Displaying 3 results from an estimated 3 matches for "rep_".
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rep
2011 Mar 11
3
Large dataset operations
Hello all,
I'm new to R and trying to figure out how to perform calculations on a large dataset (300 000 datapoints). I have already made some code to do this but it is awfully slow. What I want to do is add a new column for each "rep_ " column where I have taken each value and divide it by the mean of all values where "PlateNo" is the same. My data is in the following format:
> data
PlateNo
Well
rep_1
rep_2
rep_3
1
A01
1312
963
1172
1
A02
10464
6715
5628
1
A03
3301
3257
3281
1
A...
2012 Apr 01
1
Selecting files with a particular string in filename
...t some files from this list of 70 files. The files to be
selected do have a unique "pattern" in their file name. However, I cannot
use list.files function because it looks for a specific path. Any help is
appreciated.
Thanks in advance.
- Kumar
for (i in 1:100) {
name_rep = paste("rep_",i,"_",sep="")
files <- list.files(path="C:\\Users\\Binn\\Desktop\\script_output",
pattern= name_rep, full.names=TRUE )
natfiles <- list.files(path=files, pattern= "_natrain.csv", full.names=TRUE
)
<OPERATIONS HERE>
}
--
Section of Integ...
2014 Mar 26
2
R-devel Digest, Vol 133, Issue 23
...takes a bit of effort to learn (and remember) its syntax.
> This is a problem, since rep is one of the first functions many
> beginners will come across. Of the three main uses of rep, two have
> simpler alternatives.
>
> rep(x, times = ) has rep.int
> rep(x, length.out = ) has rep_len
>
> I think that a rep_each function would be a worthy addition for the
> third use case
>
> rep(x, each = )
>
> (It might also be worth having rep_times as a synonym for rep.int.)
I think this is exactly the wrong approach. Indeed, the aim should be
to get rid of funct...