search for: reith

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2012 Jul 20
6
Speeding up a loop
General problem: I have 20 projects that can be invested in and I need to decide which combinations meet a certain set of standards. The total possible combinations comes out to 2^20. However I know for a fact that the number of projects must be greater than 5 and less than 13. So far the the code below is the best I can come up with for iteratively creating a set to check against my set of
2012 Jul 20
0
[External] Re: Speeding up a loop
"Reith, William [USA]" <reith_william@bah.com> wrote on 07/20/2012 09:52:02 AM: > Would this matrix eat up memory making the rest of my program > slower? Each x needs to be multiplied by a matrix and the results > checked against a set of thresholds. Doing them one at a time takes...
2011 May 04
1
Str info. Thanks for helping
...tor() Or something like SA[["Response IPS1"]]["as.factor(WSD)",] ## to select the first row only, even maybe with unlist() Without a better REPRODUCIBLE example, I cannot tell more (maybe some others can, that's why I reply to the list) HTH, Ivan Le 4 mai 2011 ? 20:17, reith_william at bah.com a ?crit : > I am still waiting for this to get posted so I thought I would email it to you. > > SA gives the output: > > Response IPS1 : > Df Sum Sq Mean Sq F value Pr(>F) > as.factor(WSD) 3 3.3136 1.10455 23.047 5.19e-12 ***...
2011 Jul 12
4
qplot and for loops
I have 4 columns and 56 rows of made up data that I want to plot as a series of bar graphs. The idea is to create one bar graph for each of the 4 columns using a for loop. I tried the following command in RStudio and when I type x in the console I get just the 4th graph instead of all four graphs. I did not define what x is before hand. I was not sure what it would be. Any suggestions on how you