Displaying 1 result from an estimated 1 matches for "quandi".
Did you mean:
quand
2009 Aug 05
2
using ddply but preserving some of the outside data
I have a bit of a quandy. I'm working with a data set for which I
have sampled sites at a variety of dates. I want to use this data,
and get a running average of the sampled values for the current and
previous date.
I originally thought something like ddply would be ideal for this,
however, I cannot break up my data by date, and then apply a function
that requires information