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Hi, I am trying to create 3 mds plots: one with axis 1 vs axis 2, one with axis 2 vs axis 3, and one with axis 1 vs axis 3. When inputting my code, I only end up with one diagram and when inputting mdsg.mds$dims, the program returns 2 for 2 dimensions. How can I create the other two plots? Any help would be greatly appreciated, Calla Carbone The table I use is number of each taxa on each

Hello, I?m trying out the ?resident key? functionality in OpenSSH 8.2, and I?m having trouble getting it to find keys that I?ve created. I?m trying to create a new resident key using: ssh-keygen -O resident -t ed25519-sk -f <filename> This creates a key, but I?m not actually sure it is creating a ?resident? key, as whe...

Hi all Consider the family function, as used by glm. The help page says the value of the family object is a list, one element of which is the following: dev.resids function giving the deviance residuals as a function of (y, mu, wt). But reading any of the family functions (eg poisson) shows that dev.resids is a function that computes the *square* of the deviance residuals (at least, by

# HG changeset patch # User Boris Ostrovsky <boris.ostrovsky@amd.com> # Date 1338309680 -7200 # Node ID 3d52d9fe62559ed6f90cb33a4b95f536ab5bc683 # Parent 53e0571f94e4bcc45270dcbd444c7c91166cef6d xenpm: Fix reporting of C0 residence times Idle state residence times as provided by pmstat_get_cx_stat() are not reported precisely since remote core may be in idle state and therefore has not updated its statistics at the time local core collected them. This causes C0 residencies as calculated by xenpm to sometimes become negati...

An excerpt from dataset ChickWeight: ??? weight Time Chick Diet 1?????? 42??? 0???? 1??? 1 2?????? 51??? 2???? 1??? 1 3?????? 59??? 4???? 1??? 1 I am interested in the residuals of the dataset.? Specifically in saving them to another format. I have been creating text files with sink. CW.lm <- lm(weight ~ Diet, ChickWeight) resid.CW.lm <- resid(CW.lm) But when I call: resid.CW.lm The data

Dear all, I would like to use the residuals in a general linear mixed effect model to diagnose model fit. I know that the resid function has been implemented for linear mixed models but not yet for general linear mixed effects. Is there a way to get them out of lmer fit objects? I tried searching the r-help archive and found nothing. I tried and failed to replicate what (I guessed would be

Dear all, I have three concerns: 1) I am running models with the lme4 package. I cannot find a way to pull out a vector of the fitted values and the residuals. Does anybody know how to do it? 2) How can I nest a random effect variable into a "two-level" fixed effect variable? 3) Suppose I have the following model: y = a + b|c + d + error, where 'a' is a fixed effect, 'c'

x86 pm : provide CC7/PC2 residency Sandy bridge introduces new MSR to get cc7/pc2 residency (core C-state 7/package C-state 2). Print the cc7/pc2 residency when on sandy bridge platform. Signed-off-by: Yang Zhang <yang.z.zhang@intel.com> diff -r 662dbf6ee71c tools/libxc/xc_pm.c --- a/tools/libxc/xc_pm.c Mon Oct 24...

Dear experts, I am trying to create a data frame from the residuals I get after having applied a linear regression to each column of a data frame, but I don't know how to create this data frame from the resulting list since the list has differing numbers of rows. So for example: age<- c(5,6,10,14,16,NA,18) value1<- c(30,70,40,50,NA,NA,NA) value2<- c(2,4,1,4,4,4,4) df<-

Hello there This is the first time I have used r-help message board so I hope I have got the right address. I am trying to check the residuals of a GLMM model(run using the package lme4). I have been able to check the residiuals of REMLs in lme4 using the following: m1<-lmer(vTotal~Week+fCollar+ (1|fCat), collars) res<-resid(m1) plot(res) qqnorm(res) library(MASS) par(mfrow=c(2,3))

...should be able to reach as far as C7. Here is the snipped output of two commands: # xenpm get-cpufreq-states cpu id : 0 total P-states : 11 usable P-states : 11 current frequency : 1600 MHz P0 [2801 MHz]: transition [ 11] residency [ 866 ms] P1 [2800 MHz]: transition [ 1] residency [ 0 ms] P2 [2667 MHz]: transition [ 0] residency [ 0 ms] P3 [2533 MHz]: transition [...

