Displaying 1 result from an estimated 1 matches for "progression_months_landmark_14".
2012 Apr 13
3
Kaplan Meier analysis: 95% CI wider in R than in SAS
...d my estimate for the median is substantially larger in R than in SAS. For example, in SAS I have a median of 3.29 with a 95% CI of [1.15, 5.29]. In R, I get a median of 3.29 with a 95% CI of [1.35,?13.35].
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Can anyone tell me why I get this difference?
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My R code looks like:
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survfrm <- Surv(progression_months_landmark_14,progression==1) ~ pr_rg_landmark_14
survobj <- survfit(survfrm, data=Survival)
survlrk <- survdiff(survfrm, data=Survival)
summary(survobj)
print(survobj)
print(survlrk)
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My SAS code looks like:
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proc lifetest data=survival;
strata pr_rg_landmark_14;
time progression_months_landmark_14 * p...