proper breaks in RFM analysis > > Hey, > i want to define 3 ideal breaks (bin) for each variable one of those variables is attached in the previous email, > i don't want to consider quartile method because quartile is not working ideally for that data set because data distribution is non normal. > s...

I'm trying to perform an RFM analysis on the attached dataset, I'm able to get the results using the auto_rfm function but i want to define my own breaks for RFM. as follow r <-c(30,60,90) f <-c(2,5,8) m <-c(10,20,30) but when i tried to define my own breaks i got the identical result for RFM i.e 111 for every I...

Hi Hemant, As I suspected, the code broke when I got to the line: result <- rfm_auto(df, id="user_id", payment ="subtotal_amount", date="created_at") Error in rfm_auto(df, id = "user_id", payment = "subtotal_amount", date = "cr eated_at") : could not find function "rfm_auto" It looks like you are using th...

...s,mbreaks) If you want the breaks to work, make sure that > they cover the range of the input values, otherwise you get NAs. > > # expects a three (or more) column data frame where > # column 1 is customer ID, column 2 is amount of purchase > # and column 3 is date of purchase > qdrfm<-function(x,rbreaks=3,fbreaks=3,mbreaks=3,date.format="%Y-%m-%d", > weights=c(1,1,1),finish=NA) { > > # if no finish date is specified, use current date > if(is.na(finish)) finish<-as.Date(date(), "%a %b %d %H:%M:%S %Y") > x$rscore<-as.numeric(finish-...

...hat > >> they cover the range of the input values, otherwise you get NAs. > >> > >> # expects a three (or more) column data frame where > >> # column 1 is customer ID, column 2 is amount of purchase > >> # and column 3 is date of purchase > >> qdrfm<-function(x,rbreaks=3,fbreaks=3,mbreaks=3,date.format="%Y-%m-%d", > >> weights=c(1,1,1),finish=NA) { > >> > >> # if no finish date is specified, use current date > >> if(is.na(finish)) finish<-as.Date(date(), "%a %b %d %H:%M:%S %Y") &...

...the function (rbreaks,fbreaks,mbreaks) If you want the breaks to work, make sure that they cover the range of the input values, otherwise you get NAs. # expects a three (or more) column data frame where # column 1 is customer ID, column 2 is amount of purchase # and column 3 is date of purchase qdrfm<-function(x,rbreaks=3,fbreaks=3,mbreaks=3,date.format="%Y-%m-%d", weights=c(1,1,1),finish=NA) { # if no finish date is specified, use current date if(is.na(finish)) finish<-as.Date(date(), "%a %b %d %H:%M:%S %Y") x$rscore<-as.numeric(finish-as.Date(x[,3],date.forma...

...he breaks to work, make sure that >> they cover the range of the input values, otherwise you get NAs. >> >> # expects a three (or more) column data frame where >> # column 1 is customer ID, column 2 is amount of purchase >> # and column 3 is date of purchase >> qdrfm<-function(x,rbreaks=3,fbreaks=3,mbreaks=3,date.format="%Y-%m-%d", >> weights=c(1,1,1),finish=NA) { >> >> # if no finish date is specified, use current date >> if(is.na(finish)) finish<-as.Date(date(), "%a %b %d %H:%M:%S %Y") >> x$rscore&lt...

...ise your values and use quartile method. Cheers Petr From: Hemant Sain [mailto:hemantsain55 at gmail.com] Sent: Friday, October 13, 2017 8:51 AM To: PIKAL Petr <petr.pikal at precheza.cz> Cc: r-help mailing list <r-help at r-project.org> Subject: Re: [R] How to define proper breaks in RFM analysis Hey, i want to define 3 ideal breaks (bin) for each variable one of those variables is attached in the previous email, i don't want to consider quartile method because quartile is not working ideally for that data set because data distribution is non normal. so i want you to suggest a...

Hello, I'm working on RFM analysis and i wanted to define my own breaks but my frequency distribution is not normally distributed so when I'm using quartile its not giving the optimal results. so I'm looking for a better approach where i can define breaks dynamically because after visualization i can do it easily bu...

...ble answer. Cheers Petr > -----Original Message----- > From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Hemant Sain > Sent: Thursday, October 12, 2017 10:18 AM > To: r-help mailing list <r-help at r-project.org> > Subject: [R] How to define proper breaks in RFM analysis > > Hello, > I'm working on RFM analysis and i wanted to define my own breaks but my > frequency distribution is not normally distributed so when I'm using quartile its > not giving the optimal results. > so I'm looking for a better approach where i can define...

...vious email, i don't want to consider quartile method because quartile is not working ideally for that data set because data distribution is non normal. so i want you to suggest another method so that i can define 3 breaks with the ideal interval for Recency, frequency and monetary to calculate RFM score. i'm again attaching you some of the data set. please look into it and help me with the R code. Thanks *Data* user_id subtotal_amount created_at Recency Frequency Monetary 194849 6.99 8/22/2017 9 5 9.996 194978 14.78 8/28/2017 3 15 16.308 198614 18.44 7/31/2017 31 1 18.44 234569 34.99...

Two quick and simple questions; I want to install the "WinPower" software for my new UPS. On their web site, they have a tar.gz file available for download. I know the reasons for staying with RPM, if at all possible. I''ve Googled and Yahood for ""WinPower"+RPM+Linux and get hits, but no obvious RPM. I tried "yum install winpower" and the response was