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ratioscore
2007 Jun 27
1
how to use chi-square to test correlation question
...he null hypothesis is score is not correlated with gender. and we can also say
the null hypothesis is boys are the same smart as girls.
the alternative hypothesis is that boys are significantly smarter than girls.
boyscore=c(31,32,33,34,35,36,37,38,39,40)
girlscore=c(10,10,10,10,10,10,10,10,10,10)
ratioscore=boyscore/girlscore;
expratio=300/100; #300 boy students and 100 girl students
chisq=sum((expratio-ratioscore)^2/expratio)
df=9
pvalue=1-pchisq(chisq,df)
Since the pvalue (0.9984578) is greater than significance level (0.05), we cannot
reject the null hypothesis. Therefore the conclusion is tha...