search for: q3

InDATA <-read.table("C:/Data/May 2004/season.txt",header=T) X <- decompose(InDATA) print(X) Period Connections Q1 67519 Q2 69713 Q3 68920 Q4 69452 Q1 70015 Q2 59273 Q3 57063 Q4 65596 Q1 73527 Q2 58586 Q3 69522 Q4 60091 Q1 51686 Q2 63490 Q3 55702 Q4 53200 Q1 51033 Q2 48175 Q3 52709 Q4 50106 Q1 50855 Q2 43466 Q3 48190 Q4 41702 Q1 48747 Q2 51441 Q3 42537 Q4 49145 Q1 41457 Q2 39306 Q3 43121 Q4 42777 Q1...

sample report data that i want to forecast quarter quarter_index Revenue 2007 Q1 1 $3,856,799 2007 Q2 2 $4,243,328 2007 Q3 3 $4,930,369 2007 Q4 4 $5,443,579 2008 Q1 5 $5,164,830 2008 Q2 6 $5,104,413 2008 Q3 7 $5,713,240 2008 Q4 8 $6,509,331 2009 Q1 9 $6,271,951...

...;GOOG?", "GOOG?", "GOOG?", "GOOG?", "GOOG?", "GOOG?", "GOOG?", "GOOG?", "GOOG?", "GOOG?", "GOOG?", "GOOG?", "GOOG?", "GOOG?"), PERIOD = c("Q4?2011", "Q3?2011", "Q2?2011", "Q1?2011", "Q4?2010", "Q3?2010", "Q2?2010", "Q1?2010", "Q4?2009", "Q3?2009", "Q2?2009", "Q1?2009", "Q4?2008", "Q3?2008", "Q2?2008", "Q1?2008&...

sample report data that i want to forecast quarter quarter_index Revenue 2007 Q1 1 $3,856,799 2007 Q2 2 $4,243,328 2007 Q3 3 $4,930,369 2007 Q4 4 $5,443,579 2008 Q1 5 $5,164,830 2008 Q2 6 $5,104,413 2008 Q3 7 $5,713,240 2008 Q4 8 $6,509,331 2009 Q1 9 $6,271,951...

Example: Will ts objects be obsolete or modified? > a [,1] 1983 Q1 2.747365190 1983 Q2 2.791594762 1983 Q3 -0.009953715 1983 Q4 -0.015059485 1984 Q1 -1.190061246 1984 Q2 -0.553031799 1984 Q3 0.686874720 1984 Q4 0.953911035> lag(a,4) [,1] 1983 Q1 NA 1983 Q2 NA 1983 Q3 NA 1983 Q4 NA 1984 Q1 2.747365190 1984 Q2 2.791594762 1984 Q3 -0.009953715 1...

...not doing what I assumed. > x <- zoo(11:21) > z <- zoo(1:10, yearqtr(seq(1959.25, 1961.5, by = 0.25)), frequency = 4) > x 1 2 3 4 5 6 7 8 9 10 11 11 12 13 14 15 16 17 18 19 20 21 > lag(x) 1 2 3 4 5 6 7 8 9 10 12 13 14 15 16 17 18 19 20 21 > z 1959 Q2 1959 Q3 1959 Q4 1960 Q1 1960 Q2 1960 Q3 1960 Q4 1961 Q1 1961 Q2 1961 Q3 1 2 3 4 5 6 7 8 9 10 > lag(z) 1959 Q1 1959 Q2 1959 Q3 1959 Q4 1960 Q1 1960 Q2 1960 Q3 1960 Q4 1961 Q1 1961 Q2 1 2 3 4 5 6 7...

Hi R-people, I have a question about lattice in general, and histogram specfically. How do you control the ordering of factors that controls the placement of the conditional panels. I have a dataset with factors that go 'Q1','Q2',"Q3','Q5' and of course I want the plot to place Question Q1 at the top and Question Q5 at the bottom of the graphical output. histogram() does the opposite as 5 is larger than 1. Similarly my 'AlertFormat' factor is a textual category, and I need the data to read from left to right...

...e runtime Dear all, I want to calculate for each row the amount of the month ago. I use a matrix with 2100 rows and 22 colums (which is still a very small matrix. nrows of other matrixes can easily be more then 100000) Table before Year month quarter yearmonth Service ... Amount 2009 9 Q3 092009 A ... 120 2009 9 Q3 092009 B ... 80 2009 8 Q3 082009 A ... 40 2009 7 Q3 072009 A ... 50 The result I want...

hi, for example, I have an string "q1 q2 q3". how can I encode it in rails to produce the result like "q1%20q2%20q3". Thanks! Best Regards, Zhenjian -------------- next part -------------- An HTML attachment was scrubbed... URL: http://wrath.rubyonrails.org/pipermail/rails/attachments/20060717/3824f992/attachment.html

I have the initial matrice: > *data.frame(Subject=rep(100:101, each=4), Quarter=rep(paste("Q",1:4, sep=""),2), Boolean = rep(c("Y","N"),4))* Subject Quarter Boolean 1 100 Q1 Y 2 100 Q2 N 3 100 Q3 Y 4 100 Q4 N 5 101 Q1 Y 6 101 Q2 N 7 101 Q3 Y 8 101 Q4 N ... > And I would like to group the Subject by Quarter using as a result in the table the value of the third variable (Boolean). The final result would give: S...

