search for: repetitively

Thank you. Alexei just committed the change to SVN. Regards, Marco Leogrande Sent by a carbon-based life form; hence, it may contain repetitions, inaccuracies, logical fallacies and repetitions. On Wed, Jun 17, 2015 at 2:52 PM, Galina Kistanova <gkistanova at gmail.com> wrote: > LGTM. > Please commit. > > Thanks > > Galina > > On Tue, Jun 16, 2015 at 8:32 PM,

Hi there! I can't find any information about creating combinations with repetitions in R. The function combn() does create combinations, but _without_ repetitions. Here is what I need to do: svIter <- 1000 xx <- matrix(rnorm(m*n), c(m, n)) sequence <- seq(range(xx)[1], range(xx)[2], length.out = svIter^(1/q)) expand.grid(secuence, secuence, .../q times/..., secuence) That is,

Galina, thanks again for your help. I have cooked a new patch that should make a bit more sense. I have added the new builder under _get_experimental_scheduled_builders(), as the comment above that function suggested me it would be a good idea. :) Does it look a reasonable start? Regards, Marco Leogrande Sent by a carbon-based life form; hence, it may contain repetitions, inaccuracies,

Hi, all. I'm using void LoopBase::getExitBlocks (SmallVectorImpl< BlockT * > &ExitBlocks) const to get all exit blocks for a loop. The problem I find with this API is that it returns repetitive basic blocks in certain situations. Should repetitive basic blocks be removed? I have an example to show the problem. Following is the source code and the CFG is enclosed. int main() { int

I recently came to realize the true power of R for statistical analysis -- mainly for post-processing of data from large-scale simulations -- and have been converting many of existing Python(SciPy) scripts to those based on R and/or Perl. In the middle of this conversion, I revisited the problem of curve fitting for simulation data with multiple observations resulting from repetitions. In the

On Apr 19, 2012, at 10:43 PM, xiaoming gu <xiaoming.gu at gmail.com> wrote: > Hi, all. I'm using void LoopBase::getExitBlocks (SmallVectorImpl< BlockT * > &ExitBlocks) const to get all > exit blocks for a loop. The problem I find with this API is that it returns repetitive basic blocks in certain > situations. Should repetitive basic blocks be removed? Users

Hi, This has been asked before but not sufficiently answered from what I could find. How do you create combinations with repetitions (multisets) in R? If I have > set <- array(1:3) And I want to choose all combinations of picking 2 numbers, I want to get a print out like [,1] [,2] [1,] 1 1 [2,] 1 2 [3,] 1 3 [4,] 2 2 [5,] 2 3 [6,] 3 3 subsets(set,

Hello all, I am trying to create a matrix of 1s and -1s without any repetitions for a specified number of columns. e.g. 1s and -1s for 3 columns can be done uniquely in 2^3 ways. -1 -1 -1 -1 -1 1 -1 1 -1 -1 1 1 1 -1 -1 1 -1 1 1 1 -1 1 1 1 and for 4 columns in 2^4 ways and so on. I finally used the function combn([0 1],3) that I found at the following link

Hello Marco, Welcome aboard! slaves.py keeps the build slaves definitions, builders.py keeps the builders definitions. You have to have both. The steps of adding a new slave is here: http://llvm.org/docs/HowToAddABuilder.html. Please make sure you done the step # 10 before bringing your slave up, otherwise it wouldn't be authorized by the master and will be blacklisted after multiple

In a lattice 11x11 with 6 repetitions, we want to compare lines to their two parents. 3 of the 6 repetitions are sprinkled and the 3 others not. There are 5 factors : hm (hydrous mode), variety, block, rep and grandrep. grandrep gathers two repetition, a sprinkled and a not (as in Split Plot !). I use lme but I have problems in random. Can someone help me ? Ibnou DIENG

Just to add a note to the question asked by Bill Simpson.. I am confronted with a similar problem, but the model I try to fit on my data is nonlinear. I have a four-parameter, biexponential model describing the response times of a group of subjects performing a set of task. What I want to evaluate is whether the parameter values differ between (groups of) tasks. myfunc <-formula(x ~

On Tue, 2015-01-06 at 18:51 -0700, Warren Young wrote: > I think we?ll figure out something new to do with computers tomorrow. Certainly by Friday at latest. You seem to forget. Computers were invented to perform repetitive tasks. Computer usage should be serving mankind - not making it more difficult for mankind. -- Regards, Paul. England, EU.

"Didier Dambrin" <didid at skynet.be> wrote: ... > I like FLAC on the paper because of its metadata preservation, in that riff > tag, which is critical for my needs. Try using WavPack, http://www.wavpack.com/ This can losslessly compress 32-bit floating point WAVE-EX files, and faithfully preserves every chunk (which FLAC does not do). It is also free. Regards, Martin --

Dear all, My question concerns using repetitions and simulations (loops?) in R. I am very new R user, so any help that can be offered would be greatly appreciated! I am using fitdistr() to determine the distribution of empirical univariate datasets, and ks.test to assess the goodness of fit. Because the null distribution of the KS statistic is not known when the distribution parameters are

On Aug 7, 2009, at 21:48, Didier Dambrin wrote: > FLAC doesn't preserve every chunk? I thought it did. I only gave a > quick try > but it seemed to have preserved even the most obscure chunks. > Let me check: it even seems to preserve "MIDI note associated to > marker", > which is a very unknown metadata used by SoundForge (& even defined > in a >

Hello, I have a simple (?) simulation problem. I'm doing a simulation with logistic model and I want to reapet it 600 times. The simulation looks like this: z <- 0 x <- 0 y <- 0 aps <- 0 tiss <- 0 for (i in 1:500){ z[i] <- rbinom(1, 1, .6) x[i] <- rbinom(1, 1, .95) y[i] <- z[i]*x[i] if (y[i]==1) aps[i] <- rnorm(1,mean=13.4, sd=7.09) else aps[i] <-

Hello, The following might do it. Without data it's untested. wd <- function(i){ paste0("C:/Awork/geneAssociation/removed8samples/neuhausen7", i, "/seg.pr3.csv") } seg <- lapply(1:5, function(i) { DF <-read.csv(wd(i)) DF$id <- paste0("sn7", i) DF }) seg <- do.call(rbind, seg) row.names(seg) <- NULL Hope this helps,

Hello How can I apply functions along "layers" of a data matrix? Example: daf <- data.frame( 'id' = rep(1:5, 3), matrix(1:60, nrow=15, dimnames=list( NULL, paste('v', 1:4, sep='') )), rep = rep(1:3, each=5) ) The data frame "daf" contains 3 repetitions/layers (rep) of 4 variables of 5 persons (id). For some reason, I want to calculate

This idea is so simple that I'm sure it must have been thought of before, and discarded, since AFAIK it's not used anywhere. I did a quick web search but that didn't turn up much, so I figured I'd put it up for discussion here anyway. How about using large-scale repetition in audio compression? I'm thinking of redundancy in repeated pieces of a song, ie a chorus.

Hi everyone, I am working with Alexei Starovoitov to contribute an LLVM buildbot for the experimental BPF backend. I am following the steps at [1] to setup a buildbot and I was mostly successful: I was able to setup a slave and a temporary master to check its base config. Now I'm not sure about the next step: patching the "slaves.py" and "builders.py" files in zorg. * Is