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Hello, When I try to to obtain the expected risk for a new dataset using coxph in the survival package I get an error. Using the example from ?coxph: > test1 <- list(time= c(4, 3,1,1,2,2,3),+ status=c(1,NA,1,0,1,1,0),+ x= c(0, 2,1,1,1,0,0),+ sex= c(0, 0,0,0,1,1,1))> cox<-coxph( Surv(time, status) ~ x + strata(sex), test1)

Hi list, I was trying to use "predict.coxph" to calculate martingale residuals on a test data, however, as pointed out before http://tolstoy.newcastle.edu.au/R/e4/help/08/06/13508.html predict(mycox1, newdata, type="expected") is not implemented yet. Dieter suggested to use 'cph' and 'predict.Design', but from my reading so far, I'm not sure they can

...org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ------------------------------ Message: 21 Date: Mon, 22 Nov 2010 08:11:15 -0600 From: Terry Therneau <therneau at mayo.edu> Cc: r-help at r-project.org, dieter.menne at menne-biomed.de, r_tingley at hotmail.com Subject: Re: [R] calculating martingale residual on new data using "predict.coxph" Message-ID: <1290435075.7350.3.camel at punchbuggy> Content-Type: text/plain This feature has been added in survival 2.36-1, which is now on CRAN. (2.36-2 should appear in another da...

I want to take the first row of each unique ID value from a data frame. For instance > ddTable <- data.frame(Id=c(1,1,2,2),name=c("Paul","Joe","Bob","Larry")) I want a dataset that is Id Name 1 Paul 2 Bob > unique(ddTable) Will give me all 4 rows, and > unique(ddTable$Id) Will give me c(1,2), but not accompanied by the name column.