Displaying 1 result from an estimated 1 matches for "psrnr".
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psnr
2007 Mar 24
2
Two Problems while trying to aggregate a dataframe
...2 Mabba 5.23 5.21
4 3 Pisa 4.23 9.12
5 4 Pulla 2.23 7.32
6 5 Raba 2.77 8.32
7 6 Saba 3.83 6.99
8 6 Saba 2.76 4.45
9 6 Saba 6.32 5.34
10 7 Mulla 2.88 3.81
> aggregate(list(Betrag1=atest$Betrag1), by=list(PsrNr=atest$PrsNr,
Namen=atest$Namen), sum)
PsrNr Namen Betrag1
1 1 Holla 1.99
2 2 Mabba 7.57
3 7 Mulla 2.88
4 3 Pisa 4.23
5 4 Pulla 2.23
6 5 Raba 2.77
7 6 Saba 12.91
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The result is nearly that I want.
First problem:
How do I get all columns...