search for: qrs

Dear All I would need to generate differences between variates such as nam1<-nam2-nam3 in the following loop: for(i in c("13","26","38")) { for (j in c("HR","PQ","QRS","QT")){ nam1<-paste("d",j,i,sep="") nam2<-paste(j,i,sep=".") nam3<-paste(j,"0",sep=".") cat(nam1,"\n") cat(nam2,"\n") cat(nam3,"\n") }} for exam...

...el is adequate? For instance, I do the following: ami <- read.table(file = "http://www.public.iastate.edu/~maitra/stat501/datasets/amitriptyline.dat", col.names=c("TCAD", "drug", "gender", "antidepressant","PR", "dBP", "QRS")) ami$gender <- as.factor(ami$gender) ami$TCAD <- ami$TCAD/1000 ami$drug <- ami$drug/1000 library(car) fit.lm <- lm(cbind(TCAD, drug) ~ gender + antidepressant + PR + dBP + QRS, data = ami) fit.manova <- Manova(fit.lm) fit1.lm <- update(fit.lm, .~ . - PR - dBP - QRS)...

I'm not sure if the following is a bug or a feature: > jjmat <- array(1:6, c(2,3), list(c('ABC', 'DEF'), c('xyz', 'tuv', 'qrs'))) > jjdf <- as.data.frame(jjmat) > jjmat['AB', ] Error: subscript out of bounds > jjdf['AB',] xyz tuv qrs ABC 1 3 5 > jjmat[, 'tu'] Error: subscript out of bounds > jjdf[, 'tu'] Error in "[.data.frame"(jjdf, , "tu...

Hi, How to get all list item to one string variable. example a[1]="abc" b[1]="def" output="abc def" Thanks B.Purushothaman -- View this message in context: http://r.789695.n4.nabble.com/How-to-get-all-list-item-to-one-string-variable-tp4636283.html Sent from the R help mailing list archive at Nabble.com.

Dear all, I'm trying to improve the documentation I provide my R packages, and to that end I'd like to find out what you think is great R documentation. I'm particularly interested in function documentation, but great vignettes, websites or book are also of interest. What is your favourite bit of R documentation, and why? Thanks, Hadley

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