Hello, I have a table (1) of the form q1 q3 q4 q8 q9 A 5 2 0 1 3 B 2 0 2 4 4 I have another table (2): q1 q2 q3 q4 q5 q6 q7 q8 q9 C 10 7 4 2 6 9 3 1 2 I would like to divide the numbers in table (1) by the number of the appropriate column in table (2): q1 q3 q4 q8 q9 A 5/10 2/4...

Dear list, I am using a external program that outputs Q1, Q3, median, upper and lower whisker values for various datasets simultaneously in a tab delimited format. After importing this text file into R, I would like to plot a boxplot using these given values and not the original series of data points, i.e. not using something like boxplot(mydata). Is there...

Hi All, There are a variety of functions that can be applied to a variable (column) in a data frame: mean, min, max, sd, range, IQR, etc. I am aware of only two that work on the rows, using q1-q3 as example variables: rowMeans(cbind(q1,q2,q3),na.rm=T) #mean of multiple variables rowSums (cbind(q1,q2,q3),na.rm=T) #sum of multiple variables Can the standard column functions (listed in the first sentence) be applied to rows, with the use of correct indexes to reference the columns of...

Hi, I have a question about how to obtain the union of several data frame rows. I'm trying to create a common key for several tests composed of different items. Here is a small scale version of the problem. These are keys for 4 different tests, not all mutually exclusive: id q1 q2 q3 q4 q5 q6 1 A C 2 B D 3 A D B 4 C D B D I would like to create a single key all test versions, the "union" of the above: id q1 q2 q3 q4 q5 q6 key A C D B B D Here is what I have (unsuccessfully) tried so far: > key <- +...

I have the initial matrice: > *data.frame(Subject=rep(100:101, each=4), Quarter=rep(paste("Q",1:4, sep=""),2), Boolean = rep(c("Y","N"),4))* Subject Quarter Boolean 1 100 Q1 Y 2 100 Q2 N 3 100 Q3 Y 4 100 Q4 N 5 101 Q1 Y 6 101 Q2 N 7 101 Q3 Y 8 101 Q4 N ... > And I would like to group the Subject by Quarter using as a result in the table the value of the third variable (Boolean). The final result would give: S...

...? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?Var1? Var2 date ? ? ? ? ? ? ? ? group? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? 2007-01-01? ? ? ? ? q1 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?1? ? 9 ? ? ? ? ? ? ? ? ? ? ?q2 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?2? ? 8 ? ? ? ? ? ? ? ? ? ? ?q3 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?3? ? 7 2007-01-02? ? ? ? ? q1 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?6? ? 6 ? ? ? ? ? ? ? ? ? ? ?q2 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?7? ? 5 ? ? ? ? ? ? ? ? ? ? ?q3 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?8? ? 4 I understand that i...

...refers to a question. > > I would like to join the 21 files into one, to construct > tables for each question by CODE. > > I tried the command (8 files only): > > require(foreign) > q1 = read.epiinfo('Dados/Q1.rec') > q2 = read.epiinfo('Dados/Q2.rec') > q3 = read.epiinfo('Dados/Q3.rec') > q4 = read.epiinfo('Dados/Q4.rec') > q5 = read.epiinfo('Dados/Q5.rec') > q6 = read.epiinfo('Dados/Q6.rec') > q7 = read.epiinfo('Dados/Q7.rec') > q8 = read.epiinfo('Dados/Q8.rec') > > juntos = merge(...

...range, that I chose "english" as installlanguage, but the program is in german (my OS is in german). Pls help, because otherwise i cannot solve any problems with R. Using Win7 and R version 2.15.0 (2012-03-30). Retep -- View this message in context: http://r.789695.n4.nabble.com/Wrong-Q3-Mean-tp4630223.html Sent from the R help mailing list archive at Nabble.com.

...U: $(umask), id: $(/bin/id); $@" dovecot-lda -f "$SENDER" -a "$RECIPIENT" -onamespace/inbox/location=maildir:~/Maildir:LAYOUT=fs:FULLDIRNAME=__MAILBOX__ ---------- If a mailbox is created with dovecot-lda (sieve), permissions look like that: $ ls -ld Maildir Maildir/2018-q3 Maildir/2018-q3/__MAILBOX__ drwxrws---+ 49 leo leo 4096 Jul 1 09:53 Maildir drwxrwx---+ 3 leo leo 24 Jul 1 09:40 Maildir/2018-q3 drwxrwx---+ 2 leo staff 6 Jul 1 09:40 Maildir/2018-q3/__MAILBOX__ -> The setguid bit of Maildir is not honored and dovecot complains: Jul 1 09:40:42 st...

Hi R users, I have following data frame df<-data.frame(q1=c(0,0,33.33,"check"),q2=c(0,33.33,"check",9.156), q3=c("check","check",25,100),q4=c(7.123,35,100,"check")) and i would like to replace every element that is less then 10 with . (dot) in order to obtain this: q1 q2 q3 q4 1 . . check . 2 . 33.33 check 35 3 33.33 check 25 100 4 check...