search for: ramgad82

Displaying 12 results from an estimated 12 matches for "ramgad82".

2012 Sep 17
6
count NAs per week
Even though I work with R since a year or so I still struggle with simple problems. I hope someone can help me with this. Been trying for days and am a little frustrated now. I have a data frame somewhat like the one bellow: dattrial<-data.frame(a=c(1,NA,rnorm(4,10)), Week=c(3,3,3,4,4,4)) I want to know how many NAs I have in week 3 and in week 4. -- View this message in context:
2017 Aug 19
0
My very first loop!! I failed. May I have some start-up aid?
[answers inline] On 18 August 2017 at 20:08, Dagmar <Ramgad82 at gmx.net> wrote: > > myframe<- data.frame (ID=c("Ernie", "Ernie","Ernie","Ernie"), > Timestamp=c("24.09.2012 08:00", "24.09.2012 09:00", "24.09.2012 10:00", > "25.09.2012 10:00"), Longitude=c("8...
2012 Oct 25
2
mean of a value of the last 2 hours
Hello, I have a data frame somewhat like that: myframe <- data.frame (ID=c("Ernie", "Ernie", "Ernie", "Bert", "Bert", "Bert"), Timestamp=c("24.09.2012 09:00", "24.09.2012 10:00", "24.09.2012 11:00"), Hunger=c(1,1,1,2,2,1) ) myframestime <- as.POSIXct (strptime(as.character(myframe$Timestamp),
2012 Nov 27
5
loop with date
Hello, I tried to construct my very first loop today and completly failed :-( Maybe someone can help me? I have a dataframe somewhat like this one: myframe <- data.frame (Timestamp=c("24.09.2012 09:00", "24.09.2012 10:00", "24.09.2012 11:00", "25.09.2012 09:00", "25.09.2012 10:00", "25.09.2012
2012 Oct 26
0
mean of a value of the last 2 hours using plyr (Thank you)
...ame2 > ddply(myframe2,.(ID),summarise,Last2=mean(tail(Hunger,2))) > Felipe D. Carrillo > Supervisory Fishery Biologist > Department of the Interior > US Fish & Wildlife Service > California, USA > http://www.fws.gov/redbluff/rbdd_jsmp.aspx > > *From:* Tagmarie <Ramgad82@gmx.net> > *To:* r-help@r-project.org > *Sent:* Thursday, October 25, 2012 7:35 AM > *Subject:* [R] mean of a value of the last 2 hours > > Hello, > I have a data frame somewhat like that: > > myframe <- data.frame (ID=c("Ernie", &quot...
2012 Nov 09
3
if between 500-600 give 550
I have a data frame somewhat like this: myframe <- data.frame (ID=c(2,3,4,5), Hunger =c(415,452,550,318 )) myframe Now I would like to add a column to the right which summarizes the values for Hunger somewhat to reduce the number of values: If the values for Hunger are between 300-400 I would like to insert the number 350, between 400-500 insert 450 between 500-600 insert 550 Does
2017 Aug 19
4
My very first loop!! I failed. May I have some start-up aid?
Dear all, I have a data similar to this: myframe<- data.frame (ID=c("Ernie", "Ernie","Ernie","Ernie"), Timestamp=c("24.09.2012 08:00", "24.09.2012 09:00", "24.09.2012 10:00", "25.09.2012 10:00"), Longitude=c("8.481","8.482","8.483","8.481"),
2012 Jun 16
3
count data without NA in certain time intervals and plot it
Hello, I'm quite new to R and still spend hours trying to figure out single things so I hope nobody rolls his eyes over my question. I have a data set over time and converted it to the POSTIXct format. I added a column in the data set for the week and the month. I try to get a plot which shows the weeks on the x-axis and the number of datasets without NAs on the y-axis. That doesn't
2012 Dec 07
0
apply a function at: dateX, dateX+1, dateX+2, ....
Dear knowing people, Dennis Murphy helped me a lot with my first loop last week. Thanks again - I could have made more than 10 "Thank-You cakes" in the time it saved me! But now I want to complicate the thing. My ideas didn't work. Let's see if anyone is smarter ;-) The following packages are needed: library(adehabitatHR) library(rgdal) library(plyr) # My dataframe looks
2017 Jun 30
0
Unit of cellsize in 'ascgen' from adehabitatMR? Spatialpoints unit?
Hello dear all, A simple understanding question but I cannot find the answer anywhere. I use coordiates (longitude, latitude) in my study. I created a SpatialPoints class from those data and then I created a grid using the 'ascgen' command in the package 'adehabitatMR' like: ascgen(xy,cellsize=40). It worked out fine and my analysis is doing great. But I don't know what
2012 Dec 17
2
calculate a "rolling mean" including standard deviation
Hello everyone, I have a data frame somewhat like this one: myframe <- data.frame (Timestamp=c( "24.09.2012 06:00", "24.09.2012 07:00", "24.09.2012 08:00", "24.09.2012 09:00", "24.09.2012 10:00", "24.09.2012 11:00", "24.09.2012 12:00",
2012 Sep 26
2
average environmental data if AnimalID and Time is duplicated
Hello, I tried for about three hours now to solve this problem but I can't figure it out. I am sure someone knows how do it. At least I hope so. I have a data frame somewhat like this: myframe <- data.frame (ID=c("Ernie", "Ernie", "Bert", "Bert"), Timestamp=c("24.09.2012 09:00", "24.09.2012 09:00", "24.09.2012 10:00",