search for: promberg

...ing else",y) } Surely, there must be a less kludgy way? I tried looking at the different apply()s but am not getting anywhere, partly because I lack the mental flexibility to combine the fact that I am applying gsub() to y but now want to apply that to x ... erm. :/ Marianne -- Marianne Promberger PhD, King's College London http://promberger.info R version 2.10.1 (2009-12-14) Ubuntu 9.10

...o AC and/or AD respectively. I can get the first step by making an extra variable: dat1$condnew <- paste(dat1$cond1,dat1$cond2,sep="") although I am sure there are more elegant ways, and especially, I am stumped how to fill in the cells of the table. Thanks, Marianne -- Marianne Promberger PhD, King's College London http://promberger.info R version 2.12.0 (2010-10-15) Ubuntu 9.04

...<- function(x, ...) { ns <- nrow(x) barplot(x , ... ) } myfun(m1, main=paste("n = ",ns) ) ns is not found So, basically, how do I assign an object inside a function that I can then access in the dots when executing the function? Many thanks Marianne -- Marianne Promberger PhD, King's College London http://promberger.info R version 2.12.0 (2010-10-15) Ubuntu 9.04

...o \"one,two,three\" > file.csv") # create mockup file read.csv(file=system("sed -e 's/,/;/' file.csv")) # this does not work I think the answer must be in ?connections, maybe pipe() but I have fiddled with these and cannot figure it out. Marianne -- Marianne Promberger PhD, King's College London http://promberger.info R version 2.10.0 (2009-10-26) Ubuntu 9.04

..."one" [[2]] [1] "four" "five" I was hoping sapply(x,"[",y) would work, but it doesn't. I guess I need to sapply twice, like sapply(x, function() { sapply(y ... but I can't figure it out. Many thanks for any pointers Marianne -- Marianne Promberger PhD, King's College London http://promberger.info R version 2.11.1 (2010-05-31) Ubuntu 9.04

...aditional graphics using: barplot(xtabs(amount~what+month, data=t1),beside=T) But I'd like to be able to do this in lattice. I tried: barchart(amount~what|month,t1) But that doesn't sum the data for t1$amount for each month first. How could I do that? Thanks, Marianne -- Marianne Promberger Graduate student in Psychology http://www.psych.upenn.edu/~mpromber

...enquired with the agrocampus-ouest.fr website about the logo but was pointed to r-project.org and the R development core team. I thought in that case it might be best to ask here to have the answer publicly available -- sorry if I overlooked the information online somewhere. Marianne -- Marianne Promberger PhD, King's College London http://promberger.info R version 2.9.2 (2009-08-24) Ubuntu 9.04

...2),1)) plot(1:10,main="left plot") plot(10:1,main="right plot") lines(c(3:7,7:3),col="red") but of course now lines() gets added to the "right plot". I Is there any way to make the lines() go to the fist plot ("left plot")? Marianne -- Marianne Promberger PhD, King's College London http://promberger.info R version 2.9.2 (2009-08-24) Ubuntu 9.04

...ect,main=X) } where X is the expression I'm looking for, and the plot should have the title "s1" if I've called myplot(s1), "s2" if myplot(s2), etc. I'm sure I'll be really embarrassed that this is so trivial but I cannot figure it out. Marianne -- Marianne Promberger PhD King's College London

...ter.adapt),Second.adapt=c(Second.adapt)) library(ggplot2) qplot(jitter(Goodall),jitter(Better.adapt),colour=Second.adapt,data=d1) # follwoing doesn't work: qplot(jitter(Goodall),jitter(Better.adapt),colour=I(alpha(Second.adapt,1/5)),data=d1) Thanks for any pointers, Marianne -- Marianne Promberger PhD http://www.psych.upenn.edu/~mpromber PGP/GnuPG public key ID 80AD9916

Hello, I am doing a if else statement in R. But it always comes out error such as 'unexpected symbol' There are two variables. ini and b. when ini=1, a=3; when ini>1 and b>2, a=3; all other situations, a=6. I don't know where it is wrong. Here is my code ini=3 b=4 if (ini==1) { a=3 } else if (ini>1 and b>2 ) { a=3 } else {a=6} Thanks a

Dear R users: Maybe it is a silly question, but I'm don't understand what am I doing wrong. In a new karmik koala ubuntu installation I compile the last patched 2.10.1 version of R. Every thing was right (I install all the dev libraries I need). First I type: ./configure --enable-R-shlib And I obtain: R is now configured for i686-pc-linux-gnu Source directory: .

I have been looking at a draft of Doug Bate's book on mixed effects models (http://lme4.r-forge.r-project.org/book), and in chapter one (section "1.4.2 Matrices and Vectors in the Fitted Model Object", to be exact) he refers to the function env() for checking the environment of a fitted lmer object. This function does not appear under help, and I have not been able to find

Hi I got an barplot, and I would like to have the exact number of the bars just above the bars anyone know how to do this? Sorry for bad English, and I do hope that you understand what im after. //Joel -- View this message in context: http://r.789695.n4.nabble.com/Number-above-the-bar-tp3037438p3037438.html Sent from the R help mailing list archive at Nabble.com.

Hi everyone I have been trying to build R in ubuntu 8.04 from its source code but am getting the following error. configure: error: --with-x=yes (default) and X11 headers/libs are not available Please help me and consider me a newbie in linux thanks in advance [[alternative HTML version deleted]]

Hi everyone I have been trying to build R in ubuntu 8.04 from its source code but am getting the following error. configure: error: --with-x=yes (default) and X11 headers/libs are not available Please help me and consider me a newbie in linux thanks in advance [[alternative HTML version deleted]]

...on integrating a function that is a vector. I have a function - vector which each element is different. And, naturally, function integrate() does not work I checked the article of U. Ligges and J. Fox (2008) about code optimization "How Can I Avoid This Loop or Make It Faster?" on http://promberger.info/files/rnews-vectorvsloops2008.pdf. Their advice did not help me, because they advised a solution, when function was the same, but limits of the integral were vectors. I have got everything other way around. I could not get any result. I would be very grateful for an advice on this matter. T...

Hi to all, test <- data.frame("X"=c(1:4),"Y"=c(5:8),"Z"=c(8:11)) test <- test[,-2] Is there a way to specify the col name "Y" to delete instead the number? Kind regards Knut

Dear All, I have a data frame with 5 column and 201 row data. I want to add one more column between column 1 and 2 with value of 1. So the new column has to be the second column filled with 1. Any help will be appreciated. Thanks for your time. Thanks & Rg Mohan L

Dear All, I have two data like this : $cat main.csv name,id,memory,storage mohan,1,100.20,1.10 ram,1,200,100 kumar,1,400,50 xxx,1,100,40 aaa,1,800,45 mount,1,200,80 > main <- read.csv(file='main.csv',sep=',' , header=TRUE) > main name id memory storage 1 mohan 1 100.2 10 2 ram 1 200.0 100 3 kumar 1 400.0 50 4 xxx 1