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probtype
2002 Sep 14
0
p.s. regarding stripchart missing-data report (PR#2019)
...ie,
#pc.had,denial,qs,sf12,stai), file="hrp2.csv",sep=",", row.names=F)
qs <- array(qs,c(ns,24,4)) # subjects, items, cancers
cancer <- as.vector(qs[,1,])
cancer[cancer>4] <- 4 # correct some js error
cancer <- as.factor(cancer) # like "cat" in Systat
probtype <- as.factor(as.vector(floor(qs[,2,]/4)))
subj <- as.factor(rep(1:ns,4))
# ---- this makes one array where the third argument is the condition
# conditions are 1-4=verbal, 5-8=percent, 9-12 fraction
# 1-4 are the four cancers, also 5-8 and 9-12
qsall <- array(NA,c(ns,24,12))
for (i in 1...