search for: reoffend

...ue of 'N' if values on certain variables are >= 1 on other variables and assign a 'O' if values on any variable which have a value <= 0. The outcome of this code is to assign a single 'O'. Clearly I have made a mistake somewhere. pre_ <- new <- rep(0, nrow(reoffend)) > pre_ <- new[reoffend$pre01111 | reoffend$pre012 | reoffend$pre013>= 1] <-'V' > pre_ <- new[reoffend$pre02111>=1 | reoffend$pre02114>=1 | reoffend$pre2029>=1 | reoffend$pre0212>=1 | reoffend$pre0211>=1]<- 'V' > pre_ <- new[reoffen...

...is a value of 1 or greater for pre2029 assign a value of 4; everything else = 0. If a case has multiple values, 02111 prevails over 2114, 2114 prevails over 0211, 0211 prevails over 0212; 0212 prevails over 2029. I believe I can generate new variables (1) - (5) using code such as: ASS <- (reoffend$pre02 | reoffend$pre02111 | reoffend$pre02114 | reoffend$pre0211 | reoffend$pre0212 | reoffend$pre029 >= '1') I have three questions: 1. If this is correct, what is the most efficient way to generate (1) without having to type all the variable names. The following does not work: PR...

I am creating a model attempting to predict the probability someone will reoffend after being caught for a crime. There are seven total inputs and I planned on using a logistic regression. I started with a null deviance of 182.91 and ended up with a residual deviance of 83.40 after accounting for different interactions and such. However, I realized after that my code is diffe...