Displaying 2 results from an estimated 2 matches for "resulats".
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resultats
2008 Jul 04
1
initialize a matrix
...I've done the following :
VAR<-function(power,length){
for(i in tml:length)){
tvar[i]<-i
pmean[i]<-mean(power[i:i+deltat])
pmin[i]<-min(power[i:i+deltat])
pmax[i]<-max(power[i:i+deltat])
varmax[i]<-100*(pmax[i]-pmean[i])/pmean[i]
varmin[i]<-100*(pmean[i]-pmin[i])/pmean[i]
Resulats<-list(tvar,pmin,pmax,pmean,varmin,varmax)
}}
p.s. tml is a variable which is grater than 0 , deltat is a constant defined
The problem is that tvar is unknown for R.
So I have to initialize tvar,pmean...
Should I create a zero matrix with length of the vector? And how to do it?
Thanks for help...
2008 Jul 04
0
RES: initialize a matrix
...I've done the following :
VAR<-function(power,length){
for(i in tml:length)){
tvar[i]<-i
pmean[i]<-mean(power[i:i+deltat])
pmin[i]<-min(power[i:i+deltat])
pmax[i]<-max(power[i:i+deltat])
varmax[i]<-100*(pmax[i]-pmean[i])/pmean[i]
varmin[i]<-100*(pmean[i]-pmin[i])/pmean[i]
Resulats<-list(tvar,pmin,pmax,pmean,varmin,varmax)
}}
p.s. tml is a variable which is grater than 0 , deltat is a constant defined
The problem is that tvar is unknown for R.
So I have to initialize tvar,pmean...
Should I create a zero matrix with length of the vector? And how to do it?
Thanks for help...