search for: puzzlingly

(oops, accidentally sent this to the rspec-devel list, sorry about that) Could someone help me spec out these Rails controller methods? I don''t know where to get started, especially with the transaction stuff. Or, if anyone else could suggest ways I could improve the code, that would be great as well. Puzzle has_one Media. Both are AR model objects. class PuzzlesController <

Hi all, I made sure that it's "env$sRes1$nPositionsOptimizedM" that's correct... not the "env$sRes1$nPositionsOptimized"... But it seems both point to the same memory area... This is very dangerous because I have used naming conventions such as: MyLongVariableNameForA MyLongVariableNameForB MyLongVariableNameForC ... ... Then if internally they are actually the

Dear guys, I've put the puzzle solver running on LLVM 2.1. Well, at least partially, for it is failing three of SPEC2000 benchmarks. I will try to debug it now. The results are not as good as before. I mean, the puzzle solver is still the same, but the default allocator is producing very good code now. Even though, the puzzle solver produces faster code for half the benchmarks. It

R allows you to dynamically extend a vector by assigning past the end. So if a has length 10, then assigning to a[11] creates also a[11] with value a2[11] NA. So a is now length 11, while a2 is still length 10. So the occurrence of a[11] has a different meaning on the assigned-to side than on the assigned-from side. E.g. >a <- rep(1,10) >b <- 11 >a2 <- a >a[b] <- a2[b]

Hi, I have been working on a new puppet code formatter for Geppetto for some time, and it is now starting to work quite well. The plan is to release it in Geppetto 3.0. If you want to, you can help by sending "formatting puzzles" - i.e. "given input x, produce formatted result y". I am esp. looking for code where it is impossible to follow "the style guide" -

Dear R users, can someone help with these short puzzles? 1) Is there a function like outer() that evaluates a three-argument function on a threedimensional grid - or else how to define such a function, say, outer.3()? E.g., calculate (x/y)^z on (x,y,z) element of {1,2,3}x{3,4}x{4,5} and return the results in a 3-dimensional array. I would naively use outer() on two of the arguments within a

I hav the following code: <div id="puzzle"> <div id="divImage" style="float:left; cursor: move;>test 1</ div> <div id="divImage" style="float:left; cursor: move;>test 2</ div> <div id="divImage" style="float:left; cursor: move;>test 3</ div> <div

On 06/11/2015 7:36 AM, Therneau, Terry M., Ph.D. wrote: > I am currently puzzled by a seach path behavior. I have a library of a dozen routines > getlabs(), getssn(), getecg(), ... that interface to local repositories and pull back > patient information. All have a the first 6 arguments in common, and immediately call a > second routine to do initial processing of these 6. The

I'm puzzled by such statements as diff /var/clamav/daily.cvd /var/clamav/daily.cvd.rpmnew Binary files /var/clamav/daily.cvd and /var/clamav/daily.cvd.rpmnew differ I thought the point of rpmnew files was so that we could check what has been changed? Anne -- New to KDE4? - get help from http://userbase.kde.org Just found a cool new feature? Add it to UserBase -------------- next part

Hi all I am puzzled about the rspec tests that are generated by Rails3 scaffolding. I am however not sure if this is the correct place to discuss this issue. It might be that a rails ML/chat is better suited for that kind of discussion. It just depends on who is responsible for that code. Somehow I am too stupid to find that out, so please bare with me if I produced only noise here. Cheers

I have the following code: condition_clause = "%#{@phrase}%" logger.info "condition is #{condition_clause}" unless @phrase.nil? condition = Caboose::EZ::Condition.new :affiliates do affiliate_name =~ "%#{@phrase}%" # <<< here''s the problem end options[:conditions] = condition.to_sql logger.info "ajax

I'm trying to get code along the following lines to work: temp.name <- paste(TimePt,'df',sep='.') # invent a relevant name/symbol as a character string. assign(temp.name,IGF.df[IGF.df$TPt==TimePt,]) # this works. The relevant variable is now a data frame lm(b ~ Strain+BWt+PWt+PanPix, data=temp.name)) # this gives an error, namely Error in eval(predvars, data, env) : invalid

I am currently puzzled by a seach path behavior. I have a library of a dozen routines getlabs(), getssn(), getecg(), ... that interface to local repositories and pull back patient information. All have a the first 6 arguments in common, and immediately call a second routine to do initial processing of these 6. The functions "joe" and "fred" below capture the relevant

Hi All! I am puzzled. I am using openssh 5.3p1 on RHEL/CentOS but am seeing the same behaviour for osx and debian: ssh -R xxx:yyy:yyy:yyy remotehost Will effectively drop the first (xxx) argument and result in ssh -R 127.0.0.1:yyy:yyy:yyy remotehost ssh -R yyy:yyy:yyy remotehost I had a look at the source code where apparently all 4 values are ready and handed down to the appropriate

I've written a function, myFunc, that works fine with myFunc(data, ...), but when I use apply() to run it with an array of data apply(myArray, 1, myFunc, ...) I get a strange error: Error in match.fun(FUN) : '1' is not a function, character or symbol which really puzzles me because '1' is meant to be the margin of the array I want to apply over, but how come does apply()

Hello everyone! I''m trying to create an after filter for all my actions in all controllers. I put it in application controller (application.rb). class ApplicationController < ActionController::Base after_filter :tidyit def tidyit xxxx # syntax error - intentionally end end I have a Example (example_controller.rb) controller with index action. class

Duncan, That's helpful. Two follow-up questions: 1. Where would I have found this information? I had looked at eval and model.frame. 2. What stops the following code from falling down the same rabbit hole? Shouldn't it find base::cos first? library(survival) cos <- lung coxph(Surv(time, status) ~ age, data=cos) Terry T. On 11/06/2015 07:51 AM, Duncan Murdoch

Any doubts about R's big-league status should be put to rest, now that we have a Sudoku Puzzle Solver. Take that, SAS! See package "sudoku" on CRAN. The package could really use a puzzle generator -- contributors are welcome! -- David Brahm (brahm at alum.mit.edu) [[alternative HTML version deleted]] _______________________________________________ R-packages mailing list

I'm in a situation where I say: > predict(m.rpart, newdata=D[N1+t,]) 0 1 173 0.8 0.2 which I interpret as meaning: an 80% chance of "0" and a 20% chance of "1". Okay. This is consistent with: > predict(m.rpart, newdata=D[N1+t,], type="class") [1] 0 Levels: 0 1 But I'm puzzled at the following. If I say: > predict(m.rpart,

Any doubts about R's big-league status should be put to rest, now that we have a Sudoku Puzzle Solver. Take that, SAS! See package "sudoku" on CRAN. The package could really use a puzzle generator -- contributors are welcome! -- David Brahm (brahm at alum.mit.edu) [[alternative HTML version deleted]] _______________________________________________ R-packages mailing list