Displaying 9 results from an estimated 9 matches for "psill".
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phill
2015 Aug 04
2
Duda interpolación (package ' gstat ')
..."solve.c", line 88: singular matrix in function Usolve()
"lufactor.c", line 208: singular matrix in function m_inverse()
Error in predict.gstat(g, newdata = newdata, block = block, nsim = nsim, :
m_inverse
In addition: Warning message:
In fit.variogram(vg.aux, model = vgm(psill = 0.1, model = "Gau", :
Warning: singular model in variogram fit
Mi función del variograma es :
v.fit <- fit.variogram(vg.aux, model=vgm(psill=0.15, model='Gau', range=5000,
nugget=0.05))
¿Alguien me podría ayudar?
Gracias d...
2015 Aug 06
2
Duda interpolación (package ' gstat ')
...Usolve()
> >
> > "lufactor.c", line 208: singular matrix in function m_inverse()
> > Error in predict.gstat(g, newdata = newdata, block = block, nsim = nsim, :
> > m_inverse
> > In addition: Warning message:
> > In fit.variogram(vg.aux, model = vgm(psill = 0.1, model = "Gau", :
> > Warning: singular model in variogram fit
> >
> >
> > Mi funci?n del variograma es :
> > v.fit <- fit.variogram(vg.aux, model=vgm(psill=0.15, model='Gau', range=5000,
> >...
2005 Nov 08
2
Variogram
...tat) ? Please kindly give me some hints about the results.
I used variogram() to build a semivariogram plot as:
tr.var=variogram(Incr~1,loc=~X+Y,data=TRI2TU,width=5)
then fir the variogram to get the parameters as:
v.fit = fit.variogram(tr.var,vgm(0.5,"Exp",300,1))
v.fit
model psill range
1 Nug 1.484879 0.00000
2 Exp 3.476700 29.70914
This is the output of v.fit. Can anybody help me write the exponential formula for this variogram? I have the problem in understanding the result.
Thanks!
Leaf
2008 Aug 05
4
LIDAR Problem in R (THANKS for HELP)
...adius 45? minus radius)
8. Fig 8- semi-variogram with anisotropy (0?, 45?, 90?, 135?). Best
shape is from 135?
9. Fig 9- semi-variogram fit with Gaussian Model. R code is:
> v = variogram(Z~X+Y, subground, cutoff=1800, width=200, alpha=c(135))
> v.fit = fit.variogram(v, vgm(psill = 1, model="Gau", range=1800, nugget=
0, anis=c(135, 0.5)))
R code:
testground2 <-
read.table(file="c:/work_LIDAR_USA/R_kriging_new_set/ground_26841492694149_x
yz.txt", header=T)
class (testground2)
coordinates (testground2)=~X+Y # this makes testground a
SpatialPoi...
2008 Oct 16
1
Suppressing error messages in a for loop
...quot;, 100))"
and fitted it using
"dexp.fit <- fit.variogram(temp2, dexp, fit.method=6, debug.level=0)"
Occasionally I get the following error message and the model doesn't fit
"Error in if (direct[direct$id == id, "is.direct"] && any(model$psill <
:
missing value where TRUE/FALSE needed"
I don't mind that the model doesn't converge, however the error message
stops the for loop I'm running at the time (and so stops my code!). Is
there any way that I can suppress the error message?
Sorry if this is a really simp...
2017 Sep 24
1
R version 3.3.2, Windows 10: gstat package: Error in fitting a variogram model using 'fit.variogram' function
...r Members,
I am trying to fit a variogram model using fit.variogram function from the gstat package. The figure showing my experimental variogram can be seen here: https://i.stack.imgur.com/UZXw4.png
My code line for this operation is:
> c2.vgm.fit<-fit.variogram(c2.vgm.exp,vgm(nugget=0, psill=400,model="Exp",range =40000),fit.method = 7)
The system throws following error message:
Error in switch(model, exponential = fit.exponential(v.object, c0 = nugget, :
EXPR must be a length 1 vector
Any help to know the cause of the error and avoiding it would be highly appreciated....
2013 Mar 19
1
Cokriging
...28992")
g <- gstat(id = "Cu", formula =Cu~1,data = data_c)
g <- gstat(g, id = "S", formula = S~1,data =data_c)
g <- gstat(g, id = c("Cu", "S"), model = vgm(cov(data_c$Cu,data_c$S) , "Sph", 200, 0))
g<fit.lmc(variogram(g),g,model=vgm(psill=cov(data_c$Cu,data_c$S),model="Sph",range=200,nugget=0))
k.c <- predict.gstat(g, grid,block = c(30,30,15))
Thanks and Regards,
Nishani Musafer
2008 Aug 20
1
pdf filenames in while loop
...th a as the control
a=1
while(a <= 60)
{
d <- read.csv(paste(f.mat[a]), header=TRUE, sep=",")
coordinates(d) = ~dbl_1+dbl_2
variogram = autofitVariogram(dbl_5~1,d, model = c("Sph"), fix.values=c(NA,NA,NA), verbose = FALSE)
print(variogram)
print(variogram$var_model$psill[1])
print(variogram$var_model$range[2])
p <- plot(variogram, main="Semi-variogram (Spherical Model)", sub=paste("Range: ",variogram$var_model$range[2]))
print(p)
pdf(file="as.character(paste(f.mat[a])).pdf")
plot(p, main="Semi-variogram (Spherical Model)&...
2003 Aug 17
1
(no subject)
...Inf
.. ..$ dummy : logi FALSE
.. ..$ vfn : int 1
.. ..$ weights : NULL
$ model:List of 1
..$ rv:Classes variogram.model and `data.frame': 1 obs. of 9
variables:
.. ..$ model: Factor w/ 16 levels "Nug","Exp","Sph",..: 5
.. ..$ psill: num 1652
.. ..$ range: num 126
.. ..$ kappa: num 1.75
.. ..$ ang1 : num 0
.. ..$ ang2 : num 0
.. ..$ ang3 : num 0
.. ..$ anis1: num 1
.. ..$ anis2: num 1
.. ..- attr(*, "singular")= logi FALSE
$ set :List of 1
..$ average: num 1
- attr(*, "class")= chr [1:2]...