Displaying 3 results from an estimated 3 matches for "rexgaus".
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dexgaus
2008 Nov 06
0
gamlss.dist
Hi,
I'm not sure how use curve(dexGAUS(…
None of the following four works:
rt<- rexGAUS(100, mu=300, nu=100, sigma=35)
m1<-gamlss(rt~1, family=exGAUS)
curve(dexGAUS(rt=x, mu=300 ,sigma=35,nu=100), 100, 600, main = "The ex-
GAUS density mu=300 ,sigma=35,nu=100")
curve(dexGAUS(x=rt, mu=300 ,sigma=35,nu=100), 100, 600, main = "The ex-
GAUS density mu=300 ,sigma=35,n...
2012 Nov 16
0
dixon test
...es for the
> observations you have and determine which values are considered outliers.
>
> Try this simple syntax:
>
> library(outliers)
> library(gamlss.dist)
>
> # this produces a exponential+Gaussian distribution (which usually has
> heaps of outliers!)
> x <- rexGAUS(100,2000,3000,5000)
>
> # this confirms that Dixon works for samples between 3 and 30!!!
> dixon.test(x)
>
> # just to see what the data set looks like and visually confirm the
> outliers
> boxplot(x, notch=T)
>
> # sort the scores in ascending order
> sort(x)
>...
2008 Aug 12
3
dixon test
Hi, I need some help using the R outliers package. I would like to perform a
Q-test (Dixon test) on my data set. I used the dixon.test function, but I
cannot understand what is the confidence level used to perform the test. I
have n=101 (n= number of data). So, can I use directly dixon.test ? What
about qdixon and qtable functions?
thank you so much!
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