search for: q1_6

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2013 Feb 21
3
Having trouble converting a dataframe of character vectors to factors
...mportant"), Q1_5 = c("very important", "not important", "important", "very important", "not important", "important", "somewhat important", "important", "somewhat important", "not important"), Q1_6 = c("very important", "not important", "important", "very important", "somewhat important", "very important", "very important", "very important", "important", "important"), Q1_7 = c("very...