search for: rahiz

...[[2]] V1 V2 V3 [1,]10 11 12 [2,]13 14 15 [3,]16 17 18 [[3]] V1 V2 V3 [1,]19 20 21 [2,]22 23 24 [3,]25 26 27 how do i extract elements in each file so that after transpose, it looks something like the following; 1 10 19 2 11 20 3 12 21 and so on.. Thanks.. -- Muhammad Rahiz | Doctoral Student in Regional Climate Modeling Climate Research Laboratory, School of Geography & the Environment Oxford University Centre for the Environment South Parks Road, Oxford, OX1 3QY, United Kingdom Tel: +44 (0)1865-285194 Mobile: +44 (0)7854-625974 Email: muhammad.rahiz at...

...which is OK for a set of test data but not for my actual dataset. At the moment, I'm thinking of something in the lines of a for loop function i.e. for (i in ...){ statement... } Is there a syntax in the for loop that allows me to select the column/row in the file? Thanks. -- Muhammad Rahiz | Doctoral Student in Regional Climate Modeling Climate Research Laboratory, School of Geography & the Environment Oxford University Centre for the Environment South Parks Road, Oxford, OX1 3QY, United Kingdom Tel: +44 (0)1865-285194 Mobile: +44 (0)7854-625974 Email: muhammad.rahiz at...

...le1 File2 File3 1 1 1 4 4 4 7 7 7 2 2 2 5 5 5 8 8 8 3 3 3 6 6 6 9 9 9 I want to calculate the standard deviation for every cell in the file (I'm using gridded data). The desired output is Output 3 3 3 3 3 3 3 3 3 Thanks. Muhammad -- Muhammad Rahiz | Doctoral Student in Regional Climate Modeling Climate Research Laboratory, School of Geography & the Environment Oxford University Centre for the Environment South Parks Road, Oxford, OX1 3QY, United Kingdom Tel: +44 (0)1865-285194 Mobile: +44 (0)7854-625974 Email: muhammad.rahiz at...

...V1 V2 V3 [1,] 1 1 1 [2,] 2 2 2 [3,] 3 3 3 [[2]] V1 V2 V3 [1,] 4 4 4 [2,] 5 5 5 [3,] 6 6 6 [[3]] V1 V2 V3 [1,] 7 7 7 [2,] 8 8 8 [3,] 9 9 9 The moving average is to be performed on 1,4,7 = (1+4)/2 , (4+7)/2 2,5,8 = .. 3,6,9 = .. Thanks Muhammad -- Muhammad Rahiz | Doctoral Student in Regional Climate Modeling Climate Research Laboratory, School of Geography & the Environment Oxford University Centre for the Environment, University of Oxford South Parks Road, Oxford, OX1 3QY, United Kingdom Tel: +44 (0)1865-285194 Mobile: +44 (0)7854-625974 Email: m...

...s is the main problem. How do I make the data in Excel's Column C in R? Or in other words, how do I update the result of the conditional statements into the dummy file, d, which I created (which apparently didn't work). I hope my explanation makes sense. thanks. Muhammad -- Muhammad Rahiz | Doctoral Student in Regional Climate Modeling Climate Research Laboratory, School of Geography & the Environment Oxford University Centre for the Environment, University of Oxford South Parks Road, Oxford, OX1 3QY, United Kingdom Tel: +44 (0)1865-285194 Mobile: +44 (0)7854-625974 Email: mu...

...e1.txt", "file2.txt", "file3.txt") for (i in 1:3){ # where 3 is the number of files file[[i]] <- file[[i]] * 3 # just a simple calculation to multiply the matrix by 3 write.table(file[[i]],out[i], row.names=FALSE, col.names=FALSE) } Thanks. -- Muhammad Rahiz | Doctoral Student in Regional Climate Modeling Climate Research Laboratory, School of Geography & the Environment Oxford University Centre for the Environment South Parks Road, Oxford, OX1 3QY, United Kingdom Tel: +44 (0)1865-285194 Mobile: +44 (0)7854-625974 Email: muhammad.rahiz at...

...nction(x){ eval.parent(substitute(x <- x + 1)) print(x) } How do I apply it in a loop on my test dataset, x1, so that the procedure becomes x1[c(1:2)] x1[c(2:3)] x1[c(3:4)] where x1 = > m <- matrix(1:3,3,3) > x1 <- list(m, m+1, m+2, m+3, m+4) Thanks. Muhammad -- Muhammad Rahiz | Doctoral Student in Regional Climate Modeling Climate Research Laboratory, School of Geography & the Environment Oxford University Centre for the Environment South Parks Road, Oxford, OX1 3QY, United Kingdom Tel: +44 (0)1865-285194 Mobile: +44 (0)7854-625974 Email: muhammad.rahiz at...