...should be able to reach as far as C7. Here is the snipped output of two commands: # xenpm get-cpufreq-states cpu id : 0 total P-states : 11 usable P-states : 11 current frequency : 1600 MHz P0 [2801 MHz]: transition [ 11] residency [ 866 ms] P1 [2800 MHz]: transition [ 1] residency [ 0 ms] P2 [2667 MHz]: transition [ 0] residency [ 0 ms] P3 [2533 MHz]: transition [...

Hi all- this seems to be simple to figure out but since im new to writing functions I dont know what is happening. Here is my code along with the error I am receiving: semivario=function(data,ids,times,resids){ id=unique(data$ids) index=combinations(length(data$times[data$ids==id[1]]),2) time=gamma=numeric(dim(index)[1]) for (j in 1:dim(index)[1]){

There may be a bug in the anova.glm function. deathstar[32] R R : Copyright 2004, The R Foundation for Statistical Computing Version 2.0.1 (2004-11-15), ISBN 3-900051-07-0 R is free software and comes with ABSOLUTELY NO WARRANTY. You are welcome to redistribute it under certain conditions. Type 'license()' or 'licence()' for distribution details. R is a collaborative project

Hello world, I'm trying to do an anova on data in data.set, dependent variable is a column named "dep.var", grouping variable is in a column called "indep.var", and is.factor(indep.var) is TRUE... why can't I just do aov(dep.var ~ indep.var, data = data.set)? What have I done to deserve this?! What gives? Am I missing something totlly obvious? R-base-1.0.0-1,

On Feb 17, 2020, at 9:45 PM, Damien Miller <djm at mindrot.org> wrote: > On Mon, 17 Feb 2020, Ron Frederick wrote: >> I?m trying out the ?resident key? functionality in OpenSSH 8.2, and >> I?m having trouble getting it to find keys that I?ve created. >> >> I?m trying to create a new resident key using: >> >> ssh-keygen -O resident -t ed25519-sk -f <filename> >> >> This creates a key, but...

Okay, I stumped. I'm trying to build a matrix or data.frame that consists of values by group. For example, resid, group 574 0.536196370873122 E 575 0.93191093696265 E 576 -1.27116094894117 A 577 -1.05159666055027 A 578 0.398273458301184 D 579 0.586373126102573 E 580 0.806575304513802 E 581 0.897258393118338 E 582 0.342393324256838 D 583 0.781245511773227 E I

Dear list, I'm trying to mimic the analysis of Wedderburn (1974) as cited by McCullagh and Nelder (1989) on p.328-332. This is the leaf-blotch on barley example, and the data is available in the `faraway' package. Wedderburn suggested using the variance function mu^2(1-mu)^2. This variance function isn't readily available in R's `quasi' family object, but it seems to me

Hi, among the many (5) methods that I found in the list to do partial correlation in the following two that I had a look I am getting different t-values. Does anyone have any clues on why is that? The source code is below. Thanks. pcor3 <- function (x, test = T, p = 0.05) { nvar <- ncol(x) ndata <- nrow(x) conc <- solve(cor(x)) resid.sd <- 1/sqrt(diag(conc)) pcc <-

I am now getting the occasional complaint about survival routines that are not able to handle big data.?? I looked in the manuals to try and update my understanding of max vector size, max matrix, max data set, etc; but it is either not there or I missed it (the latter more likely).?? Is it still .Machine$integer.max for everything??? Will that change??? Found where? I am going to need to go