search for: pxy

...e left one is a bird-view plot of the whole data, the right half keep changing, i.e., different plots will be shown up on request, so that when I select/click on some where in the left plot, the right plot will be the corresponding plot. What I did is: par(mfrow=c(1,2)) plot(x, y) while(1) { ... pxy <- locator(1, type="p") #select data point (dx,dy) based on pxy for a new plot .. plot(dx,dy) } I ended up with the left plot is overwritten by plot(dx,dy). Is there anyway to keep the left side intact while changing plots on the right side? Thanks a lot! Baoqiang

Hi! I want to use the package "SPLANCE" to do Ripley's K analysis I have a basic question about the package. I try to find how to do it, but I cannot. I hope you can help me. I donot know how to change my data form to "point data set". my data form is: > qumo[1:5,] code species dbh x y tag status branch 223 10312 QUMO 54.5 7.83 44.80 10306 alive

...(p.vec[3]+p.vec[4]*x); return(u/(1+u)); } #growth function gxy<-function(x,y) { sigmax2<-p.vec[7]; sigmax<-sqrt(sigmax2); mux<-p.vec[5]+p.vec[6]*x; fac1<-sqrt(2*pi)*sigmax; fac2<-((y-mux)^2)/(2*sigmax2); return(exp(-fac2)/fac1); } #survival-growth function pxy<-function(x,y) { return(sx(x)*(1-fx(x))*gxy(x,y)) } #fecundity function fxy<-function(x,y) { nkids<-p.est*exp(p.vec[8]+p.vec[9]*x); kidsize.mean<- p.vec[10]; kidsize.var<- p.vec[11]; fac1<-sqrt(2*pi)*sqrt(kidsize.var); fac2<-((y-kidsize.mean)^2)/(2*kidsize.var); f<-...

...e as username PAssword 1001 1002 Domain/Realm 192.168.0.120 SIP Proxy 192.168.0.120 Here is call flow on this test. (c)2003 Xten Networks Inc. All rights reserved. Private build: 1008 SIP: 192.168.0.125:5061 RTP: 192.168.0.125:8000 NAT: 210.253.186.126 PXY#0: 192.168.0.120:5060 RECEIVE << 192.168.0.120:5060 NOTIFY sip:1002@192.168.0.125:5061 SIP/2.0 Via: SIP/2.0/UDP 192.168.0.120:5060;branch=z9hG4bK375605f3 From: "asterisk" <sip:asterisk@192.168.0.120>;tag=as633f7afa To: <sip:1002@192.168.0.125:5061> Contact: <sip:aste...

...tion of Tx(t) we can determine the *mean* counts of these classes at t+1 such that: x mean (t+1) = Tx(t) = [A mean (t+1),B mean (t+1),C mean (t+1)] What I want to know is what is a) what is the *distribution* of A(t+1),B(t+1) and C(t+1), and what is the variance around these mean values? Since pXY are stochastic probabilities, it seems that the distribution and variance should be calculable. Thanks! --j -- Jonathan A. Greenberg, PhD Postdoctoral Scholar Center for Spatial Technologies and Remote Sensing (CSTARS) University of California, Davis One Shields Avenue The Barn, Room 250N Dav...

Hi, I'm trying to calculate p-value to findout definitely expressed genes compare A to B situation. I got this data(this is a part of data) from whole organism , and each number means each expression values (that means, we could think 'a' gene is 13 in A situation, and it turns 30 in B situation) To findout probability, I'm going to use Audic - Claverie Method. ( The significance

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