search for: renny

...e coding "c==abs(bb+52)" is just the same from the 3line in the top, why 2 different results? HOWEVER, it is not repeatable, I am glad I did not close the window. Also, > c<-0.5-0.1 > n<-0.6-0.2 > n==c [1] FALSE So, is "==" comparing formula or result? Thanks, Renny [[alternative HTML version deleted]]

Hi, there I am a grad student struggling to get my syntax right in a model I am building in R. I am trying to specify a variable,W, in a loop, such that on the first iteration, it is equal to Wo, my starting value, which I have already specified with Wo<-9.2 On any other iteration other than the first, I want W to equal the previous value of W in the iteration. plus an increment from

Hi, there I first sent this e-mail a couple months ago, to no avail.Since I am not a member on your mailing list, so could you please cc: a response to me? I'll be sure to check the list today for replies. I am currently attempting to perform an ANOVA with both nested and normal factors. My problem is that R is treating my nested factors the exact same way as it would interaction terms.

Hi there, I've hit a bump in writing postscript files with special characters in the WinAnsi encoding on a windows machine. Here's some sample code: ########################################### postscript(file = "test.eps", encoding="WinAnsi.enc", width = 3, height = 5.5, onefile = TRUE, horizontal=FALSE, family = "sans", title =

Hi gang, I'm perplexed- I have some code that uses for() loops that works fine in R version 2.8 on my mac, worked fine in version 2.8 on my old windows machine, but doesn't work in version 2.10 on windows. The loop implements a function over a data frame (code is included below). In Mac (running version 2.8), the results of the loop are what I expect: > p_unadj [1] 0.034939481

Hi there, I'm sure there's an easy answer to this, and I can't wait to see it. The question: is there an easy way to sort a data frame by it's row names? My dilemma: I've had to pull apart a data frame, run it through a loop to do some calculations and generate new variables, and then re-construct the chunks back into a data frame at the end. Doing this preserves the row

Hi, there I am trying to replicate an error message in subset() to see what it is that I'm doing wrong with the datasets I am trying to work with. Essentially, I am trying to pass a string vector to subset() in order to select a specific collection of cases (i.e., I have data for these cases in one table, and want to select data from another table that match up with the cases in the

Hi all, In the last couple of months, there have been two proposed patches for the regain play analysis code. The first by Nathan Rennie-Waldock: http://lists.xiph.org/pipermail/flac-dev/2011-December/003070.html simply adds some more higher sample rates. The second by Earl Chew: http://lists.xiph.org/pipermail/flac-dev/2012-January/003067.html is more comprehensive. Neither of the

Hi there, I just wanted to take a quick second to thank everyone who maintains this service- just in case you don't hear it enough, there are a plethora of people who rely on this service (as evidenced by the help archives), and even if they don't say it, are greatly thankful for what you do here. Not only are you providing a service to people who are learning R, but indeed helping

Hi there, Does anyone know how to extract elements from the table returned by Manova()? Using the univariate equivalent, Anova(), it's easy: a.an<-Anova(lm(y~x1*x2)) a.an$F This will return a vector of the F-values in order of the terms of the model. However, a similar application using Manova(): m.an<-Manova(lm(Y~x1~x2)) m.an$F Returns NULL. So does any attempt at calling the

Hi there, Does anyone know how I solve for x from a given y in a polynomial function? Here's some example code: ##example file a<-1:10 b<-c(1,2,2.5,3,3.5,4,6,7,7.5,8) po.lm<-lm(a~b+I(b^2)+I(b^3)+I(b^4)); summary(po.lm) (please ignore that the model is severely overfit- that's not the point). Let's say I want to solve for the value b where a = 5.5. Any thoughts? I did

Hi, there I'm currently trying to figure out how to keep my "factor" levels for a variable when moving it from one data frame or matrix to another. Example below: vec1<-(rep("10",5)) vec2<-(rep("30",5)) vec3<-(rep("80",5)) vecs<-c(vec1, vec2, vec3) resp<-rnorm(2,15) dat<-as.data.frame(cbind(resp, vecs))

Hi, My question is how do I gain control over what values the X and Y axis show. Below is a sample plot I have made and want the X axis to represent a time vector with values taking the form Q1.60, Q2.60, Q3.60...Q1.90..etc...Currently the X axis starts with value 0 and increases by 1 through the end of the sample. win.graph() matplot(v.0,log.diff.v.6,type="l",lty=1, col=2,

Hi, there I have a loop that is producing data, but is also generating an error message that I can't understand. Here's the loop and the error message: > bio<-matrix(NA, ncol=9, nrow=366) > W<-NULL > M<- length(Day) #number of days iterated > > for (i in 1:M) + { + + + if (Day[i]==1) W[i] <- Wo else W[i] <- (W[i-1]+(Gr[i]/Ef)) + + + C<-

Hi, there I am quite sure there is an easy answer to this, but I am unsure how to gather a bunch of t-statistics in an organized format. I am trying to generate a list of t-statistics for a randomization routine. If I try to collect a bunch of t-statistics from a run, this is what happens: > M <- 10 ; simt <- NULL > for(i in 1:M) + { + perm<-sample(site,replace=F) + +

Hi, there I tried this post on R-help but did not generate any replies, so I thought I might try the waters here since it's a more programming-based group. I have written a function that will allow me to calculate the variance components for a model II (random effects) single factor ANOVA (perhaps this is me re-inventing the wheel, but I handn't yet come across anything in R that does

Hi all, Does anyone have any tips for extracting chunks of data from a distance matrix? For instance, if one was interested in only a subset of distance comparisons (i.e., that of rows 4 thru 6, and no others), is there a simple way to pull that data out? >From some playing around with an example (below), I've been able to figure out that a distance matrix in R is stored as a single

Hi there I thought this would be of particular interest to people using 'optim' functions and perhaps people involved with R development. I've been beaten down by R trying to get it to perform an optimization on a mass-balance model. I've written the same program in excel, and using the 'solver' function, it comes up with an answer for my variables (p, ACT, which

Hi there I am having trouble figuring out how to get an nlm function to report estimates for two parameter values in an estimation. The way I've got it goes something like this: f <- function (q, r) { here, I have a second loop which uses q, r to give me values for c, d below. a and b are already specified; this loop is a mass-balance function where I am trying to find values of q,

Hi, all I have a rather un-ideal dataset that I am trying to work with, and would appreciate any advice you have on the matter. I have 4 years worth of data taken at 3 depth-zones from which samples have been taken at random. I am looking at the abundance of organism A between depth zones and across years, and am interested in the possible interaction of organism A distributions shifting