Displaying 1 result from an estimated 1 matches for "res10percentnew".
2013 Jun 10
2
please check this
...Percent[which(duplicated(res10Percent)),],dummy==0)
?indx1<-as.numeric(row.names(res10PercentSub1))
indx11<-sort(c(indx1,indx1+1))
indx0<- as.numeric(row.names(res10PercentSub0))
?indx00<- sort(c(indx0,indx0-1))
indx10<- sort(c(indx11,indx00))
?nrow(res10Percent[-indx10,])
#[1] 452
?res10PercentNew<-res10Percent[-indx10,]
?nrow(subset(res10PercentNew,dummy==1))
#[1] 226
?nrow(subset(res10PercentNew,dummy==0))
#[1] 226
?nrow(unique(res10PercentNew))
#[1] 452
A.K.
----- Original Message -----
From: Cecilia Carmo <cecilia.carmo at ua.pt>
To: arun <smartpink111 at yahoo.com>
Cc:...