...location R_X86_64_32 against `.rodata' can not be used when making a shared object; recompile with -fPIC /usr/local/lib/libnetcdf.a: could not read symbols: Bad value collect2: ld returned 1 exit status make: *** [ncdf.so] Error 1 ERROR: compilation failed for package ?ncdf? * removing ?/home/rahiz/R/x86_64-redhat-linux-gnu-library/2.13/ncdf? The downloaded packages are in ?/tmp/Rtmp5khIxy/downloaded_packages? Warning message: In install.packages("ncdf") : installation of package 'ncdf' had non-zero exit status

...file))/c d2[[i]] <- file[[i]] - mean Apparently, the following command is the source of the error. d2[[i]] <- file[[i]] - mean It works OK when I typed into the terminal the following after running the script. > for (j in 1:3) print (file[[j]]-mean) Thanks. Muhammad -- Muhammad Rahiz | Doctoral Student in Regional Climate Modeling Climate Research Laboratory, School of Geography & the Environment Oxford University Centre for the Environment South Parks Road, Oxford, OX1 3QY, United Kingdom Tel: +44 (0)1865-285194 Mobile: +44 (0)7854-625974 Email: muhammad.rahiz at...

...39;d like to perform arithmetic functions on 1000 files containing a 2000x2000 matrix. Can anyone advise? For example, File1 File2 Output 1 1 1 4 4 4 5 5 5 2 2 2 + 5 5 5 = 7 7 7 3 3 3 6 6 6 9 9 9 Muhammad -- Muhammad Rahiz | Doctoral Student in Regional Climate Modeling Climate Research Laboratory, School of Geography & the Environment Oxford University Centre for the Environment South Parks Road, Oxford, OX1 3QY, United Kingdom Tel: +44 (0)1865-285194 Mobile: +44 (0)7854-625974 Email: muhammad.rahiz at...

Hi, Can someone advise why the followind did not produce the array, given the condition specified? s <- 1 a1 <- array(dim=c(1,4)) a2 <- array(dim=c(2,4)) arr <- ifelse(s==0,a1,a2) Thanks. Muhammad

Hi all, I'm trying to get the min and max of a sequence of number using a loop like the folllowing. Can anyone point me to why it doesn't work. Thanks. type <- c("min","max") n <- 1:10 for (a in 1:2) { print(type[a](n)) } -- Muhammad

Hi all, I have a list of 20000 data, and the list look like below. I wonder what is the simplest way to extract 'kappa' value (or 'xi' or 'alpha' for the matter) from each of the data. How can I simply code it without having to change the list to a dataframe first? Many thanks! $X19997 xi alpha kappa 784.7718640 165.4065141 -0.2709599 $X19998

Hi all, I would like to get the array index for a range of values, say 0 < x < 1.5. I'm wondering if there is an alternative for the following which I've done x0 <- rnorm(100) x1 <- ifelse(x0 > 0 & x0 < 1.5,"t","f") x2 <- which(x1=="t",arr.ind=TRUE) x0[x2] Thanks. -- Muhammad

Hi all, I'm trying to get the value of y when x=203 by using the intersect of three curves. The horizontal curve does not meet with the other two. How can I rectify the code below? Thanks Muhammad ts <- 1:10 dd <- 10:1 ts <- seq(200,209,1) dd <- c(NA,NA,NA,NA,1.87,1.83,1.86,NA,1.95,1.96) plot(ts,dd,ylim=c(1.5,2)) abline(lm(dd~ts),col="blue",lty=2)

...<- lapply(list, read.table) mean <- (Reduce("+", file))/3 } When I call > objects() > list [1] "2006.01.txt.h" "2006.02.txt.h" "2006.12.txt.h" The listed files are the last files in the sequence. Am I doing the loop correctly? -- Muhammad Rahiz | Doctoral Student in Regional Climate Modeling Climate Research Laboratory, School of Geography & the Environment Oxford University Centre for the Environment South Parks Road, Oxford, OX1 3QY, United Kingdom Tel: +44 (0)1865-285194 Mobile: +44 (0)7854-625974 Email: muhammad.rahiz at...

Does anyone have the code to calculate the drought severity index? -- Muhammad Rahiz | Doctoral Student in Regional Climate Modeling Climate Research Laboratory, School of Geography & the Environment Oxford University Centre for the Environment, University of Oxford South Parks Road, Oxford, OX1 3QY, United Kingdom Tel: +44 (0)1865-285194 Mobile: +44 (0)7854-625974 Email: m...

Hello all, I'm trying to create a 2x2 matrix, 32 times after unlist() so that I can convert the list to matrix. I've looked through the R archive but couldn't find the answer. There is what I've done. > f <- system("ls *.txt", intern=TRUE) > x <- lapply(f, read.table) > x [[1]] V1 V2 1 -27.3 14.4 2 29.0 -38.1 [[2]] V1 V2 1 14.4

...means the condition has length > 1 and only the first element will be used The problem is solved if I use the ifelse function but I want to specify the code as following; if (/condition/) { /statement 1a statement 1b /} else { /statement 2a statement 2b /} Thanks. Muhammad -- Muhammad Rahiz | Doctoral Student in Regional Climate Modeling Climate Research Laboratory, School of Geography & the Environment Oxford University Centre for the Environment South Parks Road, Oxford, OX1 3QY, United Kingdom Tel: +44 (0)1865-285194 Mobile: +44 (0)7854-625974 Email: muhammad.rahiz at...

Hi all, I have a file, say, test.txt, which contains the following information. I'm trying to read in the file and specifying the missing values as NA so that each column has the same number of rows. I've tried all sorts of manipulation but to no avail. r1 r2 r3 1 3 2 3 3 2 3 4 2 3 5 2 3 6 2 3 7 2 8 2 9 2 3 The output should be r1 r2 r3 1 NA 3 2 NA 3 3 2 3 4 2 3 5 2 3 6 2 3 7 2