search for: remkoduursma

...o ------------------------------------------------- Remko Duursma Research Lecturer Centre for Plants and the Environment University of Western Sydney Hawkesbury Campus Richmond NSW 2753 Dept of Biological Science Macquarie University North Ryde NSW 2109 Australia Mobile: +61 (0)422 096908 www.remkoduursma.com

...E and keep.source=TRUE, but neither seem to affect this behavior. thanks, Remko ------------------------------------------------- Remko Duursma Research Lecturer Hawkesbury Institute for the Environment University of Western Sydney Hawkesbury Campus, Richmond Mobile: +61 (0)422 096908 www.remkoduursma.com

...------------------------------------------------- Remko Duursma Post-Doctoral Fellow Centre for Plants and the Environment University of Western Sydney Hawkesbury Campus Richmond NSW 2753 Dept of Biological Science Macquarie University North Ryde NSW 2109 Australia Mobile: +61 (0)422 096908 www.remkoduursma.com

...e g is not called. The code compiled as executable works fine. thanks, Remko ------------------------------------------------- Remko Duursma Research Lecturer Centre for Plants and the Environment University of Western Sydney Hawkesbury Campus Richmond NSW 2753 Mobile: +61 (0)422 096908 www.remkoduursma.com

...o ------------------------------------------------- Remko Duursma Research Lecturer Centre for Plants and the Environment University of Western Sydney Hawkesbury Campus Richmond NSW 2753 Dept of Biological Science Macquarie University North Ryde NSW 2109 Australia Mobile: +61 (0)422 096908 www.remkoduursma.com

length(unique(c(1,2,2)))==length(c(1,2,2)) I use the above test to test if all the elements in a vector are unique. But I'm wondering if there is a convenient function to do so in R library.

I believe I have found a bug (or at least a misfeature) in plot.POSIXct. See the following example code. set.seed(1) x=seq(1,1e8,length=100)+round(runif(100)*1e8) y=as.POSIXct(x,origin="2001-01-01") plot(y) This plots some random (date)times against their indices. The y axis correctly shows appropriate values (years), but the x axis contains the single number '59:58' in the

...------------------------------------------------- Remko Duursma Post-Doctoral Fellow Centre for Plants and the Environment University of Western Sydney Hawkesbury Campus Richmond NSW 2753 Dept of Biological Science Macquarie University North Ryde NSW 2109 Australia Mobile: +61 (0)422 096908 www.remkoduursma.com

...2.794 loaded via a namespace (and not attached): [1] grid_2.12.0 tools_2.12.0 ------------------------------------------------- Remko Duursma Research Lecturer Centre for Plants and the Environment University of Western Sydney Hawkesbury Campus Richmond NSW 2753 Mobile: +61 (0)422 096908 www.remkoduursma.com

...is there a more appropriate method? Thanks a lot for any help. greetings, Remko ------------------------------------------------- Remko Duursma Research Lecturer Hawkesbury Institute for the Environment University of Western Sydney Hawkesbury Campus, Richmond Mobile: +61 (0)422 096908 www.remkoduursma.com

...ith excluding the NAs myself - but thats not so elegant!) Thanks, Remko Duursma ##################################### Remko A. Duursma, Ph.D. student Forest Biometrics Lab / Idaho Stable Isotopes Laboratory Department of Forest Resources University of Idaho - College of Natural Resources Email: remkoduursma at yahoo.com Tel: (208)-885-5165 _____________________________________________________________ Get 25MB, POP3, Spam Filtering with LYCOS MAIL PLUS for $19.95/year. http://login.mail.lycos.com/brandPage.shtml?pageId=plus&ref=lmtplus

Dear R-helpers, I have two problems that I don't know how to vectorize (but would like to because my current solution is slow). # 1. #I have a vector x: x <- c(3, 0, 1, 0, 2, 2, 2, 0, 4, 2) #I want this translated into a new vector based on x,so that each element of x #is the number of zeroes, followed by a 1. The new vector would look like: #> r# [1] 0 0 0 1 1 0 1 1 0 0 1 0 0

Hi, Time for another of my "newbie" questions. Is it possible to build up a data.frame "row by row" as I go I'm going to be running a bunch of experiments (many in a loop) to test different things. I'm using AUC as my main performance measure. My thought was to add a row to a data.frame for each iteration and then have a nice summary report at the end. I found

It seems that an vector or other non elemental data type can not be assigned to an element in the data.frame. I'm wondering what is the walk around. > li=data.frame(a=c(0,1), b=c('x','y')) > li$b[[1]]= 'x' > li$b[[2]]<- c('y','z') Error in li$b[[2]] <- c("y", "z") : more elements supplied than there are to replace

Dear R-helpers, I have a function that adds some segments to the current plot, but if I the current plot is made with any of the lattice functions (in my case, levelplot), I should use lsegments rather than segments. How can I tell if the current device was made with plot() or e.g. levelplot() or another lattice function? dev.cur() does not help me, it just tells me "windows 2".

Dear R-helpers, I have a problem converting an object made with the 'chron' function to a POSIXct object: # Make date based on DOY dat <- chron(dates=232, origin.=c(month=1, day=1, year=2008)) dat #[1] 08/20/08 # Converting to POSIXct uses current timezone (Sydney): as.POSIXct(dat) #[1] "2008-08-20 10:00:00 EST" # Setting GMT timezone has no effect? as.POSIXct(dat,

...------------------------------------------------- Remko Duursma Post-Doctoral Fellow Centre for Plants and the Environment University of Western Sydney Hawkesbury Campus Richmond NSW 2753 Dept of Biological Science Macquarie University North Ryde NSW 2109 Australia Mobile: +61 (0)422 096908 www.remkoduursma.com

Dear all, I tried to build a package from source, and ran into a problem. >R CMD build RQDA * checking for file 'RQDA/DESCRIPTION' ... OK * preparing 'RQDA': * checking DESCRIPTION meta-information ... OK ERROR copying to build directory failed I searched and found this http://r.789695.n4.nabble.com/tar-problem-when-using-R-CMD-build-on-Windows-td2734636.html > SET

Dear list, can someone explain to me why deparse(substitute(x)) does not seem to work when x is of a user-defined S3 class? In my actual problem, my print method is part of a package, and the method is registered in the NAMESPACE, if that should make a difference. > print.testclass <- function(x,...){ xname <- deparse(substitute(x)) cat("Your object name

I've built a package that contains only two functions for a test run. They are: g <- function(x){ x <- x^2 class(x) <- "foo" x } print.foo <- function(x, ...){ cat("This is a test:\n") cat(x, "\n") invisible(x) } Simply testing these functions in the R workspace prior to a build yields: > g(1:5) This is a test: 1 4 9 16 25 Now, I