Displaying 13 results from an estimated 13 matches for "probabilty".

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probability

2005 Jan 14

2

probabilty calculation in SVM

Hi All,
In package e1071 for SVM based classification, one can get a probability
measure for each prediction. I like to know what is method that is used for
calculating this probability. Is it calculated using logistic link function?
Thanks for your help.
Regards,
Raj

2010 Dec 10

2

survival package - calculating probability to survive a given time

Dear R users,
i try to calculate the probabilty to survive a given time by using the
estimated survival curve by kaplan meier.
What is the right way to do that? as far as is see i cannot use the
predict-methods from the survival package?
library(survival)
set.seed(1)
time <- cumsum(rexp(1000)/10)
status <- rbinom(1000, 1, 0.5)
##...

2007 Jan 05

1

Efficient multinom probs

Dear R-helpers,
I need to compute probabilties of multinomial observations, eg by doing the
following:
y=sample(1:3,15,1)
prob=matrix(runif(45),15)
prob=prob/rowSums(prob)
diag(prob[,y])
However, my question is whether this is the most efficient way to do this.
In the call prob[,y] a whole matrix is computed which seems a bit of a
waste.
Is there maybe a vectorized version of dmultinom

2009 Oct 29

1

correlated binary data and overall probability

..., each=5)),
task=as.factor(rep(c(1:5),10)))
[this format might be more appropriate:]
corr2<-data.frame(ID=as.factor(rep(c(1:10),5)),
tablet=as.factor(rep(c(1:5),each=10)))
Now, I want to add one column 'outcome' for the binary response:
* within each 'task', the probabilty of success (1) is fixed, (say rbinom(x,1,0.7))
* within each 'ID', the outcomes are correlated (say 0.8)
How can I generate this column 'outcome' with the given proporties?
Many thanks for hints or even code!
Regards,
Christian
--
http://portal.gmx.net/de/go/...

2017 Aug 24

1

rmutil parameters for Pareto distribution

...ttps://en.wikipedia.org/wiki/Pareto_distribution, it is clear what the
parameters are for the pareto distribution: *xmin *the scale parameter and
*a* the shape parameter.
I am using rmutil to generate random deviates from a pareto distribution.
It says in the documentation that the probabilty density of the pareto
distribution
The Pareto distribution has density
f(y) = s (1 + y/(m (s-1)))^(-s-1)/(m (s-1))
where m is the mean parameter of the distribution and s is the dispersion
Through my experimentation of using rpareto function from the library using
m as the scale paramet...

2011 Aug 31

6

Weights using Survreg

Dear R users,
I have been trying to understand what the Weights arguments is doing in the
estimation of the parameters when using the Surreg function.
I looked through the function's code but I am not sure if I got it or not.
For example, if I inclue the Surv function in it:
survreg(Surv(vector, status)~1,weights=vector2,dist="Weibull")
will it try to maximize the likelihood with

2010 Mar 02

4

ZFS Large scale deployment model

We have a virtualized environment of T-Series where each host has either zones or LDoms.
All of the virtual systems will have their own dedicated storage on ZFS (and some may also get raw LUNs). All the SAN storage is delivered in fixed sized 33GB LUNs.
The question I have to the community is whether it would be better to have a pool per virtual system, or create a large pool and carve out ZFS

2014 Dec 16

3

[LLVMdev] Lowering switch statements with PGO

> On Mon, Dec 15, 2014 at 2:26 PM, Chad Rosier <mcrosier at codeaurora.org>
> wrote:
>>
>> > On Mon, Dec 15, 2014 at 9:57 AM, Chad Rosier <mcrosier at codeaurora.org>
>> > wrote:
>> >> All,
>> >> About two months ago I posted a patch that hoisted the hottest case
>> >> statement from a switch statement during

2005 Mar 16

0

Help regarding persp

...........
[,1] [,2]
[1,] 0 0
[2,] 0 0
[3,] 0 0
[4,] 0 0
[5,] 0 0
[6,] 0 0
[7,] 0 0
[8,] 0 0
...................
i need to label x axis with scale from 10 to 6000 with length of 10
and y axis with 1 and 2
and z from 0 to 1(probabilty)
kindly guide me...(may be i have misunderstood some concepts )...
thanks in advance for the help and patience
---------------------------------
[[alternative HTML version deleted]]

2008 Jun 18

2

[FreeBSD 6.3] Zaptel stops responding

...d this opportunity to upgrade to Asterisk 1.4.20.1_1 and
Zaptel 1.4.6_5.
The hardware is an OpenVox PCI card with a single FXO module. I know,
it's not a $200 Sangoma, but then, we only get a few calls/day.
Has someone seen this before? Any idea what happened, and what to do
to recuce the probabilty that it happens again? For instance, since
it's a low-use host, (I don't mind running a CRON job to stop/start
the driver a couple of times a day to keep things running.
Thanks for any hint.

2014 Dec 23

2

[LLVMdev] Lowering switch statements with PGO

...;
> For example, while building the Huffman tree, propagate various
> information up the tree as you build it. Then you can very easily start at
> the top of the huffman tree and have all this information available to you
> (e.g. "peel off the most probable cases until the relative probabilty has
> some relation to the subtree case density").
>
> On the other hand (more likely), you could keep the cases ordered (i.e.
> not a Huffman tree) and integrate the branch probability info as the extra
> data propagated up the tree (along with other stuff); e.g. the max
> p...

2008 Jan 14

0

FreeBSD Security Advisory FreeBSD-SA-08:01.pty

...s printed to the
users terminal.
If a malicious user has read access to a device node with characters
in the device name that match the name of a pty, then the malicious user
can read the content of the pty from another user. The malicious user
can open a lot of tty''s resulting in a high probabilty of a new user
obtaining the pty name of a "vulnerable" pty.
NOTE WELL: If a user snoops a pty the snooped text will not be shown
to the real user, which in many cases mean the real owner of the pty
will be able to know the attack is taking place.
IV. Workaround
Do not run script(1) as...

2011 Feb 02

2

SVM Prediction and Plot

Hi
I'm trying to predict using a model I fitted with SVM.
I constructed the model (called Svm) using a training set, and now I want to
use a test set (called BankTest) for prediction.
The response variable is in the first column of BankTest.
> SvmPred = predict(Svm, BankTest[,-1], probability=TRUE)
> SvmPredRes = table(Pred = SvmPred, True = BankTest[,1])
I get this error:
Error in